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Question Number 104544 by john santu last updated on 22/Jul/20 $$\mathcal{G}{iven}\:{a}_{{n}+\mathrm{1}} \:=\:\mathrm{5}{a}_{{n}} −\mathrm{6}{a}_{{n}−\mathrm{1}} \\ $$$$.\mathcal{I}{f}\:{a}_{\mathrm{1}} =\:\mathrm{10}\:{and}\:{a}_{\mathrm{2}} =\:\mathrm{26},\:{find}\:{a}_{{n}} ? \\ $$ Answered by bobhans last updated…
Question Number 168480 by amin96 last updated on 11/Apr/22 $$\boldsymbol{\mathrm{n}}^{\mathrm{2}} +\boldsymbol{\mathrm{n}}+\mathrm{109}=\boldsymbol{\mathrm{x}}^{\mathrm{2}} \\ $$$$\boldsymbol{\mathrm{x}}−\boldsymbol{\mathrm{integer}} \\ $$$$\boldsymbol{\mathrm{positive}}\:\boldsymbol{\mathrm{integer}}\:\boldsymbol{\mathrm{solutions}}\:\boldsymbol{\mathrm{n}}=? \\ $$ Commented by Rasheed.Sindhi last updated on 11/Apr/22 $$\mathrm{n}=\mathrm{3},\mathrm{20},\mathrm{35},……
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Question Number 102357 by Cynosure last updated on 08/Jul/20 $${for}\:{A}=\left\{\mathrm{1},\mathrm{2},\mathrm{3},\mathrm{4},\mathrm{5},\mathrm{6},\mathrm{7}\right\},{compute}\:{the}\:{number}\:{of}: \\ $$$$\left({a}\right)\:{Subsets}\:{of}\:{A}. \\ $$$$\left({b}\right)\:{Nonempty}\:{subsets}\:{of}\:{A}. \\ $$$$\left({c}\right)\:{proper}\:{subsets}\:{of}\:{A}. \\ $$$$\left({d}\right)\:{Non}\:{empty}\:{proper}\:{subset}\:{of}\:{A}. \\ $$$$\left({e}\right)\:{Subsets}\:{of}\:{A}\:{containing}\:{three}\:{element}. \\ $$$$\left({f}\right)\:{Subsets}\:{of}\:{A}\:{containing}\:\mathrm{1},\mathrm{2}. \\ $$$$\left({g}\right)\:{Proper}\:{subsets}\:{of}\:{A}\:{containing}\:\mathrm{1},\mathrm{2}. \\…
Question Number 101891 by bobhans last updated on 05/Jul/20 $${if}\:{x}\:{a}\:{integer}\:{number}\:,\:{when}\:{divided}\:\mathrm{8} \\ $$$${has}\:{remainder}\:\mathrm{5}\:{and}\:{divided}\:\mathrm{5}\:{has}\:{remainder} \\ $$$$\mathrm{2}.\:{find}\:{x} \\ $$ Answered by Rasheed.Sindhi last updated on 05/Jul/20 $$\mathrm{8}−\mathrm{5}=\mathrm{5}−\mathrm{2}=\mathrm{3} \\…
Question Number 36061 by Raj Singh last updated on 28/May/18 Commented by Rasheed.Sindhi last updated on 28/May/18 $$\mathcal{N}{ot}\:{related}\:{to}\:{the}\:{above}\:{question}. \\ $$$$\mathcal{D}\mathrm{ear}\:\mathrm{Abu}\:\mathrm{behi}, \\ $$$$\mathcal{I}\:'\mathrm{ve}\:\mathrm{discovered}\:\mathrm{relation}\:\mathrm{between}\:\mathrm{your} \\ $$$$\mathrm{questions}\:#\mathrm{35844}\:\&\:#\mathrm{35892}. \\…
Question Number 35703 by scientist last updated on 22/May/18 Answered by arcana last updated on 17/Oct/18 $$\mathrm{tomando}\:\mathrm{la}\:\mathrm{propiedad}\:\mathrm{de}\:\mathrm{funcion}\:\mathrm{de}\:\mathrm{medida}\:{n} \\ $$$$\mathrm{A},\mathrm{B}\:\mathrm{conjuntos}\:\mathrm{finitos} \\ $$$${n}\left(\mathrm{A}\cup\mathrm{B}\right)={n}\left(\mathrm{A}\right)+{n}\left(\mathrm{B}\right)−{n}\left(\mathrm{A}\cap\mathrm{B}\right) \\ $$$$\mathrm{asi} \\ $$$$\bullet\:{n}\left(\left(\mathrm{A}\cup\mathrm{B}\right)\cup\left(\mathrm{C}\cup\mathrm{D}\right)\right)={n}\left(\mathrm{A}\cup\mathrm{B}\right)+{n}\left(\mathrm{C}\cup\mathrm{D}\right)−{n}\left(\left(\mathrm{A}\cup\mathrm{B}\right)\cap\left(\mathrm{C}\cup\mathrm{D}\right)\right)…
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