Question Number 62879 by mathmax by abdo last updated on 26/Jun/19 $${calculate}\:{min}\:\sum_{\mathrm{0}\leqslant{i}\leqslant{n}\:\:{and}\:\mathrm{0}\leqslant{j}\leqslant{n}} \:\left({i}+{j}\right) \\ $$ Answered by mr W last updated on 26/Jun/19 $$\sum_{\mathrm{0}\leqslant{i}\leqslant{n}\:\:{and}\:\mathrm{0}\leqslant{j}\leqslant{n}} \:\left({i}+{j}\right)…
Question Number 62877 by mathmax by abdo last updated on 26/Jun/19 $${calculate}\:{lim}_{{n}\rightarrow+\infty} \:\sum_{{k}=\mathrm{0}} ^{\mathrm{2}{n}+\mathrm{1}} \:\frac{{n}}{{n}^{\mathrm{2}} \:+{k}} \\ $$ Commented by mathmax by abdo last updated…
Question Number 128401 by bramlexs22 last updated on 07/Jan/21 $$\mathrm{Given}\:\mathrm{function}\:\mathrm{f}\left({x}+\mathrm{1}\right)+\mathrm{f}\left({x}−\mathrm{1}\right)={x}^{\mathrm{2}} \\ $$$$\mathrm{then}\:\mathrm{f}^{−\mathrm{1}} \left({x}\right)\:=\:? \\ $$$$\left({A}\right)\:\pm\sqrt{\mathrm{1}−\mathrm{2}{x}}\:;\:{x}\leqslant\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\left({B}\right)\:\pm\sqrt{{x}+\mathrm{2}}\:;\:{x}\geqslant−\mathrm{2} \\ $$$$\left({C}\right)\:\pm\sqrt{\mathrm{2}{x}+\mathrm{1}}\:;\:{x}\geqslant−\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\left({D}\right)\:\pm\sqrt{\mathrm{3}{x}−\mathrm{1}}\:;\:{x}\geqslant\frac{\mathrm{1}}{\mathrm{3}} \\ $$$$\left({E}\right)\:\pm\sqrt{\mathrm{2}{x}−\mathrm{1}}\:;\:{x}\geqslant\frac{\mathrm{1}}{\mathrm{2}} \\ $$…
Question Number 128402 by bramlexs22 last updated on 07/Jan/21 $$\:\mathrm{If}\:\mathrm{f}\left({x}^{\mathrm{2}} −\mathrm{5}{x}+\mathrm{4}\right)={x}+\mathrm{3}\:\mathrm{then}\:\mathrm{f}\left(−\mathrm{2}\right)=? \\ $$ Answered by liberty last updated on 07/Jan/21 $$\Rightarrow\mathrm{x}^{\mathrm{2}} −\mathrm{5x}+\mathrm{4}=−\mathrm{2}\:;\:\mathrm{x}^{\mathrm{2}} −\mathrm{5x}+\mathrm{6}=\mathrm{0} \\ $$$$\:\left(\mathrm{x}−\mathrm{3}\right)\left(\mathrm{x}−\mathrm{2}\right)=\mathrm{0}\:\rightarrow\begin{cases}{\mathrm{x}=\mathrm{3}}\\{\mathrm{x}=\mathrm{2}}\end{cases}\:\Leftrightarrow\mathrm{f}\left(−\mathrm{2}\right)=\begin{cases}{\mathrm{6}}\\{\mathrm{5}}\end{cases}…
Question Number 62815 by mathmax by abdo last updated on 25/Jun/19 $${developp}\:{at}\:{fourier}\:{serie}\:{f}\left({x}\right)\:={cos}\left({tx}\right)\:\:,\mathrm{2}\pi\:{periodic}\:{even}\:. \\ $$ Commented by mathmax by abdo last updated on 28/Jun/19 $${f}\:{is}\:{even}\:\Rightarrow{f}\left({x}\right)\:=\frac{{a}_{\mathrm{0}} }{\mathrm{2}}\:+\sum_{{n}=\mathrm{1}}…
Question Number 62777 by James Bryan Botshabelo last updated on 25/Jun/19 $$\mathrm{5}^{\mathrm{3}{x}−\mathrm{1}} .\mathrm{4}^{\mathrm{2}{x}−\mathrm{2}} =\mathrm{625} \\ $$ Commented by kaivan.ahmadi last updated on 25/Jun/19 $$\mathrm{5}^{\mathrm{2}{x}−\mathrm{1}} .\mathrm{5}^{{x}}…
Question Number 128176 by liberty last updated on 05/Jan/21 $$\mathrm{Given}\:\mathrm{t}\left(\mathrm{x}\right)=\mathrm{ax}^{\mathrm{4}} +\mathrm{bx}^{\mathrm{2}} +\mathrm{x}+\mathrm{5}\:;\:\mathrm{where}\:\mathrm{a}\:\mathrm{and}\:\mathrm{b} \\ $$$$\mathrm{are}\:\mathrm{constant}.\:\mathrm{If}\:\mathrm{t}\left(−\mathrm{4}\right)=\mathrm{3}\:\mathrm{then}\:\mathrm{t}\left(\mathrm{4}\right)=? \\ $$ Answered by bemath last updated on 05/Jan/21 $$\left(\Rightarrow\right)\:\mathrm{t}\left(\mathrm{x}\right)=\mathrm{ax}^{\mathrm{4}} +\mathrm{bx}^{\mathrm{2}}…
Question Number 128035 by rs4089 last updated on 03/Jan/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 62440 by mathsolverby Abdo last updated on 21/Jun/19 $${let}\:{h}\left({x}\right)=\:{arctan}\left({x}+\frac{\mathrm{1}}{{x}}\right) \\ $$$$\left.\mathrm{1}\right){calculate}\:{h}^{\left({n}\right)} \left({x}\right)\:{and}\:{h}^{\left({n}\right)} \left(\mathrm{1}\right) \\ $$$$\left.\mathrm{2}\right){developp}\:{f}\left({x}\right){at}\:{integr}\:{serie}\:{at}\:{x}_{\mathrm{0}} =\mathrm{1} \\ $$ Commented by mathmax by abdo…
Question Number 62435 by mathsolverby Abdo last updated on 21/Jun/19 $${calculate}\:{lim}_{{x}\rightarrow\mathrm{0}} \:\:\frac{\left(\mathrm{1}+{x}\right)^{{sinx}} −\mathrm{1}}{{x}^{\mathrm{2}} } \\ $$ Commented by Smail last updated on 22/Jun/19 $$\left(\mathrm{1}+{x}\right)^{{sinx}} ={e}^{{ln}\left(\left(\mathrm{1}+{x}\right)^{{sinx}}…