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Category: Relation and Functions

Question-100951

Question Number 100951 by bemath last updated on 29/Jun/20 Commented by Rasheed.Sindhi last updated on 29/Jun/20 $${By}\:{john}\:{santu}\left({answer}\:{of}\right. \\ $$$$\left.{q}#\mathrm{97746}\right)\:{Same}\:{as}\:{above}. \\ $$$$\mathrm{2}^{{x}} \left(\mathrm{1}+\mathrm{2}^{{x}+\mathrm{1}} \right)\:=\:\left({y}−\mathrm{1}\right)\left({y}+\mathrm{1}\right) \\ $$$${show}\:{that}\:{the}\:{factors}\:{y}−\mathrm{1}\:{and}\:{y}+\mathrm{1}…

let-f-x-e-2x-arctanx-1-calculate-f-n-x-2-find-f-n-0-3-developp-f-at-integr-serie-

Question Number 35235 by abdo.msup.com last updated on 17/May/18 $${let}\:{f}\left({x}\right)=\:{e}^{−\mathrm{2}{x}} \:{arctanx} \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:{f}^{\left({n}\right)} \left({x}\right) \\ $$$$\left.\mathrm{2}\right)\:{find}\:{f}^{\left({n}\right)} \left(\mathrm{0}\right) \\ $$$$\left.\mathrm{3}\right)\:{developp}\:{f}\:{at}\:{integr}\:{serie} \\ $$ Commented by abdo mathsup…