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Category: Relation and Functions

Question-139032

Question Number 139032 by bramlexs22 last updated on 21/Apr/21 Answered by EDWIN88 last updated on 21/Apr/21 $$\:\ell\mathrm{et}\:\mathrm{y}=\frac{\mathrm{1}−\mathrm{x}}{\mathrm{1}+\mathrm{x}}\:\Rightarrow\mathrm{xy}+\mathrm{y}=\mathrm{1}−\mathrm{x}\: \\ $$$$\:\mathrm{xy}+\mathrm{x}=\mathrm{1}−\mathrm{y}\:\Rightarrow\:\mathrm{x}=\frac{\mathrm{1}−\mathrm{y}}{\mathrm{1}+\mathrm{x}} \\ $$$$\:\left(\mathrm{f}\left(\frac{\mathrm{1}−\mathrm{x}}{\mathrm{1}+\mathrm{x}}\right)\right)^{\mathrm{2}} .\mathrm{f}\left(\mathrm{x}\right)\:=\:\frac{\mathrm{1}−\mathrm{x}}{\mathrm{1}+\mathrm{x}}\:\ldots\left(\mathrm{1}\right) \\ $$$$\left(\mathrm{f}\left(\frac{\mathrm{1}−\mathrm{x}}{\mathrm{1}+\mathrm{x}}\right)\right).\left(\mathrm{f}\left(\mathrm{x}\right)\right)^{\mathrm{2}} \:=\:\mathrm{x}\:\ldots\left(\mathrm{2}\right)…

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Question Number 139029 by bramlexs22 last updated on 21/Apr/21 $$\mathrm{Given}\:\mathrm{f}\left(\mathrm{x}+\sqrt{\mathrm{1}+\mathrm{x}^{\mathrm{2}} }\right)=\:\frac{\mathrm{x}}{\mathrm{x}+\mathrm{1}} \\ $$$$\mathrm{find}\:\mathrm{f}\left(\mathrm{x}\right)=? \\ $$ Answered by EDWIN88 last updated on 21/Apr/21 $$\:\:\:\:\:\:\:\:\:\mathrm{u}=\mathrm{x}+\sqrt{\mathrm{1}+\mathrm{x}^{\mathrm{2}} } \\…

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Question Number 73487 by abdomathmax last updated on 13/Nov/19 $${let}\:\:\:\:\alpha\:{and}\:\beta\:{roots}\:{of}\:\:{the}\:{equation}\:\:{x}^{\mathrm{2}} −{x}+\mathrm{2}=\mathrm{0} \\ $$$${simplify}\:\:\:{A}_{{p}} =\:\alpha^{{p}} \:+\beta^{{p}} \:{and}\:{calculate} \\ $$$$\sum_{{p}=\mathrm{0}} ^{{n}−\mathrm{1}} \:{A}_{{p}} \:\:{and}\:\sum_{{p}=\mathrm{0}} ^{{n}−\mathrm{1}} \:\:{A}_{{p}} ^{\mathrm{2}} \\…

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Question Number 73486 by abdomathmax last updated on 13/Nov/19 $${let}\:{P}\left({x}\right)=\left(\mathrm{1}+{ix}\right)^{{n}} −\left(\mathrm{1}−{ix}\right)^{{n}} \:{with}\:{n}\:{integr} \\ $$$${decompose}\:{the}\:{Fraction}\:{F}\:\left({x}\right)=\frac{\mathrm{1}}{{P}\left({x}\right)} \\ $$ Commented by abdomathmax last updated on 17/Nov/19 $${P}\left({x}\right)=\mathrm{0}\:\Leftrightarrow\frac{\left(\mathrm{1}−{ix}\right)^{{n}} }{\left(\mathrm{1}+{ix}\right)^{{n}}…

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Question Number 73485 by abdomathmax last updated on 13/Nov/19 $${find}\:{the}\:{roots}\:{of}\:{P}\left({x}\right)=\left(\mathrm{1}+{ix}\:+{jx}^{\mathrm{2}} \right)^{{n}} −\mathrm{1} \\ $$$${with}\:{j}\:={e}^{{i}\frac{\mathrm{2}\pi}{\mathrm{3}}} \:\:\:{then}\:{factorize}\:{P}\left({x}\right)\:{inside}\:{C}\left[{x}\right] \\ $$$${decompose}\:{the}\:{fraction}\:{F}=\frac{\mathrm{1}}{{P}} \\ $$ Terms of Service Privacy Policy Contact:…