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Category: Relation and Functions

Question-158306

Question Number 158306 by mathlove last updated on 02/Nov/21 Commented by cortano last updated on 02/Nov/21 $${f}\left(\mathrm{1}−{x}\right)=\frac{\mathrm{4}^{\mathrm{1}−{x}} }{\mathrm{4}^{\mathrm{1}−{x}} +\mathrm{2}}\:=\:\frac{\frac{\mathrm{4}}{\mathrm{4}^{{x}} }}{\frac{\mathrm{4}}{\mathrm{4}^{{x}} }+\mathrm{2}}=\frac{\mathrm{4}}{\mathrm{4}+\mathrm{2}.\mathrm{4}^{{x}} } \\ $$$${f}\left({x}\right)+{f}\left(\mathrm{1}−{x}\right)=\frac{\mathrm{4}^{{x}} }{\mathrm{4}^{{x}}…

If-f-x-3-f-x-2-and-f-1-x-1-f-x-find-f-173-1993-

Question Number 158166 by cortano last updated on 31/Oct/21 $$\:{If}\:{f}\left(\frac{{x}}{\mathrm{3}}\right)=\frac{{f}\left({x}\right)}{\mathrm{2}}\:{and}\:{f}\left(\mathrm{1}−{x}\right)=\mathrm{1}−{f}\left({x}\right). \\ $$$${find}\:{f}\left(\frac{\mathrm{173}}{\mathrm{1993}}\right). \\ $$ Commented by SLVR last updated on 05/Nov/21 $${sir}\:\:{can}\:{you}\:{provide}\:{the}\:{answer} \\ $$ Terms…

let-give-f-x-x-4x-2-1-find-f-n-x-

Question Number 27081 by abdo imad last updated on 01/Jan/18 $${let}\:{give}\:{f}\left({x}\right)=\:\:\frac{{x}}{\mathrm{4}{x}^{\mathrm{2}} −\mathrm{1}}\:\:{find}\:{f}^{\left({n}\right)} \left({x}\right)\:\:. \\ $$ Answered by prakash jain last updated on 01/Jan/18 $${f}\left({x}\right)\frac{{x}}{\mathrm{4}{x}^{\mathrm{2}} −\mathrm{1}}=\frac{\mathrm{1}}{\mathrm{4}}\left(\frac{\mathrm{1}}{\mathrm{2}{x}−\mathrm{1}}+\frac{\mathrm{1}}{\mathrm{2}{x}+\mathrm{1}}\right)…

If-f-x-1-x-1-and-g-x-x-find-domain-and-range-of-g-f-x-

Question Number 92597 by john santu last updated on 08/May/20 $$\mathrm{If}\:\mathrm{f}\left(\mathrm{x}\right)=\frac{\mathrm{1}}{\mathrm{x}−\mathrm{1}}\:\mathrm{and}\:\mathrm{g}\left(\mathrm{x}\right)=\sqrt{\mathrm{x}}\: \\ $$$$\mathrm{find}\:\mathrm{domain}\:\mathrm{and}\:\mathrm{range}\:\mathrm{of}\: \\ $$$$\mathrm{g}\left(\mathrm{f}\left(\mathrm{x}\right)\right)\:. \\ $$ Commented by jagoll last updated on 08/May/20 $$\mathrm{g}\left(\mathrm{f}\left(\mathrm{x}\right)\right)\:=\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{x}−\mathrm{1}}}\:…