Menu Close

Category: Set Theory

Question-207864

Question Number 207864 by efronzo1 last updated on 29/May/24 Answered by Rasheed.Sindhi last updated on 29/May/24 $$\mathrm{2}^{\mathrm{5}{m}} \centerdot\mathrm{5}^{\mathrm{2}{n}} \centerdot{k}=\mathrm{2020}^{\mathrm{2020}} =\left(\mathrm{2}^{\mathrm{2}} .\mathrm{5}.\mathrm{101}\right)^{\mathrm{2020}} \

1-3-5-7-9-2005-mod-1000-

Question Number 203490 by cortano12 last updated on 20/Jan/24 1×3×5×7×9××2005=(mod1000) Answered by AST last updated on 20/Jan/24 x=1×3×5×20050(mod125)x(1×3×5×7)250×1×3×5(mod8)7(mod8)$${x}=\mathrm{125}{q}\equiv\mathrm{7}\left({mod}\:\mathrm{8}\right)\Rightarrow\mathrm{5}{q}\equiv\mathrm{15}\left({mod}\:\mathrm{8}\right)\Rightarrow{q}\equiv\mathrm{3}\left({mod}\:\mathrm{8}\right)…