Question Number 95495 by i jagooll last updated on 25/May/20 $$\mathrm{3cos}\:^{\mathrm{2}} {x}\:−\:\mathrm{3cos}\:{x}\:\mathrm{sin}\:{x}\:+\:\mathrm{2sin}\:{x}\:=\:\mathrm{1} \\ $$$${x}\:\in\:\left[\:\mathrm{0},\:\mathrm{2}\pi\:\right]\: \\ $$ Answered by bobhans last updated on 25/May/20 $$\mathrm{3}−\mathrm{3sin}\:^{\mathrm{2}} \mathrm{x}−\mathrm{3sin}\:\mathrm{xcos}\:\mathrm{x}\:+\mathrm{2sin}\:\mathrm{x}\:=\:\mathrm{1}…
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Question Number 29896 by ajfour last updated on 13/Feb/18 Commented by ajfour last updated on 13/Feb/18 $${At}\:{least}\:{if}\:\alpha\:=\:\beta\:=\:\gamma\:=\theta\:\left({say}\right)\:. \\ $$ Answered by mrW2 last updated on…
Question Number 95424 by john santu last updated on 25/May/20 $$\mathrm{without}\:\mathrm{calculator}\: \\ $$$$\mathrm{tan}\:^{\mathrm{2}} \mathrm{36}^{\mathrm{o}} \:×\:\mathrm{tan}\:^{\mathrm{2}} \mathrm{72}^{\mathrm{o}} \:? \\ $$ Commented by PRITHWISH SEN 2 last…
Question Number 95417 by john santu last updated on 25/May/20 $$\mathrm{find}\:\mathrm{the}\:\mathrm{solution}\:\mathrm{of}\:\mathrm{eq}\: \\ $$$$\mathrm{3cot}\:\mathrm{2x}\:+\:\mathrm{2sin}\:\mathrm{x}\:=\:\mathrm{0}\:\mathrm{for}\:\mathrm{x}\in\left[\mathrm{0},\mathrm{360}^{\mathrm{o}} \right] \\ $$ Answered by bobhans last updated on 25/May/20 Commented by…
Question Number 29848 by abdo imad last updated on 12/Feb/18 $${find}\:\:\sum_{{k}=\mathrm{0}} ^{{n}} {cos}\left({kx}\right)\:{and}\:\sum_{{k}=\mathrm{0}} ^{{n}} \:{sin}\left({kx}\right)\:. \\ $$ Commented by Tinkutara last updated on 13/Feb/18 $$\mathrm{1}+\mathrm{cos}\:{x}+\mathrm{cos}\:\mathrm{2}{x}+…+\mathrm{cos}\:{nx}…
Question Number 29847 by abdo imad last updated on 12/Feb/18 $$\left.\theta\:\in\right]\mathrm{0},\pi\left[\:\:\:{find}\:{he}\:{values}\:{of}\:\:\sum_{{n}=\mathrm{1}} ^{\infty} \:\frac{\mathrm{1}}{{n}}{cos}\left({n}\theta\right)\:{and}\right. \\ $$$$\sum_{{n}=\mathrm{1}} ^{\infty} \:\frac{\mathrm{1}}{{n}}{sin}\left({n}\theta\right)\:. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 29834 by abdo imad last updated on 12/Feb/18 $${find}\:\:\:\:\frac{\mathrm{1}}{{cos}^{\mathrm{4}} \left(\frac{\pi}{\mathrm{9}}\right)}\:+\frac{\mathrm{1}}{{cos}^{\mathrm{4}} \left(\frac{\mathrm{3}\pi}{\mathrm{9}}\right)}\:+\:\frac{\mathrm{1}}{{cos}^{\mathrm{4}} \left(\frac{\mathrm{5}\pi}{\mathrm{9}}\right)}\:+\frac{\mathrm{1}}{{cos}^{\mathrm{4}} \left(\frac{\mathrm{7}\pi}{\mathrm{9}}\right)}\:. \\ $$ Commented by MJS last updated on 14/Feb/18 $$=\mathrm{1120}\:\mathrm{but}\:\mathrm{it}\:\mathrm{takes}\:\mathrm{quite}\:\mathrm{some}…
Question Number 29833 by abdo imad last updated on 12/Feb/18 $${find}\:\:{cos}^{\mathrm{4}} \left(\frac{\pi}{\mathrm{8}}\right)\:+{cos}^{\mathrm{4}} \left(\frac{\mathrm{3}\pi}{\mathrm{8}}\right)\:+{cos}^{\mathrm{4}} \left(\frac{\mathrm{5}\pi}{\mathrm{8}}\right)\:+{cos}^{\mathrm{4}} \left(\frac{\mathrm{7}\pi}{\mathrm{8}}\right). \\ $$ Answered by MJS last updated on 14/Feb/18 $$\mathrm{cos}\left(\frac{\pi}{\mathrm{8}}\right)=−\mathrm{cos}\left(\frac{\mathrm{7}\pi}{\mathrm{8}}\right)=\frac{\sqrt{\mathrm{2}+\sqrt{\mathrm{2}}}}{\mathrm{2}}…
Question Number 29821 by Victor31926 last updated on 12/Feb/18 $$\frac{\mathrm{sin}\:\mathrm{16x}}{\mathrm{sin}\:\mathrm{x}}\:\:\:\:\:\:?\mathrm{pls}\:\mathrm{help}. \\ $$ Commented by abdo imad last updated on 13/Feb/18 $${what}\:{is}\:{the}\:{question}\:? \\ $$ Commented by…