Question Number 213887 by efronzo1 last updated on 20/Nov/24 $$\:\:\:\mathrm{Find}\:\mathrm{amplitude},\:\mathrm{period},\:\mathrm{maximum}\: \\ $$$$\:\:\mathrm{and}\:\mathrm{minimum}\:\mathrm{value}\:\mathrm{for}\:\mathrm{function} \\ $$$$\:\:\mathrm{f}\left(\mathrm{x}\right)=\:\mathrm{6}\:\mathrm{tan}\:\left(\frac{\mathrm{1}}{\mathrm{5}}\mathrm{x}\right)−\mathrm{8}\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 213861 by BaliramKumar last updated on 19/Nov/24 Answered by A5T last updated on 19/Nov/24 $${cotA}+{cotB}=\frac{\mathrm{1}}{{tanA}}+\frac{\mathrm{1}}{{tanB}}=\frac{{p}}{{tanAtanB}}={q} \\ $$$$\Rightarrow{tanAtanB}=\frac{{p}}{{q}} \\ $$$${cot}\left({A}+{B}\right)=\frac{\mathrm{1}}{{tan}\left({A}+{B}\right)}=\frac{\mathrm{1}−{tanAtanB}}{{tanA}+{tanB}}=\frac{\mathrm{1}−\frac{{p}}{{q}}}{{p}} \\ $$$$\Rightarrow{cot}\left({A}+{B}\right)=\frac{{q}−{p}}{{pq}} \\ $$…
Question Number 213741 by bourasi last updated on 15/Nov/24 $$\sqrt{\mathrm{1}−\mathrm{sin}} \\ $$ Commented by Frix last updated on 15/Nov/24 $$\mathrm{Is}\:\mathrm{sin}\:\mathrm{a}\:\mathrm{variable}\:\mathrm{name}\:\mathrm{or}\:\mathrm{s}×\mathrm{i}×\mathrm{n}? \\ $$$$\mathrm{In}\:\mathrm{the}\:\mathrm{2}^{\mathrm{nd}} \:\mathrm{case},\:\mathrm{is}\:\mathrm{i}=\sqrt{−\mathrm{1}}? \\ $$…
Question Number 213643 by Abdullahrussell last updated on 12/Nov/24 $$\:{Find}\:{the}\:{maximum}\:{value}\:{of} \\ $$$$\:\mathrm{3}{sin}^{\mathrm{2}} {x}−\mathrm{8}{cosx}+\mathrm{5}=? \\ $$ Answered by Berbere last updated on 12/Nov/24 $${sin}^{\mathrm{2}} \left({x}\right)=\mathrm{1}−{cos}^{\mathrm{2}} \left({x}\right)…
Question Number 213606 by CrispyXYZ last updated on 10/Nov/24 $$\bigtriangleup{ABC}.\:\mathrm{2}{a}+{b}=\mathrm{2}{c}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{minimum}\:\mathrm{of} \\ $$$$\frac{\mathrm{3}}{\mathrm{sin}\:{C}}\:+\:\frac{\mathrm{1}}{\mathrm{tan}\:{A}}. \\ $$ Answered by Ghisom last updated on 10/Nov/24 $$\mathrm{wlog}\:{b}=\mathrm{1}\:\Rightarrow\:{c}={a}+\frac{\mathrm{1}}{\mathrm{2}} \\ $$$${a}^{\mathrm{2}} +{b}^{\mathrm{2}}…
Question Number 213519 by RojaTaniya last updated on 07/Nov/24 Answered by mr W last updated on 07/Nov/24 $$\mathrm{tan}\:\alpha=\frac{\mathrm{1}}{{x}} \\ $$$$\mathrm{tan}\:\left(\alpha+\beta\right)=\frac{\mathrm{3}}{{x}} \\ $$$$\mathrm{tan}\:\left(\alpha+\alpha+\beta\right)=\frac{\mathrm{6}}{{x}} \\ $$$$\frac{\mathrm{6}}{{x}}=\frac{\frac{\mathrm{1}}{{x}}+\frac{\mathrm{3}}{{x}}}{\mathrm{1}−\frac{\mathrm{1}}{{x}}×\frac{\mathrm{3}}{{x}}}=\frac{\mathrm{4}{x}}{{x}^{\mathrm{2}} −\mathrm{3}}…
Question Number 213504 by Spillover last updated on 06/Nov/24 Answered by A5T last updated on 06/Nov/24 $${psin}^{\mathrm{2}} {x}−{q}\left(\mathrm{1}−{sin}^{\mathrm{2}} {x}\right)={p}−{q} \\ $$$${psin}^{\mathrm{2}} {x}−{q}+{qsin}^{\mathrm{2}} {x}={p}−{q} \\ $$$${sin}^{\mathrm{2}}…
Question Number 213084 by MATHEMATICSAM last updated on 30/Oct/24 $$\mathrm{If}\:\mathrm{0}\:<\:{x}\:<\:\frac{\pi}{\mathrm{2}}\:\mathrm{then}\:\mathrm{prove} \\ $$$$\mathrm{sin}\left(\mathrm{cos}{x}\right)\:<\:\mathrm{cos}{x}\:<\:\mathrm{cos}\left(\mathrm{sin}{x}\right). \\ $$$$\mathrm{not}\:\mathrm{using}\:\mathrm{graph}. \\ $$ Answered by issac last updated on 30/Oct/24 $${x}=\mathrm{acos}\left({z}\right)\:,\:{z}\in\left[\mathrm{0},\mathrm{1}\right] \\…
Question Number 213119 by a.lgnaoui last updated on 30/Oct/24 $$\mathrm{determiner}\:\boldsymbol{\mathrm{a}}\:\mathrm{et}\:\boldsymbol{\mathrm{b}}\:\mathrm{par}\:\:\:;\:\:\mathrm{AB}\:\bot\mathrm{BC} \\ $$$$\begin{cases}{\mathrm{AM}\:=\mathrm{5}}\\{\mathrm{AC}\:\:=\mathrm{16}}\end{cases} \\ $$ Commented by a.lgnaoui last updated on 30/Oct/24 Answered by A5T last…
Question Number 213054 by 281981 last updated on 29/Oct/24 Commented by Ghisom last updated on 30/Oct/24 $$\mathrm{in}\:\mathrm{an}\:\mathrm{equilateral}\:\mathrm{triangle}\:\mathrm{the}\:\mathrm{ratio}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{areas}\:\mathrm{of}\:\mathrm{the}\:\mathrm{triangle}\:\mathrm{and}\:\mathrm{its}\:\mathrm{circumcircle} \\ $$$$\mathrm{is} \\ $$$$\mathrm{1}:\frac{\mathrm{4}\pi\sqrt{\mathrm{3}}}{\:\mathrm{9}}\:\approx\:\mathrm{1}:\mathrm{2}.\mathrm{4} \\ $$$$\mathrm{here}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{circumcircle}\:\mathrm{is}…