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Category: Relation and Functions

let-f-x-x-2-3x-arctan-2x-1-1-determine-f-n-x-and-f-n-0-2-developp-f-at-integr-serie-3-calculate-0-1-f-x-dx-

Question Number 68238 by mathmax by abdo last updated on 07/Sep/19 $${let}\:\:{f}\left({x}\right)=\left({x}^{\mathrm{2}} −\mathrm{3}{x}\right){arctan}\left(\mathrm{2}{x}+\mathrm{1}\right) \\ $$$$\left.\mathrm{1}\right)\:{determine}\:{f}^{\left({n}\right)} \left({x}\right)\:\:{and}\:{f}^{\left({n}\right)} \left(\mathrm{0}\right) \\ $$$$\left.\mathrm{2}\right){developp}\:{f}\:{at}\:{integr}\:{serie} \\ $$$$\left.\mathrm{3}\right)\:{calculate}\:\int_{\mathrm{0}} ^{\mathrm{1}} {f}\left({x}\right){dx} \\ $$…

Bases-on-suggestion-from-Filup-and-some-discussion-on-that-I-am-suggesting-that-we-sequence-series-and-related-function-as-a-topic-for-this-month-x-n-1-n-x-x-R-x-gt-1-Show-that-x-

Question Number 2675 by prakash jain last updated on 24/Nov/15 $$\mathrm{Bases}\:\mathrm{on}\:\mathrm{suggestion}\:\mathrm{from}\:\mathrm{Filup}\:\mathrm{and}\:\mathrm{some} \\ $$$$\mathrm{discussion}\:\mathrm{on}\:\mathrm{that}\:\mathrm{I}\:\mathrm{am}\:\mathrm{suggesting}\:\mathrm{that}\:\mathrm{we} \\ $$$$\mathrm{sequence},\:\mathrm{series}\:\mathrm{and}\:\mathrm{related}\:\mathrm{function}\:\mathrm{as}\:\mathrm{a} \\ $$$$\mathrm{topic}\:\mathrm{for}\:\mathrm{this}\:\mathrm{month}. \\ $$$$\zeta\left({x}\right)=\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}{n}^{−{x}} ,\:{x}\in\mathbb{R},\:{x}>\mathrm{1} \\ $$$$\mathrm{Show}\:\mathrm{that} \\…

f-x-y-f-x-1-y-x-1-f-x-y-ye-x-x-0-f-5-6-

Question Number 2604 by 123456 last updated on 23/Nov/15 $${f}\left({x},{y}\right)={f}\left({x}−\mathrm{1},{y}−{x}\right)+\mathrm{1} \\ $$$${f}\left({x},{y}\right)={ye}^{{x}} ,{x}\leqslant\mathrm{0} \\ $$$${f}\left(\mathrm{5},\mathrm{6}\right)=? \\ $$ Answered by Yozzis last updated on 23/Nov/15 $${f}\left(\mathrm{5},\mathrm{6}\right)={f}\left(\mathrm{4},\mathrm{1}\right)+\mathrm{1}…

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Question Number 68129 by mathmax by abdo last updated on 05/Sep/19 $${prove}\:{that}\:\pi{cotan}\left(\alpha\pi\right)=\frac{\mathrm{1}}{\alpha}\:+\sum_{{n}=\mathrm{1}} ^{\infty} \:\frac{\mathrm{2}\alpha}{\alpha^{\mathrm{2}} −{n}^{\mathrm{2}} } \\ $$$${with}\:\alpha\:\in{R}−{Z}\:\:. \\ $$$${prove}\:{also}\:{that}\:\:\:{for}\:{t}\neq\mathrm{0} \\ $$$${cotan}\left({t}\right)\:=\frac{\mathrm{1}}{{t}}\:+\sum_{{n}=\mathrm{1}} ^{\infty} \:\:\frac{\mathrm{2}{t}}{{t}^{\mathrm{2}} −{n}^{\mathrm{2}}…