Question Number 147258 by alcohol last updated on 19/Jul/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 81720 by mathmax by abdo last updated on 14/Feb/20 $${let}\:{f}\left({x}\right)={arctan}\left(\mathrm{1}+{x}^{\mathrm{2}} \right) \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:{f}^{\left({n}\right)} \left({x}\right)\:{and}\:{f}^{\left({n}\right)} \left(\mathrm{0}\right) \\ $$$$\left.\mathrm{2}\right)\:{developpf}\:{at}\:{integr}\:{serie} \\ $$ Commented by mathmax by…
Question Number 147218 by mathmax by abdo last updated on 19/Jul/21 $$\mathrm{calculate}\:\int_{\mid\mathrm{z}−\mathrm{1}\mid=\mathrm{2}} \:\:\:\:\frac{\mathrm{e}^{\mathrm{z}} }{\left(\mathrm{z}+\mathrm{i}\sqrt{\mathrm{2}}\right)^{\mathrm{2}} \left(\mathrm{z}+\mathrm{i}\right)^{\mathrm{2}} \left(\mathrm{2z}−\mathrm{1}\right)}\mathrm{dz} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 147205 by mathmax by abdo last updated on 18/Jul/21 $$\mathrm{calculate}\:\int_{\mathrm{1}} ^{\infty} \:\frac{\mathrm{arctan}\left(\frac{\mathrm{3}}{\mathrm{x}}\right)}{\mathrm{2x}^{\mathrm{2}} \:+\mathrm{1}}\mathrm{dx} \\ $$ Answered by mathmax by abdo last updated on…
Question Number 147204 by mathmax by abdo last updated on 18/Jul/21 $$\mathrm{find}\:\int_{\mathrm{0}} ^{\mathrm{1}} \mathrm{lnxln}\left(\mathrm{1}−\mathrm{x}\right)\mathrm{ln}\left(\mathrm{1}−\mathrm{x}^{\mathrm{2}} \right)\mathrm{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 147201 by mathmax by abdo last updated on 18/Jul/21 $$\mathrm{f}\left(\mathrm{x}\right)=\mathrm{cos}\left(\mathrm{sinx}\right)\:\:\mathrm{developp}\:\mathrm{f}\:\mathrm{at}\:\mathrm{fourier}\:\mathrm{serie} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 16086 by Tinkutara last updated on 17/Jun/17 $$\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{values}\:\mathrm{of}\:{x}\:\mathrm{which}\:\mathrm{are} \\ $$$$\mathrm{satisfying}\:\mathrm{the}\:\mathrm{equation}\:\mid{x}\:+\:\mathrm{4}\mid\:=\:\mathrm{8}\left[{x}\right] \\ $$$$+\:{x}\:−\:\mathrm{4}\:\mathrm{is}?\:\left(\mathrm{where}\:\left[\centerdot\right]\:\mathrm{Greatest}\:\mathrm{Integer}\right. \\ $$$$\left.\mathrm{Function}\right) \\ $$ Commented by prakash jain last updated on…
Question Number 16087 by Tinkutara last updated on 17/Jun/17 $$\mathrm{Number}\:\mathrm{of}\:\mathrm{solution}\:\mathrm{of}\:\mathrm{equation} \\ $$$$\mathrm{2}\left[−{x}\right]\:+\:\mathrm{3}{x}\:=\:\mathrm{7}\left\{{x}\right\}\:\mathrm{is}?\:\left(\mathrm{where}\:\left[\centerdot\right]\:=\right. \\ $$$$\mathrm{Greatest}\:\mathrm{Integer}\:\mathrm{Function}\:\&\:\left\{\centerdot\right\} \\ $$$$\left.\mathrm{fractional}\:\mathrm{function}.\right) \\ $$ Commented by prakash jain last updated on…
Question Number 16082 by Tinkutara last updated on 17/Jun/17 $$\mathrm{Solution}\:\mathrm{of}\:\mathrm{equation}\:\mathrm{2}\left[{x}\right]\:+\:\mathrm{4}\left\{{x}\right\}\:=\:\mathrm{3}{x} \\ $$$$+\:\mathrm{2}\:\left(\mathrm{where}\:\left\{\centerdot\right\}\:\mathrm{denotes}\:\mathrm{fractional}\right. \\ $$$$\left.\mathrm{function}\:\mathrm{and}\:\left[\centerdot\right]\:\mathrm{denotes}\:\mathrm{G}.\mathrm{I}.\mathrm{F}\right)\:\mathrm{is} \\ $$$$\left(\mathrm{1}\right)\:\left\{−\mathrm{2}\right\} \\ $$$$\left(\mathrm{2}\right)\:\left\{−\mathrm{2},\:−\:\frac{\mathrm{3}}{\mathrm{2}}\right\} \\ $$$$\left(\mathrm{3}\right)\:\phi \\ $$$$\left(\mathrm{4}\right)\:{R} \\ $$ Commented…
Question Number 16085 by Tinkutara last updated on 18/Jun/17 $$\mathrm{Let}\:{f}\left(\mathrm{sin}\:{x}\right)\:+\:\mathrm{2}{f}\left(\mathrm{cos}\:{x}\right)\:=\:\mathrm{3}\:\forall\:{x}\:\in\:\left(\mathrm{0},\:\frac{\pi}{\mathrm{2}}\right). \\ $$$$\mathrm{Then} \\ $$$$\left(\mathrm{1}\right)\:{f}\left(\mathrm{sin}\:{x}\right)\:=\:\mathrm{1},\:{x}\:\in\:\left(\mathrm{0},\:\frac{\pi}{\mathrm{2}}\right) \\ $$$$\left(\mathrm{2}\right)\:{f}\left(\mathrm{sin}\:{x}\right)\:=\:\mathrm{1},\:{x}\:\in\:\left(−\mathrm{1},\:\mathrm{0}\right) \\ $$$$\left(\mathrm{3}\right)\:{f}\left(\mathrm{cos}\:{x}\right)\:=\:\mathrm{1},\:{x}\:\in\:\left(\mathrm{0},\:\mathrm{1}\right) \\ $$$$\left(\mathrm{4}\right)\:{f}\left({x}\right)\:=\:\mathrm{1},\:{x}\:\in\:\left(\mathrm{0},\:\mathrm{1}\right) \\ $$ Commented by prakash…