Question Number 15082 by Tinkutara last updated on 07/Jun/17
Question Number 15084 by Tinkutara last updated on 07/Jun/17
Question Number 146085 by mathmax by abdo last updated on 10/Jul/21
Question Number 146083 by mathmax by abdo last updated on 10/Jul/21
Question Number 146087 by mathmax by abdo last updated on 10/Jul/21
Question Number 146082 by mathmax by abdo last updated on 10/Jul/21
Question Number 146072 by savitar last updated on 10/Jul/21
Question Number 146061 by alcohol last updated on 10/Jul/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 146041 by alcohol last updated on 10/Jul/21
Question Number 145960 by puissant last updated on 10/Jul/21 Answered by mathmax by abdo last updated on 10/Jul/21 $$\mathrm{R}_{\mathrm{n}} =\sum_{\mathrm{p}=\mathrm{n}+\mathrm{1}} ^{\mathrm{2n}} \mathrm{sin}\left(\frac{\mathrm{1}}{\mathrm{p}}\right)\:\Rightarrow\mathrm{R}_{\mathrm{n}} =_{\mathrm{p}−\mathrm{n}=\mathrm{k}} \:\:\sum_{\mathrm{k}=\mathrm{1}} ^{\mathrm{n}}…