Category: Relation and Functions

Question Number 140978 by Mathspace last updated on 14/May/21 $$calculate\sum _{n=0}^{\mathrm{\infty }}\frac{1}{{(n!)}^2}$$ Answered by Dwaipayan Shikari last updated on 14/May/21 $$\underset{{n}=\mathrm{0}} {\overset{\infty}…

Question Number 140828 by jlewis last updated on 13/May/21 $$\mathrm{factorise}{3\mathrm{k}}^2+2\mathrm{kh}-{8\mathrm{h}}^2$$ Answered by liberty last updated on 13/May/21 $$(3\mathrm{k}-4\mathrm{h})(\mathrm{k}+2\mathrm{h})$$ Commented by…

Question Number 75212 by chess1 last updated on 08/Dec/19 Answered by mind is power last updated on 08/Dec/19 $$\mathrm{x}=\mathrm{y}=0\Rightarrow$$$$\mathrm{f}\left(0\right)=1$$$$\mathrm{y}=-2\mathrm{x}$$$$\mathrm{f}\left(\mathrm{x}\right)+\mathrm{1}−\mathrm{10x}^{\mathrm{2}}…

Question Number 9571 by PANKAJ last updated on 16/Dec/16 Answered by ridwan balatif last updated on 17/Dec/16 $$1.(\frac{\mathrm{x}}{3}+1,\mathrm{y}-\frac{2}{3})=(\frac{5}{3},\frac{1}{3})$$$$\frac{\mathrm{x}}{3}+1=\frac{5}{3}\mathrm{y}-\frac{2}{3}=\frac{1}{3}$$$$\frac{\mathrm{x}}{3}=\frac{2}{3}\mathrm{y}=1$$$$\mathrm{x}=\mathrm{2} \…

Question Number 140636 by Mathspace last updated on 10/May/21 $$calculate\sum _{n=1}^{\mathrm{\infty }}\frac{{(-1)}^n}{n^2(n+1){(2n+1)}^2}$$ Answered by Dwaipayan Shikari last updated on 10/May/21…