Question Number 29319 by kunalnotiyal2005@gmail.com last updated on 07/Feb/18 $$\left.{m}\left.{xmz}\right]\mathrm{33}\right]\mathrm{2}{n}\mathrm{3}{xmxksnd} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 94756 by AshrafNejem last updated on 20/May/20 $$\left.{s}\left.{olution}:\:\mathrm{Q1}\right){a}\right)\:{n}=\frac{{ln}\left({m}/{m}_{\mathrm{0}} \right)}{{ln}\mathrm{0}.\mathrm{5}}\:=\:\frac{{ln}\left(\mathrm{12}/\mathrm{75}\right)}{{ln}\mathrm{0}.\mathrm{5}}\:=\mathrm{2}.\mathrm{64} \\ $$$${N}=\mathrm{N}_{\mathrm{0}} \left(\mathrm{0}.\mathrm{5}\right)^{{n}} \:=\:\mathrm{6}.\mathrm{02}×\mathrm{10}^{\mathrm{23}} \left(\mathrm{0}.\mathrm{5}\right)^{\mathrm{2}.\mathrm{64}} =\:\mathrm{9}.\mathrm{66}×\mathrm{10}^{\mathrm{22}} \\ $$$${A}=\lambda{N}=\mathrm{1}.\mathrm{5}×\mathrm{10}^{−\mathrm{4}} \:×\:\mathrm{9}.\mathrm{66}×\mathrm{10}^{\mathrm{22}} =\mathrm{1}.\mathrm{45}×\mathrm{10}^{\mathrm{19}} \:{Bq} \\ $$ Commented…
Question Number 29159 by abdo imad last updated on 04/Feb/18 $${let}\:{give}\:{f}\left({x}\right)=\mathrm{2}\sqrt{{x}−\mathrm{1}}\:+\mathrm{3}{x}\:\:\:{find}\:{f}^{−\mathrm{1}} \left({x}\right)\:{and}\:\left({f}^{−\mathrm{1}} \right)^{'} \left({x}\right)\:. \\ $$ Commented by abdo imad last updated on 08/Feb/18 $${f}\left({x}\right)={y}\:\Leftrightarrow\:{x}={f}^{−\mathrm{1}}…
Question Number 29161 by abdo imad last updated on 04/Feb/18 $${let}\:{give}\:{f}\left({x}\right)=\sqrt{{x}−\mathrm{1}+\mathrm{2}\sqrt{{x}−\mathrm{2}}}\:\:+\sqrt{{x}−\mathrm{1}−\mathrm{2}\sqrt{{x}−\mathrm{2}}} \\ $$$$\left.\mathrm{1}\right)\:{simlify}\:{f}\left({x}\right) \\ $$$$\left.\mathrm{2}\right)\:{solve}\:{inside}\:\mathbb{N}^{\mathrm{2}} \:{the}\:{equation}\:{f}\left({x}\right)={y}. \\ $$ Commented by abdo imad last updated on…
Question Number 29156 by abdo imad last updated on 04/Feb/18 $${find}\:{lim}_{{x}\rightarrow\mathrm{0}^{+} } \:\:\:{x}\left[\frac{\mathrm{1}}{{x}}\right]\:\:{and}\:\:{lim}_{{x}\rightarrow\mathrm{0}^{+} } \:\:\:\:{x}^{\mathrm{2}} \:\left[\:\frac{\mathrm{1}}{{x}}\right]\:\:. \\ $$$$\left[\alpha\right]\:{is}\:{the}\:{greatest}\:{integr}\:{inferior}\:{or}\:{equal}\:{to}\:\alpha. \\ $$ Commented by abdo imad last…
Question Number 29148 by abdo imad last updated on 04/Feb/18 $${let}\:{give}\:{the}\:{sequence}\:\left({u}_{{n}} \right)\:/{u}_{\mathrm{0}} =\mathrm{1}\:{and}\:{u}_{\mathrm{1}} =\mathrm{2}\:{and} \\ $$$$\forall\:{n}\:\in{N}\:\:\:\mathrm{2}{u}_{{n}+\mathrm{2}} =\mathrm{3}\:{u}_{{n}+\mathrm{1}} −{u}_{{n}} .\:{let}\:{give}\:{the}\:{sequence}\:\left({v}_{{n}} \right)\:/ \\ $$$${v}_{{n}} =\:{u}_{{n}+\mathrm{1}} −{u}_{{n}} \:.…
Question Number 29149 by abdo imad last updated on 04/Feb/18 $$\left({u}_{{n}} \right)_{{n}} \:\:{is}\:{arithmetic}\:{progression}/\:{u}_{{n}} =\:{u}_{\mathrm{0}} +{nr}\: \\ $$$${find}\:{S}_{{n}} =\:\:\sum_{{k}=\mathrm{0}} ^{{n}} \:\:{u}_{{k}} ^{\mathrm{2}} .\: \\ $$ Answered…
Question Number 94660 by msup by abdo last updated on 20/May/20 $${u}_{{n}} =\left(\mathrm{1}+\frac{\mathrm{1}}{{n}^{\mathrm{2}} }\right)\left(\mathrm{1}+\frac{\mathrm{2}}{{n}^{\mathrm{2}} }\right)…\left(\mathrm{1}+\frac{{n}}{{n}^{\mathrm{2}} }\right) \\ $$$${find}\:{lim}_{{n}\rightarrow+\infty} {u}_{{n}} \\ $$ Terms of Service Privacy…