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Category: Relation and Functions

find-dx-x-x-1-x-1-x-

Question Number 148812 by mathmax by abdo last updated on 31/Jul/21 finddx(x+x+1)(x1+x) Answered by MJS_new last updated on 31/Jul/21 dx(x+x+1)(x+x1)=$$=\int\left(\frac{\mathrm{1}}{\left(\sqrt{{x}}+\sqrt{{x}+\mathrm{1}}\right)\left(\sqrt{{x}}+\sqrt{{x}−\mathrm{1}}\right)}×\frac{\left(\sqrt{{x}}−\sqrt{{x}+\mathrm{1}}\right)\left(\sqrt{{x}}−\sqrt{{x}−\mathrm{1}}\right)}{\left(\sqrt{{x}}−\sqrt{{x}+\mathrm{1}}\right)\left(\sqrt{{x}}−\sqrt{{x}−\mathrm{1}}\right)}\right){dx}= \