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Category: Relation and Functions

compare-without-calculator-5-1-7-1-and-7-1-5-1-

Question Number 135378 by Bird last updated on 12/Mar/21 $${compare}\:{without}\:{calculator} \\ $$$$\mathrm{5}\left(\sqrt{\mathrm{1}+\sqrt{\mathrm{7}}}−\mathrm{1}\right)\:{and}\:\mathrm{7}\left(\sqrt{\mathrm{1}+\sqrt{\mathrm{5}}}−\mathrm{1}\right) \\ $$ Answered by mr W last updated on 12/Mar/21 $$\mathrm{5}\left(\sqrt{\mathrm{1}+\sqrt{\mathrm{7}}}−\mathrm{1}\right)<\mathrm{5}\left(\sqrt{\mathrm{1}+\sqrt{\mathrm{9}}}−\mathrm{1}\right)=\mathrm{5} \\ $$$$…

let-f-x-e-2x-ln-3-x-1-calculate-f-n-x-and-f-n-0-2-developp-f-at-integr-serie-

Question Number 135369 by Bird last updated on 12/Mar/21 $${let}\:{f}\left({x}\right)={e}^{−\mathrm{2}{x}} {ln}\left(\mathrm{3}+{x}\right) \\ $$$$\left.\mathrm{1}\left.\right)\:{calculate}\:{f}^{\left({n}\right.} \right)\left({x}\right)\:{and}\:{f}^{\left({n}\right)} \left(\mathrm{0}\right) \\ $$$$\left.\mathrm{2}\right){developp}\:{f}\:{at}\:{integr}\:{serie} \\ $$ Terms of Service Privacy Policy Contact:…

1-find-f-0-cos-x-x-4-1-2-dx-with-real-2-find-the-value-of-0-cos-2x-x-4-1-2-dx-3-find-nature-of-the-serie-f-n-

Question Number 69803 by Abdo msup. last updated on 28/Sep/19 $$\left.\mathrm{1}\right){find}\:\:\:{f}\left(\alpha\right)\:=\int_{\mathrm{0}} ^{\infty} \:\:\:\frac{{cos}\left(\alpha{x}\right)}{\left({x}^{\mathrm{4}} +\mathrm{1}\right)^{\mathrm{2}} }{dx}\:\:{with}\:\alpha\:{real} \\ $$$$\left.\mathrm{2}\right)\:{find}\:{the}\:{value}\:\:{of}\:\int_{\mathrm{0}} ^{\infty} \:\:\frac{{cos}\left(\mathrm{2}{x}\right)}{\left({x}^{\mathrm{4}} +\mathrm{1}\right)^{\mathrm{2}} }{dx} \\ $$$$\left.\mathrm{3}\right)\:{find}\:{nature}\:{of}\:{the}\:{serie}\:\Sigma{f}\left({n}\right) \\ $$…