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Category: Trigonometry

Question-32968

Question Number 32968 by diyatrivedi last updated on 08/Apr/18 Answered by MJS last updated on 08/Apr/18 sinαsinθ=cosα×cosθ+sinα×sinθsinα=cosα×cosθ×sinθ+sinα×sin2θsinα=cosα×sin2θ2+sinα×(1cos2θ2)$$\frac{\mathrm{sin}\:\alpha}{\mathrm{2}}=\mathrm{cos}\:\alpha×\frac{\mathrm{sin}\:\mathrm{2}\theta}{\mathrm{2}}−\mathrm{sin}\:\alpha×\frac{\mathrm{cos}\:\mathrm{2}\theta}{\mathrm{2}} \