Question Number 209458 by SonGoku last updated on 10/Jul/24 Commented by SonGoku last updated on 10/Jul/24 $$\mathrm{l}\:=\:?\: \\ $$$$\mathrm{BC}\:=\:\:\mathrm{l}\:+\:\mathrm{200m} \\ $$$$\mathrm{B}\hat {\mathrm{A}C}\:=\:\mathrm{120}° \\ $$$$\mathrm{A}\hat {\mathrm{B}C}\:=\:\mathrm{38}°\mathrm{12}'\mathrm{48}''…
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Question Number 209211 by SonGoku last updated on 03/Jul/24 Commented by A5T last updated on 03/Jul/24 $${AC}=\sqrt{{AB}^{\mathrm{2}} +{BC}^{\mathrm{2}} −\mathrm{2}{AB}×{BCcos}\mathrm{123}}\approx\mathrm{74}.\mathrm{738} \\ $$ Terms of Service Privacy…
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Question Number 208912 by dimentri last updated on 27/Jun/24 $$\:\:\:\underbrace{\Subset} \underbrace{ \cancel{} }\pi \\ $$ Commented by Frix last updated on 27/Jun/24 $$\mathrm{33} \\ $$…
Question Number 208755 by efronzo1 last updated on 22/Jun/24 Answered by mr W last updated on 22/Jun/24 Commented by mr W last updated on 22/Jun/24…
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Question Number 208437 by efronzo1 last updated on 16/Jun/24 Answered by som(math1967) last updated on 16/Jun/24 $$\:{a}={sin}\mathrm{84}+{cos}\mathrm{66} \\ $$$$\Rightarrow{a}={sin}\mathrm{84}+{sin}\mathrm{24} \\ $$$$\Rightarrow{a}=\mathrm{2}{sin}\mathrm{54}{cos}\mathrm{30} \\ $$$$\:\therefore{a}=\mathrm{2}×\frac{\sqrt{\mathrm{5}}+\mathrm{1}}{\mathrm{4}}×\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}=\frac{\sqrt{\mathrm{3}}\left(\sqrt{\mathrm{5}}+\mathrm{1}\right)}{\mathrm{4}} \\ $$$${b}={sin}\mathrm{48}−{sin}\mathrm{12}…