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Category: Relation and Functions

The-maximum-value-of-f-x-2-x-2-2x-is-equal-to-1-6-2-4-3-5-4-3-

Question Number 18574 by Tinkutara last updated on 25/Jul/17 $$\mathrm{The}\:\mathrm{maximum}\:\mathrm{value}\:\mathrm{of}\:{f}\left({x}\right)\:=\:\mathrm{2}\:−\:\mid{x}\mid^{\mathrm{2}} \\ $$$$−\:\mathrm{2}{x}\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to} \\ $$$$\left(\mathrm{1}\right)\:\mathrm{6} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{4} \\ $$$$\left(\mathrm{3}\right)\:\mathrm{5} \\ $$$$\left(\mathrm{4}\right)\:\mathrm{3} \\ $$ Answered by prakash…

let-f-x-e-nx-ln-2-x-2-with-n-integr-natural-1-calculste-f-n-x-and-f-n-0-2-developp-f-at-integr-serie-3-find-0-1-f-x-d-and-0-f-x-dx-

Question Number 84029 by mathmax by abdo last updated on 08/Mar/20 $${let}\:{f}\left({x}\right)={e}^{−{nx}} {ln}\left(\mathrm{2}+{x}^{\mathrm{2}} \right)\:\:\:{with}\:{n}\:{integr}\:{natural} \\ $$$$\left.\mathrm{1}\right)\:{calculste}\:{f}^{\left({n}\right)} \left({x}\right)\:{and}\:{f}^{\left({n}\right)} \left(\mathrm{0}\right) \\ $$$$\left.\mathrm{2}\right)\:{developp}\:{f}\:{at}\:{integr}\:{serie} \\ $$$$\left.\mathrm{3}\right){find}\:\int_{\mathrm{0}} ^{\mathrm{1}} \:{f}\left({x}\right){d}\:{and}\:\int_{\mathrm{0}} ^{\infty}…

for-x-R-satisfy-the-equation-f-x-3x-f-1-x-2-x-1-find-f-2019-

Question Number 83956 by jagoll last updated on 08/Mar/20 $$\mathrm{for}\:\mathrm{x}\:\in\:\mathbb{R}\:\mathrm{satisfy}\:\mathrm{the}\:\mathrm{equation}\: \\ $$$$\mathrm{f}\left(\mathrm{x}\right)+\mathrm{3x}\:\mathrm{f}\left(\frac{\mathrm{1}}{\mathrm{x}}\right)\:=\:\mathrm{2}\left(\mathrm{x}+\mathrm{1}\right) \\ $$$$\mathrm{find}\:\mathrm{f}\left(\mathrm{2019}\right)\:.\: \\ $$ Commented by mr W last updated on 08/Mar/20 $$\mathrm{f}\left(\mathrm{x}\right)+\mathrm{3x}\:\mathrm{f}\left(\frac{\mathrm{1}}{\mathrm{x}}\right)\:=\:\mathrm{2}\left(\mathrm{x}+\mathrm{1}\right)\:\:\:…\left({i}\right)…

The-number-of-integral-values-of-x-which-satisfies-x-5-10-x-13-20-x-19-13-x-10-18-x-25-19-0-and-2-x-30-are-1-23-2-24-3-25-4-26-

Question Number 18416 by Tinkutara last updated on 20/Jul/17 $$\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{integral}\:\mathrm{values}\:\mathrm{of}\:{x} \\ $$$$\mathrm{which}\:\mathrm{satisfies} \\ $$$$\frac{\left({x}\:−\:\mathrm{5}\right)^{\mathrm{10}} \left({x}\:−\:\mathrm{13}\right)^{\mathrm{20}} \left({x}\:−\:\mathrm{19}\right)^{\mathrm{13}} }{\left({x}\:−\:\mathrm{10}\right)^{\mathrm{18}} \left({x}\:−\:\mathrm{25}\right)^{\mathrm{19}} }\:\geqslant\:\mathrm{0}\:\mathrm{and} \\ $$$$\mathrm{2}\:\leqslant\:{x}\:\leqslant\:\mathrm{30}\:\mathrm{are} \\ $$$$\left(\mathrm{1}\right)\:\mathrm{23} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{24}…

if-f-x-x-2-1-and-g-x-1-x-2-3-find-domain-function-g-f-x-

Question Number 83662 by jagoll last updated on 05/Mar/20 $$\mathrm{if}\:\mathrm{f}\left(\mathrm{x}\right)\:=\:\sqrt{\mathrm{x}^{\mathrm{2}} −\mathrm{1}}\:\:\:\mathrm{and}\:\mathrm{g}\left(\mathrm{x}\right)\:=\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{x}^{\mathrm{2}} −\mathrm{3}}} \\ $$$$\mathrm{find}\:\mathrm{domain}\:\mathrm{function}\: \\ $$$$\left(\mathrm{g}\:\bullet\:\mathrm{f}\right)\left(\mathrm{x}\right) \\ $$ Commented by MJS last updated on 05/Mar/20…

1-x-1-5-6-3-6-x-x-2-gt-1-1-x-1-

Question Number 83610 by john santu last updated on 04/Mar/20 $$\frac{\mathrm{1}}{\mathrm{x}−\mathrm{1}}\:+\:\frac{\mathrm{5}}{\mathrm{6}−\mathrm{3}\sqrt{\mathrm{6}+\mathrm{x}−\mathrm{x}^{\mathrm{2}} }}\:>\:\frac{\mathrm{1}}{\mathrm{1}+\mid\mathrm{x}−\mathrm{1}\mid} \\ $$ Commented by john santu last updated on 04/Mar/20 $$\mathrm{ans}\::\:\left[−\mathrm{2},\:−\mathrm{1}\right)\:\cup\:\left(\mathrm{1},\:\frac{\mathrm{6}}{\mathrm{5}}\right)\:\cup\:\left(\mathrm{2},\mathrm{3}\:\right] \\ $$…

what-is-range-of-function-f-x-x-x-2-1-

Question Number 83539 by jagoll last updated on 03/Mar/20 $$\mathrm{what}\:\mathrm{is}\:\mathrm{range}\:\mathrm{of}\:\mathrm{function}\: \\ $$$$\mathrm{f}\left(\mathrm{x}\right)\:=\:\frac{\mathrm{x}}{\:\sqrt{\mathrm{x}^{\mathrm{2}} −\mathrm{1}}}? \\ $$ Commented by john santu last updated on 03/Mar/20 $$\mathrm{domain}\:\mathrm{x}^{\mathrm{2}} −\mathrm{1}>\mathrm{0}\:\Rightarrow\:\mathrm{x}<−\mathrm{1}\:\vee\mathrm{x}\:>\mathrm{1}…