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Category: Relation and Functions

Analytical-Continuation-Sum-of-the-below-divergent-series-was-shown-to-be-using-analytical-continuation-i-1-n-2-i-1-1-A-1-i-0-i-1-12-B-While-reading-about

Question Number 2720 by prakash jain last updated on 25/Nov/15 AnalyticalContinuationSumofthebelowdivergentserieswasshowntobeusinganalyticalcontinuation.ni=12i1=1(A)$$\zeta\left(−\mathrm{1}\right)=\underset{{i}=\mathrm{0}} {\overset{\infty} {\sum}}{i}=−\frac{\mathrm{1}}{\mathrm{12}}\:\:\:\:\:\:…\left(\mathrm{B}\right) \