Category: Relation and Functions

Question Number 56330 by maxmathsup by imad last updated on 14/Mar/19 $$calculate\sum _{n=0}^{\mathrm{\infty }}\frac{{(-1)}^n}{n^2(3n+1)}$$ Commented by maxmathsup by imad last updated…

Question Number 121490 by mathmax by abdo last updated on 08/Nov/20 $$\mathrm{let}\mathrm{f}\left(\mathrm{x}\right)=\ln \left(\mathrm{tanx}\right)$$$$\mathrm{developp}\mathrm{f}\mathrm{at}\mathrm{fourier}\mathrm{serie}$$ Answered by mnjuly1970 last updated on 08/Nov/20 $$\:\:\:\mathrm{1}.{f}\left({x}\right)={ln}\left(\mathrm{2}{sin}\left({x}\right)\right)\overset{{fourier}\:{series}} {=}\underset{{n}=\mathrm{1}}…

Question Number 55823 by 121194 last updated on 04/Mar/19 $$let$$$$f(n,m)=\{\begin{array}{ll}1& n=1\\ m+1& n=2\\ \underset{i=0}{\sum ^m}f(n-1,i)& n>2\end{array}$$$$a.\mathrm{compute}f(3,4)$$$$b.\mathrm{find}\mathrm{a}\mathrm{function}\mathrm{tha}\mathrm{satisfies}\mathrm{above}\mathrm{recursion}.$$ Terms of Service Privacy Policy…

Question Number 55621 by Tawa1 last updated on 28/Feb/19 $$\mathrm{The}\mathrm{function}\mathrm{pogof}\left(\mathrm{x}\right)={\mathrm{x}}^4+{2\mathrm{x}}^3+{2\mathrm{x}}^2\mathrm{is}\mathrm{divisible}\mathrm{by}\mathrm{the}\mathrm{half}\mathrm{of}\mathrm{the}$$$$\mathrm{function}\mathrm{of}\mathrm{p}.\mathrm{Find}\mathrm{g}\left(\mathrm{x}\right).$$ Answered by kaivan.ahmadi last updated on 28/Feb/19 $$\mathrm{2}{p}\left({gof}\left({x}\right)\right)=\mathrm{2}{x}^{\mathrm{2}}…

Question Number 120819 by bramlexs22 last updated on 03/Nov/20 $$\mathrm{If}\mathrm{f}\left(\mathrm{x}\right)+2\mathrm{f}\left(\frac{1}{\mathrm{x}}\right)+3\mathrm{f}\left(\frac{\mathrm{x}}{\mathrm{x}-1}\right)=\mathrm{x}$$$$\mathrm{what}\mathrm{is}\mathrm{f}\left(\mathrm{x}\right)?$$ Commented by liberty last updated on 03/Nov/20 $$\left(\mathrm{i}\right)\mathrm{f}\left(\mathrm{x}\right)+2\mathrm{f}\left(\frac{1}{\mathrm{x}}\right)+3\mathrm{f}\left(\frac{\mathrm{x}}{\mathrm{x}-1}\right)=\mathrm{x}$$$$\left(\mathrm{ii}\right)\:\mathrm{replace}\:\mathrm{x}\:\mathrm{with}\:\frac{\mathrm{1}}{\mathrm{x}},\:\mathrm{give} \…