Question Number 33072 by prof Abdo imad last updated on 10/Apr/18 $${find}\:\:\sum_{{k}=\mathrm{0}} ^{{n}} \:{k}\:{C}_{{n}} ^{{k}} \:. \\ $$ Commented by abdo imad last updated on…
Question Number 33048 by rahul 19 last updated on 09/Apr/18 $${Let}\:{f}:{N}\rightarrow{R}\:{be}\:{a}\:{function}\:{sarisfying} \\ $$$${following}\:{conditions}: \\ $$$${f}\left(\mathrm{1}\right)=\mathrm{1}. \\ $$$${f}\left(\mathrm{1}\right)+\mathrm{2}{f}\left(\mathrm{2}\right)+….+{nf}\left({n}\right)={n}\left({n}+\mathrm{1}\right){f}\left({n}\right). \\ $$$${Then}\:{find}\:{the}\:{value}\:{of}\:\mathrm{49}{f}\left(\mathrm{49}\right)\:? \\ $$ Commented by rahul 19…
Question Number 33036 by rahul 19 last updated on 09/Apr/18 $${If}\:{range}\:{of}\: \\ $$$${f}\left({x}\right)=\:\left({x}+\mathrm{1}\right)\left({x}+\mathrm{2}\right)\left({x}+\mathrm{3}\right)\left({x}+\mathrm{4}\right)+\mathrm{5} \\ $$$${x}\in\:\left[−\mathrm{6},\mathrm{6}\right]\:{is}\:\left[{a},{b}\right]\:,{a},{b}\in{N},\:{find}\:{a}+{b}\:? \\ $$ Answered by MJS last updated on 09/Apr/18 $$\mathrm{we}\:\mathrm{need}\:\mathrm{the}\:\mathrm{minimum}\:\mathrm{and}…
Question Number 98535 by bobhans last updated on 14/Jun/20 $${f}\left({x}\right)\:=\:\mathrm{log}\:_{\mathrm{5}} \left({x}\right)\:+\:\mathrm{5}{e}^{\mathrm{3}{x}} \\ $$$${f}^{−\mathrm{1}} \left({x}\right)\:=\:? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 32998 by abdo imad last updated on 09/Apr/18 $${calculate}\:\:\sum_{{n}=\mathrm{1}} ^{\infty} \:\:\:\:\frac{\mathrm{4}{n}+\mathrm{1}}{{n}^{\mathrm{2}} \left(\mathrm{3}{n}+\mathrm{1}\right)^{\mathrm{2}} }\:\:. \\ $$ Commented by abdo imad last updated on 15/Apr/18…
Question Number 32996 by abdo imad last updated on 09/Apr/18 $${find}\:{the}\:{sequence}\:\left({v}_{{n}} \right)\:{wich}\:{verify}\:\:{v}_{{n}+\mathrm{2}} \:=\sqrt{{v}_{{n}} \:.{v}_{{n}+\mathrm{1}} }\:. \\ $$ Commented by prof Abdo imad last updated on…
Question Number 32997 by abdo imad last updated on 09/Apr/18 $${calculate}\:\sum_{{n}=\mathrm{0}} ^{\infty} \:\:\:\frac{\mathrm{2}{n}+\mathrm{3}}{\left({n}+\mathrm{1}\right)^{\mathrm{2}} \left({n}+\mathrm{2}\right)^{\mathrm{2}} } \\ $$ Commented by abdo imad last updated on 10/Apr/18…
Question Number 32995 by abdo imad last updated on 09/Apr/18 $${let}\:{u}_{\mathrm{0}} ={a}\:,\:{u}_{\mathrm{1}} ={b}\:{and}\:{u}_{{n}+\mathrm{2}} =\frac{\mathrm{1}}{\mathrm{2}}\left({u}_{{n}} \:+{u}_{{n}+\mathrm{1}} \right) \\ $$$$\left.\mathrm{1}\right)\:{find}\:{u}_{{n}} \:{interms}\:{of}\:{n} \\ $$$$\left.\mathrm{2}\right)\:{find}\:{lim}_{{n}\rightarrow\infty} \:{u}_{{n}} \:\:{if}\:{a}=\mathrm{0} \\ $$$$…
Question Number 32989 by abdo imad last updated on 09/Apr/18 $${let}\:{give}\:{f}\left({x}\right)=\frac{\sqrt{\mathrm{2}+{x}}\:−\sqrt{\mathrm{2}−{x}}\:}{{x}} \\ $$$${find}\:{f}^{−\mathrm{1}} \left({x}\right)\:{and}\:{calculate}\:\left({f}^{−\mathrm{1}} \left({x}\right)\right)^{'} \:\:. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 32990 by abdo imad last updated on 09/Apr/18 $$\:\:{find}\:{lim}_{{x}\rightarrow\mathrm{0}^{+} } \:\:{x}\:{e}^{−{lnx}} \:\:. \\ $$ Commented by prof Abdo imad last updated on 09/Apr/18…