Question Number 1875 by Filup last updated on 20/Oct/15 $$\mathrm{Given}\:\mathrm{that}: \\ $$$${Z}=\left\{\mathrm{0},\:\mathrm{1},\:\mathrm{2},\:…\right\}\:\mathrm{all}\:\mathrm{integers}\:\geqslant\mathrm{0} \\ $$$${R}=\left\{\mathrm{0},\:\mathrm{0}.\mathrm{01},\:…,\:\mathrm{1},\:\mathrm{1}.\mathrm{01},\:…\right\}\:\mathrm{all}\:\mathrm{reals}\:\geqslant\mathrm{0} \\ $$$$\:\mathrm{Prove}\:\mathrm{that}\:\mid{R}\mid>\mid{Z}\mid \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 1763 by Gerlândio Almeida last updated on 18/Sep/15 $$ \\ $$ Commented by 123456 last updated on 18/Sep/15 $${p}_{\mathrm{0}} \left({n}\right)={xn} \\ $$$${r}\left({n}\right)=\alpha{xn} \\…
Question Number 1744 by Rasheed Ahmad last updated on 13/Sep/15 $${If}\:\boldsymbol{\mathrm{A}}\:{and}\:\boldsymbol{\mathrm{B}}\:{are}\:{two}\:{sets}\:{and}\:\mathbb{U}\:{is} \\ $$$${a}\:{universal}\:{set}\:{prove}\:{that} \\ $$$$\boldsymbol{\mathrm{A}}\:\subseteq\:\boldsymbol{\mathrm{B}}\:\:\Rightarrow\:\boldsymbol{\mathrm{B}}=\boldsymbol{\mathrm{A}}\:\cup\:\left(\boldsymbol{\mathrm{A}}'\:\cap\:\boldsymbol{\mathrm{B}}\right) \\ $$ Answered by Rasheed Ahmad last updated on 19/Sep/15…
Question Number 1698 by Rasheed Ahmad last updated on 01/Sep/15 $$\bullet{Are}\:\boldsymbol{\mathrm{A}}\cup\boldsymbol{\mathrm{B}}=\boldsymbol{\mathrm{A}}\cap\boldsymbol{\mathrm{B}}\:\:{and}\:\:\boldsymbol{\mathrm{A}}=\boldsymbol{\mathrm{B}}\: \\ $$$${completely}\:{equivalent}? \\ $$$$\bullet{Simplify}\:\boldsymbol{\mathrm{A}}\cup\boldsymbol{\mathrm{B}}=\boldsymbol{\mathrm{A}}\cap\boldsymbol{\mathrm{B}}\:{to}\:\boldsymbol{\mathrm{A}}=\boldsymbol{\mathrm{B}} \\ $$$${using}\:{set}\:{operations}\:{and}\:{their} \\ $$$${properties}. \\ $$ Answered by 123456 last…
Question Number 1694 by 123456 last updated on 01/Sep/15 $$\mathrm{proof}\:\mathrm{that}\:\mathrm{for}\:\mathrm{two}\:\mathrm{set}\:\mathrm{A}\:\mathrm{and}\:\mathrm{B}\:\left(\mathrm{or}\:\mathrm{give}\:\mathrm{a}\:\mathrm{counter}\:\mathrm{example}\right) \\ $$$$\mid\mathrm{A}\cup\mathrm{B}\mid\geqslant\mid\mathrm{A}\cap\mathrm{B}\mid \\ $$ Answered by Rasheed Soomro last updated on 01/Sep/15 $$\:\mathrm{In}\:\mathrm{the}\:\mathrm{following}\:\boldsymbol{\mathrm{A}}\:\mathrm{and}\:\boldsymbol{\mathrm{B}}\:\mathrm{are}\:\mathrm{assumed}\:\mathrm{as}\:\mathrm{finite}\:\mathrm{sets}. \\ $$$$\:\boldsymbol{\mathrm{A}}\cap\boldsymbol{\mathrm{B}}\:\subseteq\boldsymbol{\mathrm{A}}\subseteq\:\boldsymbol{\mathrm{A}}\cup\boldsymbol{\mathrm{B}}\Rightarrow\mid\boldsymbol{\mathrm{A}}\cap\boldsymbol{\mathrm{B}}\mid\leqslant\mid\boldsymbol{\mathrm{A}}\mid\leqslant\mid\boldsymbol{\mathrm{A}}\cup\boldsymbol{\mathrm{B}}\mid………..\boldsymbol{\mathrm{I}}…
