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Category: Trigonometry

Question-95903

Question Number 95903 by 675480065 last updated on 28/May/20 Commented by PRITHWISH SEN 2 last updated on 28/May/20 $$\because\:\mathrm{x}>\mathrm{0} \\ $$$$\therefore\:\mathrm{x}^{\mathrm{2}} >\mathrm{0}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{1}+\mathrm{x}>\mathrm{1} \\ $$$$\mathrm{1}−\mathrm{x}^{\mathrm{2}} <\mathrm{1}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\therefore\:\:\frac{\mathrm{1}}{\mathrm{1}+\mathrm{x}}<\mathrm{1}…

If-y-cos-2-x-sin-4-x-for-all-values-of-x-then-prove-that-3-4-y-1-

Question Number 161396 by abdullah_ff last updated on 17/Dec/21 $$\mathrm{If}\:{y}\:=\:{cos}^{\mathrm{2}} {x}\:+\:{sin}^{\mathrm{4}} {x}\:\mathrm{for}\:\mathrm{all}\:\mathrm{values}\:\mathrm{of}\:\mathrm{x}, \\ $$$$\mathrm{then}\:\mathrm{prove}\:\mathrm{that}\: \\ $$$$\frac{\mathrm{3}}{\mathrm{4}}\:\leq\:{y}\:\leq\:\mathrm{1} \\ $$ Commented by cortano last updated on 17/Dec/21…

4sin-2pi-7-sec-pi-14-cot-pi-7-

Question Number 161254 by cortano last updated on 15/Dec/21 $$\:\frac{\mathrm{4sin}\:\left(\frac{\mathrm{2}\pi}{\mathrm{7}}\right)+\mathrm{sec}\:\left(\frac{\pi}{\mathrm{14}}\right)}{\mathrm{cot}\:\left(\frac{\pi}{\mathrm{7}}\right)}=? \\ $$ Commented by bobhans last updated on 15/Dec/21 $$\mathcal{P}\:=\:\frac{\mathrm{4sin}\:\left(\frac{\mathrm{2}\pi}{\mathrm{7}}\right)\:\mathrm{cos}\:\left(\frac{\pi}{\mathrm{14}}\right)+\mathrm{1}}{\mathrm{cos}\:\left(\frac{\pi}{\mathrm{14}}\right)\left[\frac{\mathrm{cos}\:\left(\frac{\pi}{\mathrm{7}}\right)}{\mathrm{2sin}\:\left(\frac{\pi}{\mathrm{14}}\right)\:\mathrm{cos}\:\left(\frac{\pi}{\mathrm{14}}\right)}\right]} \\ $$$$\:\mathcal{P}\:=\:\frac{\mathrm{4sin}\:\left(\frac{\mathrm{2}\pi}{\mathrm{7}}\right)\:\mathrm{sin}\:\left(\frac{\pi}{\mathrm{7}}\right)+\mathrm{2sin}\:\left(\frac{\pi}{\mathrm{14}}\right)}{\mathrm{cos}\:\left(\frac{\pi}{\mathrm{7}}\right)} \\ $$$$\:\mathcal{P}\:=\:\frac{−\mathrm{2}\left(\mathrm{cos}\:\left(\frac{\mathrm{3}\pi}{\mathrm{7}}\right)−\mathrm{cos}\:\left(\frac{\pi}{\mathrm{7}}\right)\right)+\mathrm{2cos}\:\left(\frac{\mathrm{3}\pi}{\mathrm{7}}\right)}{\mathrm{cos}\:\left(\frac{\pi}{\mathrm{7}}\right)} \\…

x-cot-1-cos-tan-1-cos-sin-x-

Question Number 161181 by cortano last updated on 13/Dec/21 $$\:\:{x}=\mathrm{cot}^{−\mathrm{1}} \left(\sqrt{\mathrm{cos}\:\theta}\right)−\mathrm{tan}^{−\mathrm{1}} \left(\sqrt{\mathrm{cos}\:\theta}\right) \\ $$$$\:\mathrm{sin}\:{x}=? \\ $$ Commented by MJS_new last updated on 13/Dec/21 $$\mathrm{sin}\:\left(\mathrm{arctan}\:{a}\:−\mathrm{arctan}\:{b}\right)\:=\frac{{a}−{b}}{\:\sqrt{\left({a}^{\mathrm{2}} +\mathrm{1}\right)\left({b}^{\mathrm{2}}…

Question-30054

Question Number 30054 by rahul 19 last updated on 15/Feb/18 Answered by ajfour last updated on 16/Feb/18 $${let}\:\:\mathrm{sin}\:{x}=\:{s} \\ $$$$\mathrm{5}{s}^{\mathrm{2}} +\mathrm{4}{s}^{\mathrm{2}} \left(\mathrm{1}−{s}^{\mathrm{2}} \right)−\mathrm{4}\left(\mathrm{1}−\mathrm{2}{s}^{\mathrm{2}} \right)\:>\:\mathrm{0} \\…

If-cos-sin-sin-sin-cos-cos-sin-sin-sin-cos-cos-sin-sin-sin-cos-then-find-cos-cos-cos-briefly-and-if-possible-linearly-in-terms-of-only-si

Question Number 30000 by ajfour last updated on 14/Feb/18 $${If}\:\mathrm{cos}\:\alpha\:=\:\mathrm{sin}\:\beta\:\mathrm{sin}\:\phi=\mathrm{sin}\:\gamma\:\mathrm{cos}\:\psi \\ $$$$\:\:\:\:\:\:\mathrm{cos}\:\beta\:=\:\mathrm{sin}\:\gamma\:\mathrm{sin}\:\psi\:=\mathrm{sin}\:\alpha\:\mathrm{cos}\:\theta \\ $$$$\:\:\:\:\:\:\mathrm{cos}\:\gamma\:=\:\mathrm{sin}\:\alpha\:\mathrm{sin}\:\theta\:=\mathrm{sin}\:\beta\:\mathrm{cos}\:\phi \\ $$$${then}\:{find}\:\:\mathrm{cos}\:\alpha,\:\mathrm{cos}\:\beta\:,\:\mathrm{cos}\:\gamma\:\:\: \\ $$$${briefly}\:{and}\:{if}\:{possible}\:{linearly} \\ $$$${in}\:{terms}\:{of}\:{only}\:\mathrm{sin}\:\theta,\:\mathrm{cos}\:\theta, \\ $$$$\mathrm{sin}\:\phi,\:\mathrm{cos}\:\phi,\:\mathrm{sin}\:\psi,\:\mathrm{cos}\:\psi\:. \\ $$ Commented…

tanx-ctg2x-tan-2-x-1-

Question Number 95531 by Abdulrahman last updated on 25/May/20 $$\frac{\mathrm{tanx}×\mathrm{ctg2x}}{\mathrm{tan}^{\mathrm{2}} \mathrm{x}−\mathrm{1}}=? \\ $$ Commented by PRITHWISH SEN 2 last updated on 25/May/20 $$\mathrm{put}\:\mathrm{cot2x}\:=\:\frac{\mathrm{1}−\mathrm{tan}\:^{\mathrm{2}} \mathrm{x}}{\mathrm{2tan}\:\mathrm{x}} \\…