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Category: Relation and Functions

let-give-f-x-x-2-x-1-x-1-study-the-variation-of-and-give-the-graph-C-f-2-give-the-equation-of-tangent-at-C-f-in-point-A-1-f-1-

Question Number 29835 by abdo imad last updated on 12/Feb/18 $${let}\:{give}\:{f}\left({x}\right)=−{x}\:+\mathrm{2}\:+\frac{\sqrt{{x}+\mathrm{1}}}{{x}} \\ $$$$\left.\mathrm{1}\right)\:{study}\:{the}\:{variation}\:{of}\:{and}\:{give}\:{the}\:{graph}\:{C}_{{f}} \\ $$$$\left.\mathrm{2}\right){give}\:{the}\:{equation}\:{of}\:{tangent}\:{at}\:{C}_{{f}} \:{in}\:{point}\:{A}\left(\mathrm{1},{f}\left(\mathrm{1}\right)\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

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Question Number 29831 by abdo imad last updated on 12/Feb/18 $$\left.{let}\:{give}\:{f}\left({x}\right)=\:\frac{\mathrm{1}}{\mathrm{1}+{x}^{\mathrm{2}} }\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{1}\right){prove}\:{that}\:\:\:{prove}\:{that} \\ $$$${f}^{\left({n}\right)} \left({x}\right)=\frac{{p}_{{n}} \left({x}\right)}{\left(\mathrm{1}+{x}^{\mathrm{2}} \right)^{{n}+\mathrm{1}} }\:{with}\:{p}_{{n}} {is}\:{a}\:{polynomial} \\ $$$$\left.\mathrm{2}\right)\:{prove}\:{that}\:{p}_{{n}+\mathrm{1}} \left({x}\right)=\left(\mathrm{1}+{x}^{\mathrm{2}} \right){p}_{{n}} ^{'} \left({x}\right)\:−\mathrm{2}\left({n}+\mathrm{1}\right){p}_{{n}}…

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Question Number 95212 by mathmax by abdo last updated on 24/May/20 $$\mathrm{solve}\:\mathrm{by}\:\mathrm{Laplace}\:\mathrm{transform} \\ $$$$\mathrm{y}^{''} \:+\mathrm{5y}^{'} \:+\mathrm{2y}\:=\mathrm{x}^{\mathrm{2}} \mathrm{cosx}\:\:\mathrm{with}\:\mathrm{y}\left(\mathrm{o}\right)=\mathrm{1}\:\mathrm{and}\:\mathrm{y}^{'} \left(\mathrm{0}\right)\:=\mathrm{2} \\ $$ Answered by mathmax by abdo…

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Question Number 95150 by bobhans last updated on 23/May/20 $$\mathrm{how}\:\mathrm{do}\:\mathrm{you}\:\mathrm{solve}\:\mathrm{f}\left(\mathrm{x}\right)\:+\mathrm{2}\:\mathrm{f}\left(\frac{\mathrm{1}}{\mathrm{1}−\mathrm{x}}\right)\:=\:\mathrm{x}\: \\ $$$$\mathrm{for}\:\mathrm{f}\:?\: \\ $$ Answered by mr W last updated on 23/May/20 $${f}\left({x}\right)+\mathrm{2}{f}\left(\frac{\mathrm{1}}{\mathrm{1}−{x}}\right)={x}\:\:\:…\left({i}\right) \\ $$$${f}\left(\frac{\mathrm{1}}{\mathrm{1}−{x}}\right)+\mathrm{2}{f}\left(\frac{{x}−\mathrm{1}}{{x}}\right)=\frac{\mathrm{1}}{\mathrm{1}−{x}}\:\:\:…\left({ii}\right)…