Question Number 38721 by maxmathsup by imad last updated on 28/Jun/18 $${let}\:\:{f}\left({x}\right)=\sqrt{\mathrm{1}+\mathrm{2}{x}^{\mathrm{2}} }\:\:−{x}\sqrt{\mathrm{2}}\:\:+\mathrm{3} \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:{lim}_{{x}\rightarrow+\infty} \:{f}\left({x}\right)\:{and}\:{lim}_{{x}\rightarrow−\infty} {f}\left({x}\right) \\ $$$$\left.\mathrm{2}\right){calculate}\:{lim}_{{x}\rightarrow+\infty} \:\:\frac{{f}\left({x}\right)}{{x}}\:{and}\:{lim}_{{x}\rightarrow−\infty} \:\:\frac{{f}\left({x}\right)}{{x}} \\ $$$$\left.\mathrm{3}\right){give}\:{the}\:{assymtote}\:{to}\:{graph}\:{C}_{{f}} \\ $$$$\left.\mathrm{4}\right)\:{give}\:{the}\:{assymtote}\:{to}\:{C}_{{f}}…
Question Number 38722 by maxmathsup by imad last updated on 28/Jun/18 $${let}\:{f}\left({x}\right)=\:\left({x}+\mathrm{1}\right){e}^{−{x}} \:\:{and}\:\:{g}\left({x}\right)={ln}\left(\mathrm{2}+{x}^{\mathrm{2}} \right) \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:{fog}\left({x}\right)\:{and}\:{gof}\left({x}\right) \\ $$$$\left.\mathrm{2}\right)\:{calculate}\:\:\left({fog}\right)^{'} \left({x}\right)\:{and}\:\left({gof}\right)^{'} \left({x}\right). \\ $$ Commented by math…
Question Number 38699 by Tinkutara last updated on 28/Jun/18 Answered by behi83417@gmail.com last updated on 28/Jun/18 $${y}^{\mathrm{2}} ={a}^{\mathrm{2}} +{b}^{\mathrm{2}} +\mathrm{2}\sqrt{\left({a}^{\mathrm{2}} {cos}^{\mathrm{2}} {x}+{b}^{\mathrm{2}} {sin}^{\mathrm{2}} {x}\right)\left({a}^{\mathrm{2}} {sin}^{\mathrm{2}}…
Question Number 38692 by Zuarkton last updated on 28/Jun/18 $${If}\:{f}\left({x}\right)=\mathrm{2}{x}+\mathrm{1} \\ $$$${g}\left({x}\right)=\sqrt{{x}}+\mathrm{3} \\ $$$${h}\left({x}\right)=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$${then}\:{hog}^{\mathrm{2}} \:{of}\:\left(\mathrm{2}\right)=? \\ $$ Answered by MJS last updated on…
Question Number 38643 by maxmathsup by imad last updated on 27/Jun/18 $${calculate}\:{lim}_{{n}\rightarrow+\infty} \:\:\:\frac{\mathrm{1}+\mathrm{2}+\mathrm{3}+…+{n}}{\mathrm{1}+\mathrm{2}^{\mathrm{4}} \:+\mathrm{3}^{\mathrm{4}} \:+…+{n}^{\mathrm{4}} } \\ $$ Commented by abdo mathsup 649 cc last…
Question Number 38641 by maxmathsup by imad last updated on 27/Jun/18 $${calculate}\:{lim}_{{n}\rightarrow+\infty} \:\:\:\frac{\mathrm{1}+\mathrm{2}^{\mathrm{3}} \:+\mathrm{3}^{\mathrm{3}} \:+….+{n}^{\mathrm{3}} }{\mathrm{1}+\mathrm{2}^{\mathrm{4}} \:+\mathrm{3}^{\mathrm{4}} \:+…+{n}^{\mathrm{4}} }\:. \\ $$ Commented by abdo mathsup…
Question Number 38642 by maxmathsup by imad last updated on 27/Jun/18 $${calculate}\:{lim}_{{n}\rightarrow+\infty} \:\:\frac{\mathrm{1}\:+\mathrm{2}^{\mathrm{2}} \:+\mathrm{3}^{\mathrm{2}} \:+….+{n}^{\mathrm{2}} }{\mathrm{1}+\mathrm{2}^{\mathrm{4}} \:+\mathrm{3}^{\mathrm{4}} \:+….+{n}^{\mathrm{4}} } \\ $$ Commented by tanmay.chaudhury50@gmail.com last…
Question Number 38640 by maxmathsup by imad last updated on 27/Jun/18 $${calculate}\:\sum_{{k}=\mathrm{1}} ^{{n}} {k}^{\mathrm{4}} \:\:{interms}\:{of}\:{n}. \\ $$ Commented by math khazana by abdo last updated…
Question Number 38533 by behi83417@gmail.com last updated on 26/Jun/18 Commented by math khazana by abdo last updated on 03/Aug/18 $$\left.\mathrm{1}\right)\:{f}\left({a}\right)={f}\left({b}\right)\:\Rightarrow\frac{{pa}+\sqrt{{pa}}}{\:\sqrt{{pa}+\mathrm{1}}}\:=\frac{{pb}+\sqrt{{pb}}}{\:\sqrt{{pb}}\:+\mathrm{1}}\:\Rightarrow \\ $$$$\left.\mathrm{2}\right)\:{f}\left({p}\right)={p}−\mathrm{1}\:\Rightarrow\frac{{p}^{\mathrm{2}} \:+{p}}{\:\sqrt{{p}^{\mathrm{2}} \:+\mathrm{1}}}\:={p}−\mathrm{1}\:\Rightarrow \\…
Question Number 38521 by math khazana by abdo last updated on 26/Jun/18 $${letf}\left({x}\right)\:=\:\frac{\mathrm{2}{x}+\mathrm{1}}{\left({x}−\mathrm{2}\right)\left({x}^{\mathrm{2}} \:+{x}+\mathrm{1}\right)} \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:{f}^{\left({n}\right)} \left({x}\right) \\ $$$$\left.\mathrm{2}\right)\:{find}\:{f}^{\left({n}\right)} \left(\mathrm{0}\right) \\ $$$$\left.\mathrm{3}\right)\:{developp}\:{f}\:{at}\:{integr}\:{serie}. \\ $$$$\left(\right. \\…