Question Number 199723 by cortano12 last updated on 08/Nov/23 Answered by AST last updated on 08/Nov/23 $${Suppose}\:{ABCD}\:{is}\:{a}\:{square} \\ $$$${Through}\:{P},{let}\:{the}\:{line}\:{parallel}\:{to}\:{BC}\:{meet}\:{AB} \\ $$$${at}\:{F};{then}\:{PF}=\mathrm{8}\Rightarrow\frac{{sin}\left(\mathrm{2}\alpha\right)}{\mathrm{1}}=\frac{\mathrm{4}}{\mathrm{5}} \\ $$$$\Rightarrow{cos}\left(\mathrm{2}\alpha\right)=\frac{\mathrm{3}}{\mathrm{5}}=\frac{{AF}}{\mathrm{10}}\Rightarrow{AF}=\mathrm{6}\Rightarrow{PC}=\mathrm{2} \\ $$…
Question Number 199718 by cortano12 last updated on 08/Nov/23 $$\:\begin{cases}{\mathrm{cos}\:\mathrm{x}+\mathrm{cos}\:\mathrm{y}=\frac{\mathrm{1}}{\mathrm{2}}}\\{\mathrm{sin}\:\mathrm{x}+\mathrm{sin}\:\mathrm{y}=\frac{\mathrm{1}}{\mathrm{4}}}\\{\mathrm{sin}\:\mathrm{2x}\:+\:\mathrm{sin}\:\mathrm{2y}=−\frac{\mathrm{27}}{\mathrm{20}}}\end{cases} \\ $$$$\:\:\:\mathrm{sin}\:\left(\mathrm{x}+\mathrm{y}\right)\:=\:… \\ $$ Answered by Sutrisno last updated on 08/Nov/23 $$\left({cosx}+{cosy}\right)\left({sinx}+{siny}\right)=\frac{\mathrm{1}}{\mathrm{8}} \\ $$$${cosxsinx}+{cosxsiny}+{cosysinx}+{cosysiny}=\frac{\mathrm{1}}{\mathrm{8}} \\…
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Question Number 199544 by a.lgnaoui last updated on 05/Nov/23 $$\:\:\frac{\boldsymbol{\mathrm{Area}}\left(\boldsymbol{{ydllow}}\right)}{\boldsymbol{\mathrm{Area}}\left(\boldsymbol{{Blue}}\right)}=? \\ $$ Commented by a.lgnaoui last updated on 05/Nov/23 Commented by ajfour last updated on…
Question Number 199481 by tri26112004 last updated on 04/Nov/23 $${Give}\:\bigtriangleup{ABC}\:{is}\:{acute}\:{triangle}. \\ $$$${M}\:\:{is}\:{a}\:{midpoint}\:{of}\:{BC} \\ $$$${Prove}\:{that}\:{AB}+{AC}>\mathrm{2}{AM} \\ $$ Answered by mr W last updated on 04/Nov/23 Commented…
Question Number 199480 by Abdullahrussell last updated on 04/Nov/23 Commented by mr W last updated on 04/Nov/23 $$=\frac{\mathrm{sin}\:\theta+\mathrm{sin}\:\mathrm{50}°+\mathrm{1}+\mathrm{sin}\:\mathrm{50}°}{\mathrm{cos}\:\theta+\mathrm{cos}\:\mathrm{50}°+\mathrm{0}−\mathrm{cos}\:\mathrm{50}°} \\ $$$$=\frac{\mathrm{sin}\:\theta+\mathrm{1}+\mathrm{2}\:\mathrm{sin}\:\mathrm{50}°}{\mathrm{cos}\:\theta} \\ $$ Terms of Service…
Question Number 199424 by cortano12 last updated on 03/Nov/23 $$\:\:\:\boldsymbol{{x}} \\ $$ Answered by Frix last updated on 04/Nov/23 $${f}\left({x}\right)=\frac{\mathrm{cos}\:{x}}{\mathrm{3}}\left(\mathrm{6sin}^{\mathrm{3}} \:{x}\:−\mathrm{4sin}^{\mathrm{2}} \:{x}\:+\mathrm{1}\right) \\ $$$${f}'\left({x}\right)=−\mathrm{sin}\:{x}\:\left(\mathrm{1}−\mathrm{2sin}\:{x}\right)\left(\mathrm{3}−\mathrm{4sin}^{\mathrm{2}} \:{x}\right)…
Question Number 199374 by cortano12 last updated on 02/Nov/23 Commented by cortano12 last updated on 02/Nov/23 $$\mathrm{prove}\:\mathrm{that}\:\:\cancel{\boldsymbol{{B}}} \\ $$ Commented by MathematicalUser2357 last updated on…
Question Number 199371 by cortano12 last updated on 02/Nov/23 Commented by Frix last updated on 02/Nov/23 $$\frac{\mathrm{1}}{\mathrm{3}} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 199177 by cortano12 last updated on 29/Oct/23 Commented by yaslm last updated on 31/Oct/23 the name of book pleas Answered by a.lgnaoui last updated on 29/Oct/23 $$\mathrm{58}°…