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Category: Relation and Functions

let-give-a-sequence-of-real-numbets-positif-a-i-1-i-n-1-prove-that-i-1-n-a-i-2-n-i-1-n-a-i-2-2-let-put-H-n-k-1-n-1-k-and-w-n-H-n-2-n-prove-that-the-sequence-

Question Number 33847 by prof Abdo imad last updated on 26/Apr/18 $$\:{let}\:{give}\:{a}\:{sequence}\:{of}\:{real}\:{numbets}\:{positif} \\ $$$$\left({a}_{{i}} \right)_{\mathrm{1}\leqslant{i}\leqslant{n}} \\ $$$$\left.\mathrm{1}\right)\:{prove}\:{that}\:\left(\sum_{{i}=\mathrm{1}} ^{{n}} \:{a}_{{i}} \right)^{\mathrm{2}} \leqslant\:{n}\:\sum_{{i}=\mathrm{1}} ^{{n}} \:{a}_{{i}} ^{\mathrm{2}} \\…

Let-f-R-1-be-defined-as-f-x-log-10-3x-2-4x-k-1-10-If-f-x-is-surjective-then-find-the-value-of-k-

Question Number 33818 by rahul 19 last updated on 25/Apr/18 $$\boldsymbol{{L}}{et}\:{f}:\boldsymbol{{R}}\:\rightarrow\:\left[\:\mathrm{1},\:\infty\right)\:{be}\:{defined}\:{as}\: \\ $$$${f}\left({x}\right)\:=\:\mathrm{log}_{\mathrm{10}} \:\left(\sqrt{\mathrm{3}{x}^{\mathrm{2}} −\mathrm{4}{x}+\boldsymbol{{k}}+\mathrm{1}}\:+\mathrm{10}\:\right). \\ $$$$\boldsymbol{{I}}{f}\:{f}\left({x}\right)\:{is}\:\boldsymbol{{surjective}}\:,\:{then}\:{find} \\ $$$${the}\:{value}\:{of}\:\boldsymbol{{k}}\:? \\ $$ Answered by MJS last…

Let-f-D-R-be-defined-as-f-x-x-2-2x-a-x-2-4x-3a-where-D-and-R-denote-the-domain-of-f-and-the-set-of-all-real-numbers-respectively-If-f-is-surjective-mapping-then-the-range-of-a-is

Question Number 33815 by rahul 19 last updated on 25/Apr/18 $$\boldsymbol{{L}}{et}\:{f}:{D}\:\rightarrow\:\boldsymbol{{R}}\:{be}\:{defined}\:{as}\: \\ $$$${f}\left({x}\right)\:=\:\frac{{x}^{\mathrm{2}} +\mathrm{2}{x}+{a}}{{x}^{\mathrm{2}} +\mathrm{4}{x}+\mathrm{3}{a}}\:{where}\:{D}\:{and}\:{R} \\ $$$${denote}\:{the}\:{domain}\:{of}\:\boldsymbol{{f}}\:{and}\:{the}\:{set} \\ $$$${of}\:{all}\:{real}\:{numbers}\:{respectively}. \\ $$$${If}\:{f}\:{is}\:''\:{surjective}\:''\:\:{mapping}\:{then} \\ $$$${the}\:{range}\:{of}\:\boldsymbol{{a}}\:{is}\:? \\ $$$$\left.{a}\right)\:\mathrm{0}\leqslant{a}\leqslant\mathrm{1}…

Question-164874

Question Number 164874 by cortano1 last updated on 22/Jan/22 Answered by mahdipoor last updated on 22/Jan/22 $${get}\:{x}+\sqrt{{x}^{\mathrm{2}} +\mathrm{1}}={t}\:\Rightarrow\:{x}^{\mathrm{2}} +\mathrm{1}={t}^{\mathrm{2}} +{x}^{\mathrm{2}} −\mathrm{2}{xt} \\ $$$$\Rightarrow\:\frac{{t}^{\mathrm{2}} −\mathrm{1}}{\mathrm{2}{t}}={x} \\…

simplify-S-n-x-1-x-2-1-x-4-1-x-2-n-2-find-lim-n-S-n-x-if-x-lt-1-

Question Number 33719 by prof Abdo imad last updated on 22/Apr/18 $${simplify}\:{S}_{{n}} \left({x}\right)\:=\left(\mathrm{1}+{x}^{\mathrm{2}} \right)\left(\mathrm{1}+{x}^{\mathrm{4}} \right)….\left(\mathrm{1}+{x}^{\mathrm{2}^{{n}} } \right) \\ $$$$\left.\mathrm{2}\right)\:{find}\:{lim}_{{n}\rightarrow+\infty} \:{S}_{{n}} \left({x}\right)\:{if}\:\mid{x}\mid<\mathrm{1}\:. \\ $$ Commented by…

find-n-1-arctan-ln-1-1-n-1-ln-1-1-n-1-1-1-n-1-1-n-1-

Question Number 33718 by prof Abdo imad last updated on 22/Apr/18 $${find}\:\:\sum_{{n}=\mathrm{1}} ^{+\infty} {arctan}\left(\:\frac{{ln}\left(\mathrm{1}+\frac{\mathrm{1}}{{n}+\mathrm{1}}\right)\:−{ln}\left(\mathrm{1}+\frac{\mathrm{1}}{{n}}\right)}{\mathrm{1}+\left(\mathrm{1}\:+\frac{\mathrm{1}}{{n}}\right)\left(\mathrm{1}+\frac{\mathrm{1}}{\left.{n}+\mathrm{1}\right)}\right.}\right) \\ $$ Commented by prof Abdo imad last updated on 26/Apr/18…