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Category: Relation and Functions

If-is-an-even-function-defined-on-the-interval-5-5-then-a-value-of-x-satisfying-the-equation-f-x-f-x-1-x-2-is-a-1-5-2-b-3-5-2-c-1-5-2-d-3-5-2-

Question Number 44351 by Necxx last updated on 27/Sep/18 $${If}\:{is}\:{an}\:{even}\:{function}\:{defined}\:{on} \\ $$$${the}\:{interval}\:\left(−\mathrm{5},\mathrm{5}\right)\:{then}\:{a}\:{value} \\ $$$${of}\:{x}\:{satisfying}\:{the}\:{equation} \\ $$$${f}\left({x}\right)={f}\left(\frac{{x}+\mathrm{1}}{{x}+\mathrm{2}}\right)\:{is} \\ $$$$\left.{a}\left.\right)\left.\frac{−\mathrm{1}+\sqrt{\mathrm{5}}}{\mathrm{2}}\:{b}\right)\frac{−\mathrm{3}+\sqrt{\mathrm{5}}}{\mathrm{2}}\:{c}\right)\frac{−\mathrm{1}−\sqrt{\mathrm{5}}}{\mathrm{2}}\: \\ $$$$\left.{d}\right)\frac{−\mathrm{3}−\sqrt{\mathrm{5}}}{\mathrm{2}_{} } \\ $$ Commented by…

let-u-n-0-1-x-n-artan-nx-dx-1-lim-u-n-2-nature-of-u-n-3-calculate-u-n-4-equivalent-of-u-n-

Question Number 174938 by Mathspace last updated on 14/Aug/22 $${let}\:{u}_{{n}} =\:\int_{\mathrm{0}} ^{\mathrm{1}} {x}^{{n}} {artan}\left({nx}\right){dx} \\ $$$$\left.\mathrm{1}\right){lim}\:{u}_{{n}} ? \\ $$$$\left.\mathrm{2}\right){nature}\:{of}\:\Sigma\:{u}_{{n}} \\ $$$$\left.\mathrm{3}\right)\:{calculate}\:{u}_{{n}} \\ $$$$\left.\mathrm{4}\right){equivalent}\:{of}\:{u}_{{n}} ? \\…

find-nature-of-n-0-1-x-2-cos-n-x-with-mean-floor-

Question Number 109213 by mathmax by abdo last updated on 22/Aug/20 $$\mathrm{find}\:\mathrm{nature}\:\mathrm{of}\:\sum_{\mathrm{n}=\mathrm{0}} ^{\infty} \:\frac{\left(−\mathrm{1}\right)^{\left[\mathrm{x}\right]} }{\mathrm{2}+\mathrm{cos}\left(\mathrm{n}\left[\mathrm{x}\right]\right)}\:\:\mathrm{with}\:\left[..\right]\:\mathrm{mean}\:\mathrm{floor} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

find-lim-x-pi-2-sinx-ln-x-pi-2-

Question Number 109191 by abdomsup last updated on 21/Aug/20 $${find}\:\:{lim}_{{x}\rightarrow\frac{\pi}{\mathrm{2}}} \:\:\:\left({sinx}\right)^{{ln}\mid{x}−\frac{\pi}{\mathrm{2}}\mid} \\ $$ Commented by bemath last updated on 22/Aug/20 $${set}\:{x}\:=\:\frac{\pi}{\mathrm{2}}+\:{z} \\ $$$${L}=\:\underset{{z}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(\mathrm{sin}\:\left(\frac{\pi}{\mathrm{2}}+{z}\right)\right)^{\mathrm{ln}\:\mid{z}\mid} =\underset{{z}\rightarrow\mathrm{0}}…