Question Number 95634 by i jagooll last updated on 26/May/20 $$\mathrm{solve}\:\mid{x}+\frac{\mathrm{1}}{{x}}\mid\:>\:\mathrm{2}\: \\ $$ Answered by john santu last updated on 26/May/20 $$\mathrm{solution}:\: \\ $$$$\mathrm{this}\:\mathrm{is}\:\mathrm{equivalent}\:\mathrm{to}\:\mid\frac{{x}^{\mathrm{2}} +\mathrm{1}}{{x}}\mid\:>\:\mathrm{2}…
Question Number 30049 by abdo imad last updated on 15/Feb/18 $${find}\:\sum_{{n}=\mathrm{1}} ^{\infty} \:\frac{{n}\left({n}+\mathrm{1}\right)}{\mathrm{3}^{{n}} }\:. \\ $$ Commented by prof Abdo imad last updated on 16/Feb/18…
Question Number 161114 by cortano last updated on 12/Dec/21 $$\:\:{Let}\:{f}\left({x}\right)=\:\mathrm{sin}\:^{\mathrm{3}} \left(\mathrm{2}{x}\right)\:{for}\:−\frac{\pi}{\mathrm{4}}\leqslant{x}\leqslant\frac{\pi}{\mathrm{4}} \\ $$$$\:{then}\:{Df}^{−\mathrm{1}} \left(\frac{\mathrm{1}}{\mathrm{8}}\right)=\frac{{a}}{{b}\sqrt{{b}}}\:{so}\:\begin{cases}{{a}=?}\\{{b}=?}\end{cases} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 29987 by abdo imad last updated on 14/Feb/18 $${prove}\:{that}\:\:\sum_{{n}=\mathrm{1}_{{n}\neq{p}} } ^{\infty} \:\:\frac{\mathrm{1}}{{n}^{\mathrm{2}} \:−{p}^{\mathrm{2}} }\:\:=\:\:\frac{\mathrm{3}}{\mathrm{4}{p}^{\mathrm{2}} }\:. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 29986 by abdo imad last updated on 14/Feb/18 $${find}\:\sum_{{n}=\mathrm{0}} ^{\infty} \:\:\:\frac{{n}+\mathrm{1}}{\mathrm{4}^{{n}} }\:. \\ $$ Commented by abdo imad last updated on 14/Feb/18 $${let}\:{introduce}\:{for}\:\mid{x}\mid<\mathrm{1}\:\:\:{S}\left({x}\right)=\:\sum_{{n}=\mathrm{0}}…
Question Number 29985 by abdo imad last updated on 14/Feb/18 $${prove}\:{that}\:\:\:\:\sum_{{p}=\mathrm{1}} ^{\infty} \:\:\:\:\:\:\frac{{a}^{{p}} }{\mathrm{1}−{a}^{\mathrm{2}{p}} }\:=\:\sum_{{p}=\mathrm{1}} ^{\infty} \:\:\:\:\frac{{a}^{\mathrm{2}{p}−\mathrm{1}} }{\mathrm{1}−{a}^{\mathrm{2}{p}−\mathrm{1}} }\:. \\ $$ Terms of Service Privacy…
Question Number 29984 by abdo imad last updated on 14/Feb/18 $${prove}\:{that}\:\:\:\sum_{{n}=\mathrm{1}} ^{\infty} \:\:\:\frac{{H}_{{n}} }{{n}!}=={e}\:\sum_{{n}=\mathrm{1}} ^{\infty} \:\:\:\frac{\left(\mathrm{1}\right)^{\boldsymbol{{n}}−\mathrm{1}} }{\boldsymbol{{n}}\:\left(\boldsymbol{{n}}!\right)}\:. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 29982 by abdo imad last updated on 14/Feb/18 $${let}\:{give}\:{f}\left({x}\right)=\sqrt{{x}+\sqrt{\mathrm{1}+{x}^{\mathrm{2}} \:}}\:\:\:\:{developp}\:{f}\:{at}\:{integr}\:{series} \\ $$$${in}\:{point}\:\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 29983 by abdo imad last updated on 14/Feb/18 $${find}\:{radius}\:{andsum}\:{of}\:\:\sum_{{n}=\mathrm{1}} ^{\infty} \:\:\frac{{n}−\mathrm{1}}{{n}!}\:{x}^{{n}} . \\ $$ Commented by abdo imad last updated on 15/Feb/18 $${S}\left({x}\right)=\sum_{{n}=\mathrm{1}}…
Question Number 29981 by abdo imad last updated on 14/Feb/18 $${find}\:{radius}\:{and}\:{sum}\:{of}\:\:\:\sum_{{n}=\mathrm{0}} ^{\infty} \:\:\:\:\frac{{x}^{\mathrm{2}{n}} }{\mathrm{2}{n}+\mathrm{1}} \\ $$$$\left.\mathrm{2}\right)\:{find}\:\:\:\sum_{{n}=\mathrm{0}} ^{\infty} \:\:\:\:\:\frac{\mathrm{1}}{\left(\mathrm{2}{n}+\mathrm{1}\right)\mathrm{9}^{{n}} }\:. \\ $$ Commented by abdo imad…