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Category: Relation and Functions

let-S-n-k-1-n-1-k-k-and-H-n-k-1-n-1-k-calculate-S-n-interms-of-H-n-2-find-lim-n-S-n-

Question Number 63164 by mathmax by abdo last updated on 29/Jun/19 $${let}\:{S}_{{n}} =\sum_{{k}=\mathrm{1}} ^{{n}} \:\:\frac{\left(−\mathrm{1}\right)^{{k}} }{{k}}\:\:\:\:\:\:{and}\:{H}_{{n}} =\sum_{{k}=\mathrm{1}} ^{{n}} \:\frac{\mathrm{1}}{{k}} \\ $$$${calculate}\:{S}_{{n}} \:{interms}\:{of}\:{H}_{{n}} \\ $$$$\left.\mathrm{2}\right){find}\:{lim}_{{n}\rightarrow+\infty} \:{S}_{{n}}…

calculate-S-1-1-2-1-3-4-1-5-6-

Question Number 63101 by mathmax by abdo last updated on 29/Jun/19 $${calculate}\:\:{S}\:=\frac{\mathrm{1}}{\mathrm{1}×\mathrm{2}}\:+\frac{\mathrm{1}}{\mathrm{3}×\mathrm{4}}\:+\frac{\mathrm{1}}{\mathrm{5}×\mathrm{6}}\:+….. \\ $$ Commented by mathmax by abdo last updated on 29/Jun/19 $${let}\:{try}\:{another}\:{way}\:{we}\:{have}\:\frac{{d}}{{dx}}{ln}\left(\mathrm{1}+{x}\right)\:=\frac{\mathrm{1}}{\mathrm{1}+{x}}\:=\sum_{{n}=\mathrm{0}} ^{\infty}…

simplify-A-n-1-1-3-i-n-1-1-3-i-n-

Question Number 128498 by mathmax by abdo last updated on 07/Jan/21 $$\mathrm{simplify}\:\mathrm{A}_{\mathrm{n}} =\frac{\mathrm{1}}{\left(\mathrm{1}+\sqrt{\mathrm{3}}\mathrm{i}\right)^{\mathrm{n}} }+\frac{\mathrm{1}}{\left(\mathrm{1}−\sqrt{\mathrm{3}}\mathrm{i}\right)^{\mathrm{n}} } \\ $$ Answered by TheSupreme last updated on 08/Jan/21 $$\mathrm{1}+{i}\sqrt{\mathrm{3}}=\mathrm{2}{e}^{{i}\frac{\pi}{\mathrm{3}}}…

P-x-tan-1-x-n-0-1-n-x-2n-1-2n-1-P-1000-x-what-is-this-sum-in-terms-of-x-

Question Number 62962 by fyyac c last updated on 27/Jun/19 $${P}\left({x}\right)=\mathrm{tan}^{−\mathrm{1}} \left({x}\right)=\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}} {x}^{\mathrm{2}{n}+\mathrm{1}} }{\mathrm{2}{n}+\mathrm{1}}\: \\ $$$${P}_{\mathrm{1000}} \left({x}\right)=?\:{what}\:{is}\:{this}\:{sum}\:{in}\:{terms}\:{of}\:{x}? \\ $$ Terms of Service Privacy…

calculate-A-1-2-6-4-1-2-6-4-

Question Number 128496 by mathmax by abdo last updated on 07/Jan/21 $$\mathrm{calculate}\:\:\:\mathrm{A}\:=\frac{\mathrm{1}}{\left(\mathrm{2}−\sqrt{\mathrm{6}}\right)^{\mathrm{4}} }+\frac{\mathrm{1}}{\left(\mathrm{2}+\sqrt{\mathrm{6}}\right)^{\mathrm{4}} } \\ $$ Commented by liberty last updated on 08/Jan/21 $$\frac{\left(\mathrm{2}−\sqrt{\mathrm{6}}\right)^{\mathrm{4}} +\left(\mathrm{2}+\sqrt{\mathrm{6}}\right)^{\mathrm{4}}…

If-f-x-x-tan-x-and-f-is-inverse-of-g-then-g-x-is-equal-to-a-1-1-g-x-x-2-b-1-1-g-x-x-2-c-1-2-g-x-x-2-d-1-2-g-x-x-2-

Question Number 128425 by bramlexs22 last updated on 07/Jan/21 $$\:\mathrm{If}\:\mathrm{f}\left(\mathrm{x}\right)\:=\:\mathrm{x}\:+\:\mathrm{tan}\:\mathrm{x}\:\mathrm{and}\:\mathrm{f}\:\mathrm{is}\:\mathrm{inverse} \\ $$$$\mathrm{of}\:\mathrm{g}\:,\:\mathrm{then}\:\mathrm{g}'\left(\mathrm{x}\right)\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to} \\ $$$$\left(\mathrm{a}\right)\:\frac{\mathrm{1}}{\mathrm{1}+\left(\mathrm{g}\left(\mathrm{x}\right)−\mathrm{x}\right)^{\mathrm{2}} }\:\:\:\left(\mathrm{b}\right)\:\frac{\mathrm{1}}{\mathrm{1}−\left(\mathrm{g}\left(\mathrm{x}\right)−\mathrm{x}\right)^{\mathrm{2}} } \\ $$$$\left(\mathrm{c}\right)\:\frac{\mathrm{1}}{\mathrm{2}+\left(\mathrm{g}\left(\mathrm{x}\right)−\mathrm{x}\right)^{\mathrm{2}} }\:\:\:\left(\mathrm{d}\right)\:\frac{\mathrm{1}}{\mathrm{2}−\left(\mathrm{g}\left(\mathrm{x}\right)−\mathrm{x}\right)^{\mathrm{2}} } \\ $$ Answered by liberty…