Question Number 203897 by NasaSara last updated on 01/Feb/24 Answered by AST last updated on 01/Feb/24 $${cos}^{\mathrm{2}} \left({x}\right)−{cos}\left({x}\right)=\sqrt{\mathrm{1}−{cos}^{\mathrm{2}} {x}} \\ $$$$\Rightarrow{cos}^{\mathrm{4}} \left({x}\right)+\mathrm{2}{cos}^{\mathrm{2}} \left({x}\right)−\mathrm{2}{cos}^{\mathrm{3}} \left({x}\right)−\mathrm{1}=\mathrm{0} \\…
Question Number 203704 by mnjuly1970 last updated on 26/Jan/24 $$ \\ $$$$\:\:\:\:\:{Q}:\:{In}\:{A}\overset{\Delta} {{B}C}\::\:\:\left(\:{AB}={AC}={b}\:\right)\:{and}\:\:\left(\:{BC}={a}\:\right).\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:{If}\:\:,\:\:{cos}\:\left({A}\:\right)=\:\frac{{a}^{\mathrm{2}} }{{b}^{\mathrm{2}} }\:,\:\:\:\:{then}\:{find}\:{the}\:{value}\:{of}\::\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\sqrt{\frac{{b}}{{a}}\:}\:=? \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\: \\ $$ Answered by…
Question Number 203325 by depressiveshrek last updated on 16/Jan/24 $$\mathrm{sin}^{\mathrm{2}} {x}+\mathrm{cos}^{\mathrm{2}} \left(\mathrm{2}{x}\right)+\mathrm{sin}^{\mathrm{2}} \left(\mathrm{3}{x}\right)=\frac{\mathrm{3}}{\mathrm{2}} \\ $$ Answered by esmaeil last updated on 16/Jan/24 $${sin}^{\mathrm{2}} {x}+\left(\mathrm{1}−\mathrm{2}{sin}^{\mathrm{2}} {x}\overset{\mathrm{2}}…
Question Number 203321 by SonGoku last updated on 16/Jan/24 $$\mathrm{Help}-\mathrm{me}! \\ $$$$\: \\ $$$$\mathrm{Observe}\:\mathrm{points}\:\mathrm{A},\:\mathrm{B}\:\mathrm{and}\:\mathrm{C}\:\mathrm{below}\:\mathrm{and}\:\mathrm{find}\:\mathrm{the}\:\mathrm{widthof}\:\mathrm{a}\:\mathrm{lake}\:\mathrm{according}\:\mathrm{to}\:\mathrm{the}\:\mathrm{following}\:\mathrm{data}: \\ $$$$\: \\ $$$$\left(\mathrm{AB}\right)\mathrm{m};\:\hat {\mathrm{C}}\:=\:\mathrm{39}°\mathrm{52}'\mathrm{12}'' \\ $$$$\left(\mathrm{BC}\:−\:\mathrm{257}.\mathrm{5}\right)\mathrm{m};\:\hat {\mathrm{A}}\:=\:\mathrm{97}°\mathrm{7}'\mathrm{56}'' \\ $$$$\left(\mathrm{CA}\:−\:\mathrm{30}\right)\mathrm{m};\:\hat {\mathrm{B}}\:=\:\mathrm{42}°\mathrm{59}'\mathrm{52}''…
Question Number 203277 by cortano12 last updated on 14/Jan/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 203244 by cortano12 last updated on 13/Jan/24 Answered by MathematicalUser2357 last updated on 14/Jan/24 $$\mathrm{If}\:\mathrm{you}\:\mathrm{took}\:\mathrm{that}\:\mathrm{image}\:\mathrm{on}\:\mathrm{FB}, \\ $$$$\mathrm{You}\:\mathrm{will}\:\mathrm{be}\:\mathrm{known}\:\mathrm{soon}. \\ $$$$\mathrm{Here}\:\mathrm{is}\:\mathrm{a}\:\mathrm{proof}: \\ $$ Commented by…
Question Number 203171 by a.lgnaoui last updated on 11/Jan/24 $$\mathrm{Ratio}\:\mathrm{of}\:\mathrm{green}\:\mathrm{blue}\:\mathrm{and}\:\mathrm{Red}\:\mathrm{triangles}? \\ $$$$\mathrm{Evaluate}\:\mathrm{these}\:\mathrm{Area}\:\mathrm{for}\:\boldsymbol{\alpha}=\mathrm{25}°\:\:\mathrm{and} \\ $$$$\mathrm{length}\:\mathrm{of}\:\mathrm{aquart}=\mathrm{1} \\ $$ Commented by a.lgnaoui last updated on 11/Jan/24 Commented by…
Question Number 202976 by ajfour last updated on 06/Jan/24 Commented by ajfour last updated on 06/Jan/24 $${If}\:\mathrm{tan}\:\alpha={t}\:,\:{find}\:{h}. \\ $$ Answered by mr W last updated…
Question Number 202614 by a.lgnaoui last updated on 30/Dec/23 $$\mathrm{find}\:\mathrm{x} \\ $$$$ \\ $$ Commented by a.lgnaoui last updated on 30/Dec/23 Commented by a.lgnaoui last…
Question Number 201899 by cortano12 last updated on 15/Dec/23 Terms of Service Privacy Policy Contact: info@tinkutara.com