Question Number 152671 by liberty last updated on 31/Aug/21 Commented by MJS_new last updated on 31/Aug/21 $${f}\left(\mathrm{1}\right)=\mathrm{5} \\ $$$${f}\left(\mathrm{2}\right)={f}\left(\mathrm{1}+\mathrm{1}\right)={f}\left(\mathrm{1}\right)+\mathrm{6}×\mathrm{1}+\mathrm{4}=\mathrm{15} \\ $$$${f}\left(\mathrm{3}\right)={f}\left(\mathrm{2}+\mathrm{1}\right)={f}\left(\mathrm{2}\right)+\mathrm{6}×\mathrm{2}+\mathrm{4}=\mathrm{31} \\ $$$$\mathrm{but} \\ $$$${f}\left(\mathrm{3}\right)={f}\left(\mathrm{3}×\mathrm{1}\right)=\mathrm{4}{f}\left(\mathrm{1}\right)+\mathrm{1}=\mathrm{21}…
Question Number 21491 by dioph last updated on 24/Sep/17 $$\mathrm{If}\:{Y}\:\mathrm{is}\:\mathrm{a}\:\mathrm{non}−\mathrm{void}\:\mathrm{set},\:\mathrm{define}\:{Y}^{{T}} \:\mathrm{to}\:\mathrm{be} \\ $$$$\mathrm{the}\:\mathrm{collection}\:\mathrm{of}\:\mathrm{all}\:\mathrm{functions}\:\mathrm{with} \\ $$$$\mathrm{domain}\:{T}\:\mathrm{and}\:\mathrm{range}\:{Y}.\:\mathrm{Show}\:\mathrm{that} \\ $$$$\mathrm{if}\:{T}\:\mathrm{and}\:{Y}\:\mathrm{are}\:\mathrm{finite}\:\mathrm{sets}\:\mathrm{with}\:{m}\:\mathrm{and} \\ $$$${n}\:\mathrm{elements},\:\mathrm{then}\:{Y}^{{T}} \:\mathrm{has}\:{n}^{{m}} \:\mathrm{elements}. \\ $$ Terms of…
Question Number 86983 by mathmax by abdo last updated on 01/Apr/20 $$\left.\mathrm{1}\right)\:{calculate}\:\int\:\:\frac{{dx}}{\left({x}+\mathrm{1}\right)^{\mathrm{3}} \left({x}−\mathrm{2}\right)^{\mathrm{3}} } \\ $$$$\left.\mathrm{2}\right)\:{decompose}\:{the}\:{fraction}\:{F}\left({x}\right)=\frac{\mathrm{1}}{\left({x}+\mathrm{1}\right)^{\mathrm{3}} \left({x}−\mathrm{2}\right)^{\mathrm{3}} } \\ $$ Commented by hknkrc46 last updated…
Question Number 86962 by abdomathmax last updated on 01/Apr/20 $${calculste}\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\:{x}^{\mathrm{2}} {ln}\left({x}\right){ln}\left(\mathrm{1}−{x}\right){dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 86960 by abdomathmax last updated on 01/Apr/20 $${let}\:{the}\:{mstrice}\:{A}\:\:=\begin{pmatrix}{\mathrm{1}\:\:\:\:\:\:\:\:\:\:\:\mathrm{1}}\\{−\mathrm{1}\:\:\:\:\:\:\:\mathrm{0}}\end{pmatrix} \\ $$$$\left.\mathrm{1}\right){calculste}\:{A}^{{n}} \\ $$$$\left.\mathrm{2}\right)\:{find}\:\:{e}^{{A}} \:{and}\:{e}^{−{A}} \\ $$$$\left.\mathrm{3}\right){find}\:{sin}\left({A}\right)\:{and}\:{cis}\left({A}\right) \\ $$ Commented by abdomathmax last updated on…
Question Number 86958 by abdomathmax last updated on 01/Apr/20 $${calculate}\:\sum_{{n}=\mathrm{1}} ^{\infty} \:\frac{\left(−\mathrm{1}\right)^{{n}} }{{n}^{\mathrm{3}} \left({n}+\mathrm{1}\right)^{\mathrm{2}} } \\ $$ Commented by mathmax by abdo last updated on…
Question Number 21251 by youssoufab last updated on 17/Sep/17 $${resolve}\:: \\ $$$$\forall{x}\in\mathbb{R},\:\sqrt{{x}+\mathrm{1}}\mid{x}−\mathrm{2}\mid=\sqrt{{x}+\mathrm{2}}\mid{x}−\mathrm{1}\mid−\mathrm{2} \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 152151 by john_santu last updated on 26/Aug/21 Answered by Rasheed.Sindhi last updated on 26/Aug/21 $${f}\left({x}\right)=\frac{{ax}+{b}}{{cx}+{d}} \\ $$$$\bullet{f}\left({f}\left({x}\right)\right)=\frac{{a}\left(\frac{{ax}+{b}}{{cx}+{d}}\right)+{b}}{{c}\left(\frac{{ax}+{b}}{{cx}+{d}}\right)+{d}}={x} \\ $$$$\:\:\:=\frac{{a}\left({ax}+{b}\right)+{b}\left({cx}+{d}\right)}{{c}\left({ax}+{b}\right)+{d}\left({cx}+{d}\right)}={x} \\ $$$${x}=\mathrm{0}:\:\frac{{ab}+{bd}}{{bc}+{d}^{\mathrm{2}} }=\mathrm{0} \\…
Question Number 21021 by youssoufab last updated on 10/Sep/17 Commented by $@ty@m last updated on 10/Sep/17 $${pl}.\:{translate}\:{into}\:{English} \\ $$ Commented by Joel577 last updated on…
Question Number 86406 by mathmax by abdo last updated on 28/Mar/20 $${let}\:\:\overset{\rightarrow} {{u}}=\overset{\rightarrow} {{i}}−\overset{\rightarrow} {{j}}\:+\overset{\rightarrow} {{k}}\:{and}\:\overset{\rightarrow} {{v}}=\mathrm{2}\overset{\rightarrow} {{i}}+\overset{\rightarrow} {{j}}\:+\mathrm{3}\overset{\rightarrow} {{k}} \\ $$$$\left({o},{i},{j},{k}\right)\:{orthonormal} \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:\:\mid\mid\overset{\rightarrow} {{u}}\mid\mid\:\:,\mid\mid\overset{\rightarrow}…