Question Number 128496 by mathmax by abdo last updated on 07/Jan/21 $$\mathrm{calculate}\:\:\:\mathrm{A}\:=\frac{\mathrm{1}}{\left(\mathrm{2}−\sqrt{\mathrm{6}}\right)^{\mathrm{4}} }+\frac{\mathrm{1}}{\left(\mathrm{2}+\sqrt{\mathrm{6}}\right)^{\mathrm{4}} } \\ $$ Commented by liberty last updated on 08/Jan/21 $$\frac{\left(\mathrm{2}−\sqrt{\mathrm{6}}\right)^{\mathrm{4}} +\left(\mathrm{2}+\sqrt{\mathrm{6}}\right)^{\mathrm{4}}…
Question Number 62924 by mathmax by abdo last updated on 26/Jun/19 $${find}\:{min}_{\left({a},{b}\right)\in{R}^{\mathrm{2}} } \:\:\:\:\:\int_{−\mathrm{1}} ^{\mathrm{1}} \left({ax}+{b}\right)^{\mathrm{2}} {dx} \\ $$ Commented by kaivan.ahmadi last updated on…
Question Number 128425 by bramlexs22 last updated on 07/Jan/21 $$\:\mathrm{If}\:\mathrm{f}\left(\mathrm{x}\right)\:=\:\mathrm{x}\:+\:\mathrm{tan}\:\mathrm{x}\:\mathrm{and}\:\mathrm{f}\:\mathrm{is}\:\mathrm{inverse} \\ $$$$\mathrm{of}\:\mathrm{g}\:,\:\mathrm{then}\:\mathrm{g}'\left(\mathrm{x}\right)\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to} \\ $$$$\left(\mathrm{a}\right)\:\frac{\mathrm{1}}{\mathrm{1}+\left(\mathrm{g}\left(\mathrm{x}\right)−\mathrm{x}\right)^{\mathrm{2}} }\:\:\:\left(\mathrm{b}\right)\:\frac{\mathrm{1}}{\mathrm{1}−\left(\mathrm{g}\left(\mathrm{x}\right)−\mathrm{x}\right)^{\mathrm{2}} } \\ $$$$\left(\mathrm{c}\right)\:\frac{\mathrm{1}}{\mathrm{2}+\left(\mathrm{g}\left(\mathrm{x}\right)−\mathrm{x}\right)^{\mathrm{2}} }\:\:\:\left(\mathrm{d}\right)\:\frac{\mathrm{1}}{\mathrm{2}−\left(\mathrm{g}\left(\mathrm{x}\right)−\mathrm{x}\right)^{\mathrm{2}} } \\ $$ Answered by liberty…
Question Number 128424 by bramlexs22 last updated on 07/Jan/21 $$\mathrm{If}\:\mathrm{f}\left(\mathrm{x}\right)\:\mathrm{is}\:\mathrm{an}\:\mathrm{even}\:\mathrm{function}\:\mathrm{and} \\ $$$$\mathrm{satisfies}\:\mathrm{the}\:\mathrm{relation}\:\mathrm{x}^{\mathrm{2}} \mathrm{f}\left(\mathrm{x}\right)−\mathrm{2f}\left(\mathrm{x}\right)=\mathrm{g}\left(\mathrm{x}\right) \\ $$$$\mathrm{where}\:\mathrm{g}\left(\mathrm{x}\right)\:\mathrm{is}\:\mathrm{an}\:\mathrm{odd}\:\mathrm{function}\: \\ $$$$\mathrm{then}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{f}\left(\mathrm{5}\right)\:\mathrm{is}\: \\ $$$$\left(\mathrm{a}\right)\:\mathrm{0}\:\:\left(\mathrm{b}\right)\:\frac{\mathrm{37}}{\mathrm{75}}\:\:\:\left(\mathrm{c}\right)\:\mathrm{4}\:\:\:\:\left(\mathrm{d}\right)\:\frac{\mathrm{51}}{\mathrm{77}} \\ $$ Answered by mr W…
