Question Number 83403 by jagoll last updated on 02/Mar/20 $$\mathrm{what}\:\mathrm{is}\:\mathrm{range}\:\mathrm{function}\: \\ $$$$\mathrm{y}\:=\:\frac{\mathrm{1}}{\left(\mathrm{x}−\mathrm{1}\right)^{\mathrm{2}} } \\ $$ Answered by MJS last updated on 02/Mar/20 $${y}=\frac{\mathrm{1}}{\left({x}−\mathrm{1}\right)^{\mathrm{2}} }\:\mathrm{defined}\:\mathrm{for}\:{x}\neq\mathrm{1} \\…
Question Number 83395 by Rio Michael last updated on 01/Mar/20 $$\mathrm{Let}\:\mathrm{R}\:\mathrm{be}\:\mathrm{a}\:\mathrm{relation}\:\mathrm{such}\:\mathrm{that}\: \\ $$$$\mathrm{R}\:=\:\left\{\mathrm{3},\mathrm{6},\mathrm{12},\mathrm{24}\right\} \\ $$$$\mathrm{prove}\:\mathrm{that}\:\mathrm{R}\:\mathrm{is}\:\mathrm{a}\:\mathrm{strict}\:\mathrm{order} \\ $$$$\mathrm{relation}.\: \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 148812 by mathmax by abdo last updated on 31/Jul/21 $$\mathrm{find}\:\int\:\:\frac{\mathrm{dx}}{\left(\sqrt{\mathrm{x}}+\sqrt{\mathrm{x}+\mathrm{1}}\right)\left(\sqrt{\mathrm{x}−\mathrm{1}}+\sqrt{\mathrm{x}}\right)} \\ $$ Answered by MJS_new last updated on 31/Jul/21 $$\int\frac{{dx}}{\left(\sqrt{{x}}+\sqrt{{x}+\mathrm{1}}\right)\left(\sqrt{{x}}+\sqrt{{x}−\mathrm{1}}\right)}= \\ $$$$=\int\left(\frac{\mathrm{1}}{\left(\sqrt{{x}}+\sqrt{{x}+\mathrm{1}}\right)\left(\sqrt{{x}}+\sqrt{{x}−\mathrm{1}}\right)}×\frac{\left(\sqrt{{x}}−\sqrt{{x}+\mathrm{1}}\right)\left(\sqrt{{x}}−\sqrt{{x}−\mathrm{1}}\right)}{\left(\sqrt{{x}}−\sqrt{{x}+\mathrm{1}}\right)\left(\sqrt{{x}}−\sqrt{{x}−\mathrm{1}}\right)}\right){dx}= \\…
Question Number 83255 by mathmax by abdo last updated on 29/Feb/20 $${let}\:{g}\left({x}\right)={ln}\left(\mathrm{2}−{cosx}\right) \\ $$$${devlopp}\:{g}\:{at}\:{integr}\:{serie} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 83254 by mathmax by abdo last updated on 29/Feb/20 $${let}\:{f}\left({x}\right)={arctan}\left(\mathrm{2}{x}−\frac{\mathrm{1}}{{x}}\right) \\ $$$${find}\:{f}^{\left({n}\right)} \left({x}\right)\:{andf}^{\left({n}\right)} \left(\mathrm{1}\right) \\ $$ Commented by mathmax by abdo last updated…
Question Number 83245 by mathmax by abdo last updated on 29/Feb/20 $${let}\:{f}\left({x}\right)\:={e}^{−\mathrm{2}{x}} {ln}\left(\mathrm{1}+\mathrm{2}{x}\right) \\ $$$$\left.\mathrm{1}\right)\:{find}\:{f}^{\left({n}\right)} \left({x}\right)\:{and}\:{f}^{\left({n}\right)} \left(\mathrm{0}\right) \\ $$$$\left.\mathrm{2}\right){developp}\:{f}\:{at}\:{integr}\:{serie} \\ $$ Commented by mathmax by…
Question Number 83214 by mathmax by abdo last updated on 28/Feb/20 $${calculate}\:\:{U}_{{n}} =\sum_{{k}=\mathrm{0}} ^{{n}} \:\frac{\mathrm{1}}{\mathrm{3}{k}+\mathrm{1}}\:{interms}\:{of}\:{H}_{{n}} =\sum_{{k}=\mathrm{1}} ^{{n}} \:\frac{\mathrm{1}}{{k}} \\ $$ Answered by ~blr237~ last updated…
Question Number 148568 by mathmax by abdo last updated on 29/Jul/21 $$\mathrm{calculate}\:\mathrm{lim}_{\mathrm{x}\rightarrow\mathrm{0}} \:\:\:\frac{\mathrm{sh}\left(\mathrm{2sinx}\right)−\mathrm{sin}\left(\mathrm{sh}\left(\mathrm{2x}\right)\right)}{\mathrm{x}^{\mathrm{2}} } \\ $$ Answered by Ar Brandon last updated on 29/Jul/21 $$\mathscr{L}=\underset{{x}\rightarrow\mathrm{0}}…
Question Number 148564 by mathmax by abdo last updated on 29/Jul/21 $$\mathrm{calculate}\:\int_{\mathrm{1}} ^{\mathrm{2}} \:\frac{\mathrm{logx}}{\mathrm{1}+\mathrm{x}}\mathrm{dx} \\ $$ Answered by Kamel last updated on 29/Jul/21 $$ \\…
Question Number 148558 by puissant last updated on 29/Jul/21 $$\mathrm{Trouver}\:\mathrm{toutes}\:\mathrm{les}\:\mathrm{fonctions}\:\mathrm{continues} \\ $$$$\mathrm{f}:\mathbb{R}\rightarrow\mathbb{R}\:\mathrm{verifiant}: \\ $$$$\forall\left(\mathrm{x},\mathrm{y}\right)\in\mathbb{R}^{\mathrm{2}} ,\:\mathrm{f}\left(\mathrm{x}+\mathrm{y}\right)\mathrm{f}\left(\mathrm{x}−\mathrm{y}\right)=\mathrm{f}^{\mathrm{2}} \left(\mathrm{x}\right)\mathrm{f}^{\mathrm{2}} \left(\mathrm{y}\right).. \\ $$$$\mathrm{monsieur}\:\mathrm{j}'\mathrm{ai}\:\mathrm{suppos}\acute {\mathrm{e}}\:\mathrm{que}\:\mathrm{f}\:\mathrm{est}\:\mathrm{un}\: \\ $$$$\mathrm{morphisme}\:\mathrm{mutiplicatif}\:\mathrm{de}\:\mathbb{R}..\:\mathrm{mais}\:\mathrm{ca}\:\mathrm{ne} \\ $$$$\mathrm{sort}\:\mathrm{pas}… \\…