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Category: Set Theory

Question-161439

Question Number 161439 by amin96 last updated on 17/Dec/21 Commented by bobhans last updated on 18/Dec/21 (Q2)y=xψx25x+6yx25yx+6y=xψyx2(5y+1)x+(6y+ψ)=0$$\:\bigtriangleup\geqslant\mathrm{0}\:\Rightarrow\mathrm{25y}^{\mathrm{2}} +\mathrm{10y}+\mathrm{1}−\mathrm{4y}\left(\mathrm{6y}+\psi\right)\geqslant\mathrm{0}…

If-n-A-15-and-n-B-25-a-What-are-the-greatest-and-least-values-of-n-AuB-b-What-are-the-greatest-and-least-value-of-n-AnB-c-Draw-Venn-diagrams-to-illustrate-the-four-situations-in-

Question Number 28806 by pieroo last updated on 30/Jan/18 Ifn(A)=15andn(B)=25,(a)Whatarethegreatestandleastvaluesofn(AuB)?(b)Whatarethegreatestandleastvalueofn(AnB)?(c)DrawVenndiagramstoillustratethefoursituationsin(a)and(b)above Answered by Rasheed.Sindhi last updated…

Let-be-the-binary-operation-on-N-given-by-a-b-L-C-M-of-a-and-b-Find-i-5-7-20-16-ii-is-communitative-iii-is-associative-iv-Find-the-identity-of-in-N-v-which-elements-of-N-are-

Question Number 93950 by oustmuchiya@gmail.com last updated on 16/May/20 LetbethebinaryoperationonNgivenbyab=L.C.M.ofaandb.Find(i)57,2016(ii)iscommunitative?(iii)isassociative?(iv)FindtheidentityofinN(v)whichelementsofNareinvertiblefortheoperation? Answered…

Let-be-the-binary-operation-on-the-set-1-2-3-4-5-defined-by-a-b-H-C-Fof-a-and-b-Is-the-operation-same-as-the-operation-defined-above-justify-your-answer-

Question Number 93933 by oustmuchiya@gmail.com last updated on 16/May/20 Letbethebinaryoperationontheset{1,2,3,4,5}definedbyab=H.C.Fofaandb.Istheoperationsameastheoperationdefinedabove?justifyyouranswer. Commented by Rasheed.Sindhi last updated on 16/May/20 Operationisdefinedinthe$${question}.{What}\:{do}\:{you}\:{mean}\:{by} \

Given-a-1-a-2-a-n-are-non-negative-integers-and-satisfy-1-2-a-1-1-2-a-2-1-2-a-n-1-3-a-1-2-3-a-2-n-3-a-n-1-If-n-is-positive-integer-find-all-

Question Number 25723 by Joel578 last updated on 13/Dec/17 Givena1,a2,,anarenonnegativeintegersandsatisfy$$\frac{\mathrm{1}}{\mathrm{2}^{{a}_{\mathrm{1}} } }\:+\:\frac{\mathrm{1}}{\mathrm{2}^{{a}_{\mathrm{2}} } }\:+\:…\:+\:\frac{\mathrm{1}}{\mathrm{2}^{{a}_{{n}} } }\:=\:\frac{\mathrm{1}}{\mathrm{3}^{{a}_{\mathrm{1}} } }\:+\:\frac{\mathrm{2}}{\mathrm{3}^{{a}_{\mathrm{2}}…