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Category: Trigonometry

Question-34115

Question Number 34115 by tanmay.chaudhury50@gmail.com last updated on 30/Apr/18 Commented by abdo mathsup 649 cc last updated on 03/May/18 wehaveforf(t)=arctant$${f}^{'} \left({t}\right)\:=\:\frac{\mathrm{1}}{\mathrm{1}+{t}^{\mathrm{2}} }\:\:{with}\:−\mathrm{1}<{t}<\mathrm{1}\Rightarrow{f}^{'} \left({x}\right)=\sum_{{n}=\mathrm{0}}…