Category: Set Theory

Question Number 148397 by nadovic last updated on 27/Jul/21 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 14028 by tawa tawa last updated on 26/May/17 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 13200 by Joel577 last updated on 16/May/17 $$\sqrt[\sqrt[\sqrt[\sqrt{3}]{2}]{5}]{6}=x$$$$\mathrm{How}\mathrm{to}\mathrm{write}x\mathrm{in}\mathrm{standard}\mathrm{form}?$$ Answered by ajfour last updated on 16/May/17 $${x}=\mathrm{6}^{\left[\frac{\mathrm{1}}{\mathrm{5}^{\left(\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{1}/\sqrt{\mathrm{3}}} }\right)} }\right]} \:…

Question Number 242 by 123456 last updated on 25/Jan/15 $$\mathrm{give}\mathrm{the}\mathrm{sets}$$$$\mathrm{A}=\{x\in \mathbb{N}:0⩽x⩽9\}$$$$\mathrm{B}=\left\{0\right\}$$$$\mathrm{C}=\left\{1\right\}$$$$\mathrm{D}=\{2,3,5,7\}$$$$\mathrm{E}=\{4,6,8,9\}$$$$\mathrm{compute}$$$$\mid\mathrm{A}\backslash\mathrm{B}\mid+\mid\mathrm{A}\backslash\mathrm{C}\mid+\mid\mathrm{A}\backslash\mathrm{D}\mid+\mid\mathrm{A}\backslash\mathrm{E}\mid \…

Question Number 12291 by 1kanika# last updated on 18/Apr/17 Answered by 433 last updated on 07/May/17 $$\left[\begin{array}{cc}0& 1\\ 1& 0\end{array}\right]\times \left[\begin{array}{cc}0& -1\\ 1& 0\end{array}\right]=\left[\begin{array}{cc}1& 0\\ 0& -1\end{array}\right]=A$$$$\left[\begin{array}{cc}0& -1\\ 1& 0\end{array}\right]\times \left[\begin{array}{cc}0& 1\\ 1& 0\end{array}\right]=\left[\begin{array}{cc}-1& 0\\ 0& 1\end{array}\right]=-A$$$$\left[\begin{array}{cc}0& -1\\ 1& 0\end{array}\right]\times \left[\begin{array}{cc}0& -1\\ 1& 0\end{array}\right]=\left[\begin{array}{cc}-1& 0\\ 0& -1\end{array}\right]=-I_2$$$$$$\left[\begin{array}{cc}0& 1\\ 1& 0\end{array}\right]$$^{\mathrm{2}} ={I}_{\mathrm{2}} \…