Question Number 1682 by Rasheed Soomro last updated on 31/Aug/15 $${Let}\:\mid\:\mathrm{S}\:\mid\:{denotes}\:{number}\:{of}\:{elements}\:{in}\:{a}\:{set}\:\mathrm{S}\:,\: \\ $$$$\mathbb{N}\:{and}\:\mathbb{R}\:{are}\:{sets}\:{of}\:{natural}\:{and}\:{real}\:{numbers}\: \\ $$$${respectively}: \\ $$$$\mid\:\mathbb{N}\:\mid\overset{?} {=}\mid\:\mathbb{R}\:\mid \\ $$ Commented by 112358 last updated…
Question Number 1672 by 123456 last updated on 30/Aug/15 $$\mathrm{lets}\:\mathrm{A}\:\mathrm{and}\:\mathrm{B}\:\mathrm{be}\:\mathrm{two}\:\mathrm{finite}\:\mathrm{sets},\:\mathrm{proof}\:\left(\mathrm{or}\:\mathrm{give}\:\mathrm{a}\:\mathrm{counter}\:\mathrm{example}\right)\:\mathrm{that} \\ $$$$\mid\mathrm{A}\cup\mathrm{B}\mid\leqslant\mid\mathrm{A}\cap\mathrm{B}\mid\:\Rightarrow\:\mathrm{A}=\mathrm{B} \\ $$ Answered by Rasheed Soomro last updated on 01/Sep/15 $$\boldsymbol{\mathrm{Case}}−\mathrm{1}\:\boldsymbol{\mathrm{W}}\mathrm{hen}\:\boldsymbol{\mathrm{A}}\cap\boldsymbol{\mathrm{B}}=\varnothing\:,\:\mid\:\boldsymbol{\mathrm{A}}\cap\boldsymbol{\mathrm{B}}\:\mid=\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\boldsymbol{\mathrm{SubCase}}\:\:\left(\boldsymbol{\mathrm{a}}\right)\:\boldsymbol{\mathrm{At}}\:\boldsymbol{\mathrm{least}}\:\boldsymbol{\mathrm{one}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{A}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{B}}\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{nonempty}}.…
Question Number 1616 by 123456 last updated on 27/Aug/15 $$\mathrm{lets}\:\mathrm{two}\:\mathrm{sets}\:\mathrm{A},\mathrm{B}\:\mathrm{and}\:\mathrm{take}\:\mid\mathrm{X}\mid\:\mathrm{the}\:\mathrm{number} \\ $$$$\mathrm{of}\:\mathrm{elements}\:\mathrm{of}\:\mathrm{the}\:\mathrm{set}\:\mathrm{X},\:\mathrm{them} \\ $$$$\mathrm{proof}\:\mathrm{or}\:\mathrm{give}\:\mathrm{a}\:\mathrm{counter}\:\mathrm{example}\:\mathrm{that} \\ $$$$\mathrm{if}\:\mid\mathrm{A}\cup\mathrm{B}\mid=\infty\:\mathrm{and}\:\mid\mathrm{A}\cap\mathrm{B}\mid=\infty\:\mathrm{then}\:\mid\mathrm{A}\mid=\infty\:\mathrm{and}\:\mid\mathrm{B}\mid=\infty \\ $$ Commented by 112358 last updated on 27/Aug/15…
Question Number 1132 by 123456 last updated on 24/Jun/15 $$\mathrm{let}\:\mathrm{S}=\left\{\mathrm{1},\mathrm{2},\mathrm{3},\mathrm{4},\mathrm{5}\right\},\:\mathrm{if}\:\mathrm{A},\mathrm{B},\mathrm{C}\:\mathrm{is}\:\mathrm{such}\:\mathrm{that} \\ $$$$\mathrm{A}\cap\mathrm{B}\cap\mathrm{C}=\varnothing \\ $$$$\mathrm{A}\cap\mathrm{B}\neq\varnothing \\ $$$$\mathrm{A}\cap\mathrm{C}\neq\varnothing \\ $$$$\mathrm{how}\:\mathrm{many}\:\mathrm{ways}\:\mathrm{can}\:\mathrm{be}\:\mathrm{choose}\:\mathrm{A},\mathrm{B}\:\mathrm{and} \\ $$$$\mathrm{C} \\ $$ Commented by Faaiz…