Question Number 38692 by Zuarkton last updated on 28/Jun/18 $${If}\:{f}\left({x}\right)=\mathrm{2}{x}+\mathrm{1} \\ $$$${g}\left({x}\right)=\sqrt{{x}}+\mathrm{3} \\ $$$${h}\left({x}\right)=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$${then}\:{hog}^{\mathrm{2}} \:{of}\:\left(\mathrm{2}\right)=? \\ $$ Answered by MJS last updated on…
Question Number 38643 by maxmathsup by imad last updated on 27/Jun/18 $${calculate}\:{lim}_{{n}\rightarrow+\infty} \:\:\:\frac{\mathrm{1}+\mathrm{2}+\mathrm{3}+…+{n}}{\mathrm{1}+\mathrm{2}^{\mathrm{4}} \:+\mathrm{3}^{\mathrm{4}} \:+…+{n}^{\mathrm{4}} } \\ $$ Commented by abdo mathsup 649 cc last…
Question Number 38641 by maxmathsup by imad last updated on 27/Jun/18 $${calculate}\:{lim}_{{n}\rightarrow+\infty} \:\:\:\frac{\mathrm{1}+\mathrm{2}^{\mathrm{3}} \:+\mathrm{3}^{\mathrm{3}} \:+….+{n}^{\mathrm{3}} }{\mathrm{1}+\mathrm{2}^{\mathrm{4}} \:+\mathrm{3}^{\mathrm{4}} \:+…+{n}^{\mathrm{4}} }\:. \\ $$ Commented by abdo mathsup…
Question Number 38642 by maxmathsup by imad last updated on 27/Jun/18 $${calculate}\:{lim}_{{n}\rightarrow+\infty} \:\:\frac{\mathrm{1}\:+\mathrm{2}^{\mathrm{2}} \:+\mathrm{3}^{\mathrm{2}} \:+….+{n}^{\mathrm{2}} }{\mathrm{1}+\mathrm{2}^{\mathrm{4}} \:+\mathrm{3}^{\mathrm{4}} \:+….+{n}^{\mathrm{4}} } \\ $$ Commented by tanmay.chaudhury50@gmail.com last…
Question Number 38640 by maxmathsup by imad last updated on 27/Jun/18 $${calculate}\:\sum_{{k}=\mathrm{1}} ^{{n}} {k}^{\mathrm{4}} \:\:{interms}\:{of}\:{n}. \\ $$ Commented by math khazana by abdo last updated…
Question Number 38533 by behi83417@gmail.com last updated on 26/Jun/18 Commented by math khazana by abdo last updated on 03/Aug/18 $$\left.\mathrm{1}\right)\:{f}\left({a}\right)={f}\left({b}\right)\:\Rightarrow\frac{{pa}+\sqrt{{pa}}}{\:\sqrt{{pa}+\mathrm{1}}}\:=\frac{{pb}+\sqrt{{pb}}}{\:\sqrt{{pb}}\:+\mathrm{1}}\:\Rightarrow \\ $$$$\left.\mathrm{2}\right)\:{f}\left({p}\right)={p}−\mathrm{1}\:\Rightarrow\frac{{p}^{\mathrm{2}} \:+{p}}{\:\sqrt{{p}^{\mathrm{2}} \:+\mathrm{1}}}\:={p}−\mathrm{1}\:\Rightarrow \\…
Question Number 38521 by math khazana by abdo last updated on 26/Jun/18 $${letf}\left({x}\right)\:=\:\frac{\mathrm{2}{x}+\mathrm{1}}{\left({x}−\mathrm{2}\right)\left({x}^{\mathrm{2}} \:+{x}+\mathrm{1}\right)} \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:{f}^{\left({n}\right)} \left({x}\right) \\ $$$$\left.\mathrm{2}\right)\:{find}\:{f}^{\left({n}\right)} \left(\mathrm{0}\right) \\ $$$$\left.\mathrm{3}\right)\:{developp}\:{f}\:{at}\:{integr}\:{serie}. \\ $$$$\left(\right. \\…
Question Number 38518 by math khazana by abdo last updated on 26/Jun/18 $${calculate}\:\:\sum_{{n}=\mathrm{1}} ^{\infty} \:\:\frac{\mathrm{1}}{{n}^{\mathrm{2}} \left(\mathrm{2}{n}−\mathrm{1}\right)^{\mathrm{2}} } \\ $$ Commented by prof Abdo imad last…
Question Number 38520 by math khazana by abdo last updated on 26/Jun/18 $${find}\:{the}\:{value}\:{of}\:\sum_{{n}=\mathrm{2}} ^{\infty} \:\:\frac{\mathrm{3}{n}^{\mathrm{2}} \:+\mathrm{1}}{\left({n}−\mathrm{1}\right)^{\mathrm{3}} \left({n}+\mathrm{1}\right)^{\mathrm{3}} } \\ $$ Commented by abdo mathsup 649…
Question Number 103995 by mathmax by abdo last updated on 18/Jul/20 $$\mathrm{solve}\:\mathrm{y}^{''} +\mathrm{2y}^{'} −\mathrm{y}\:=\frac{\mathrm{e}^{−\mathrm{x}} }{\mathrm{x}} \\ $$ Answered by mathmax by abdo last updated on…