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Question Number 38699 by Tinkutara last updated on 28/Jun/18 Answered by behi83417@gmail.com last updated on 28/Jun/18 $${y}^{\mathrm{2}} ={a}^{\mathrm{2}} +{b}^{\mathrm{2}} +\mathrm{2}\sqrt{\left({a}^{\mathrm{2}} {cos}^{\mathrm{2}} {x}+{b}^{\mathrm{2}} {sin}^{\mathrm{2}} {x}\right)\left({a}^{\mathrm{2}} {sin}^{\mathrm{2}}…
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