Question Number 62882 by mathmax by abdo last updated on 26/Jun/19 $${let}\:{f}\left({x}\right)={ln}\mid\frac{{x}−\mathrm{1}}{{x}+\mathrm{1}}\mid \\ $$$$\left.\mathrm{1}\right){determine}\:{D}_{{f}} \\ $$$$\left.\mathrm{2}\right)\:{calculatef}^{\left({n}\right)} \left({x}\right)\:{and}\:{f}^{\left({n}\right)} \left(\mathrm{0}\right) \\ $$$$\left.\mathrm{3}\right)\:{developp}\:{f}\:{at}\:{integr}\:{serie} \\ $$$$\left.\mathrm{4}\right)\:{calculate}\:\int_{−\frac{\mathrm{1}}{\mathrm{2}}} ^{\frac{\mathrm{1}}{\mathrm{2}}} {f}\left({x}\right){dx}\:. \\…
Question Number 62878 by mathmax by abdo last updated on 26/Jun/19 $${calculate}\:{min}\:\sum_{\mathrm{0}\leqslant{i}\leqslant{n}\:{and}\:\mathrm{0}\leqslant{j}\leqslant{n}} \:\:\:\:{i}.{j} \\ $$ Answered by mr W last updated on 26/Jun/19 $$\sum_{\mathrm{0}\leqslant{i}\leqslant{n}\:{and}\:\mathrm{0}\leqslant{j}\leqslant{n}} \:\:\:\:{i}.{j}…
Question Number 62879 by mathmax by abdo last updated on 26/Jun/19 $${calculate}\:{min}\:\sum_{\mathrm{0}\leqslant{i}\leqslant{n}\:\:{and}\:\mathrm{0}\leqslant{j}\leqslant{n}} \:\left({i}+{j}\right) \\ $$ Answered by mr W last updated on 26/Jun/19 $$\sum_{\mathrm{0}\leqslant{i}\leqslant{n}\:\:{and}\:\mathrm{0}\leqslant{j}\leqslant{n}} \:\left({i}+{j}\right)…
Question Number 62877 by mathmax by abdo last updated on 26/Jun/19 $${calculate}\:{lim}_{{n}\rightarrow+\infty} \:\sum_{{k}=\mathrm{0}} ^{\mathrm{2}{n}+\mathrm{1}} \:\frac{{n}}{{n}^{\mathrm{2}} \:+{k}} \\ $$ Commented by mathmax by abdo last updated…
Question Number 128401 by bramlexs22 last updated on 07/Jan/21 $$\mathrm{Given}\:\mathrm{function}\:\mathrm{f}\left({x}+\mathrm{1}\right)+\mathrm{f}\left({x}−\mathrm{1}\right)={x}^{\mathrm{2}} \\ $$$$\mathrm{then}\:\mathrm{f}^{−\mathrm{1}} \left({x}\right)\:=\:? \\ $$$$\left({A}\right)\:\pm\sqrt{\mathrm{1}−\mathrm{2}{x}}\:;\:{x}\leqslant\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\left({B}\right)\:\pm\sqrt{{x}+\mathrm{2}}\:;\:{x}\geqslant−\mathrm{2} \\ $$$$\left({C}\right)\:\pm\sqrt{\mathrm{2}{x}+\mathrm{1}}\:;\:{x}\geqslant−\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\left({D}\right)\:\pm\sqrt{\mathrm{3}{x}−\mathrm{1}}\:;\:{x}\geqslant\frac{\mathrm{1}}{\mathrm{3}} \\ $$$$\left({E}\right)\:\pm\sqrt{\mathrm{2}{x}−\mathrm{1}}\:;\:{x}\geqslant\frac{\mathrm{1}}{\mathrm{2}} \\ $$…
Question Number 128402 by bramlexs22 last updated on 07/Jan/21 $$\:\mathrm{If}\:\mathrm{f}\left({x}^{\mathrm{2}} −\mathrm{5}{x}+\mathrm{4}\right)={x}+\mathrm{3}\:\mathrm{then}\:\mathrm{f}\left(−\mathrm{2}\right)=? \\ $$ Answered by liberty last updated on 07/Jan/21 $$\Rightarrow\mathrm{x}^{\mathrm{2}} −\mathrm{5x}+\mathrm{4}=−\mathrm{2}\:;\:\mathrm{x}^{\mathrm{2}} −\mathrm{5x}+\mathrm{6}=\mathrm{0} \\ $$$$\:\left(\mathrm{x}−\mathrm{3}\right)\left(\mathrm{x}−\mathrm{2}\right)=\mathrm{0}\:\rightarrow\begin{cases}{\mathrm{x}=\mathrm{3}}\\{\mathrm{x}=\mathrm{2}}\end{cases}\:\Leftrightarrow\mathrm{f}\left(−\mathrm{2}\right)=\begin{cases}{\mathrm{6}}\\{\mathrm{5}}\end{cases}…