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Category: Relation and Functions

Question-140748

Question Number 140748 by 676597498 last updated on 12/May/21 Answered by qaz last updated on 12/May/21 $$\left({i}\right)…{r}=\frac{\mathrm{2}}{\mathrm{1}+\mathrm{sin}\:\theta} \\ $$$$\Rightarrow{r}+{r}\mathrm{sin}\:\theta=\mathrm{2} \\ $$$$\Rightarrow\sqrt{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} }+{y}=\mathrm{2} \\ $$$$\Rightarrow{x}^{\mathrm{2}}…

Question-9571

Question Number 9571 by PANKAJ last updated on 16/Dec/16 Answered by ridwan balatif last updated on 17/Dec/16 $$\mathrm{1}.\left(\frac{\mathrm{x}}{\mathrm{3}}+\mathrm{1},\mathrm{y}−\frac{\mathrm{2}}{\mathrm{3}}\right)=\left(\frac{\mathrm{5}}{\mathrm{3}},\frac{\mathrm{1}}{\mathrm{3}}\right) \\ $$$$\frac{\mathrm{x}}{\mathrm{3}}+\mathrm{1}=\frac{\mathrm{5}}{\mathrm{3}}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{y}−\frac{\mathrm{2}}{\mathrm{3}}=\frac{\mathrm{1}}{\mathrm{3}} \\ $$$$\:\:\:\:\:\:\:\:\frac{\mathrm{x}}{\mathrm{3}}=\frac{\mathrm{2}}{\mathrm{3}}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{y}=\mathrm{1} \\ $$$$\mathrm{x}=\mathrm{2} \\…

let-f-x-arctan-2-x-developp-f-at-integr-serie-

Question Number 140638 by Mathspace last updated on 10/May/21 $${let}\:{f}\left({x}\right)={arctan}\left(\frac{\mathrm{2}}{{x}}\right) \\ $$$${developp}\:{f}\:{at}\:{integr}\:{serie} \\ $$ Answered by Dwaipayan Shikari last updated on 10/May/21 $${f}\left({x}\right)={f}\left(\mathrm{0}\right)+\frac{{f}'\left(\mathrm{0}\right)}{\mathrm{1}!}{x}+\frac{{f}''\left(\mathrm{0}\right)}{\mathrm{2}!}{x}^{\mathrm{2}} +.. \\…