Category: Relation and Functions

Question Number 41512 by maxmathsup by imad last updated on 08/Aug/18 $$let{u}_n=\frac{1}{1^3}+\frac{1}{2^3}+\dots .+\frac{1}{n^3}$$$$1)provethat\frac{9}{8}-\frac{1}{2{(n+1)}^2}⩽u_n⩽\frac{3}{2}-\frac{1}{2n^2}$$$$\left.\mathrm{2}\right)\:{prove}\:{that}\:\forall\:{n}\in{N}^{\bigstar} \:\:\:\mathrm{1}\leqslant{u}_{{n}} \leqslant\:\frac{\mathrm{3}}{\mathrm{2}}…

Question Number 41410 by maxmathsup by imad last updated on 06/Aug/18 $$let{A}_n={\int }_0^{\mathrm{\infty }}\left[{ne}^{-x}\right]dxwithn⩾2$$$$1)calculate{A}_n$$$$2)findnatureof\sum _{n⩾2}{A}_n$$$$\left.\mathrm{3}\right)\:{study}\:{the}\:{convergence}\:{of}\:\:\Sigma\:\frac{\mathrm{1}}{{A}_{{n}} }\:\:{and}\:\Sigma\:\frac{\mathrm{1}}{{A}_{{n}} ^{\mathrm{2}}…

Question Number 41409 by maxmathsup by imad last updated on 06/Aug/18 $$calculate{S}_p=\sum _{n=1}^{\mathrm{\infty }}\frac{{(-1)}^n}{n(n+1)(n+2)\dots (n+p)}withpfromN$$ Answered by sma3l2996 last updated on 07/Aug/18…

Question Number 41349 by math khazana by abdo last updated on 06/Aug/18 $$calculate\sum _{n=1}^{\mathrm{\infty }}\frac{{(-1)}^n}{3n-1}$$ Commented by maxmathsup by imad last updated…

Question Number 41342 by maxmathsup by imad last updated on 05/Aug/18 $$findthevalueof\sum _{n=1}^{\mathrm{\infty }}\frac{1}{n^2{(n+1)}^2{(n+2)}^2}$$ Terms of Service Privacy Policy Contact:…