Category: Trigonometry

Question Number 90700 by jagoll last updated on 25/Apr/20 $$\sin {}^2\left(\frac{7\pi }{8}\right)+\sin {}^2\left(\frac{3\pi }{8}\right)+\sin {}^2\left(\frac{5\pi }{8}\right)+\sin {}^2\left(\frac{\pi }{8}\right)?$$ Commented by john santu last updated on 25/Apr/20 $$\mathrm{sin}\:^{\mathrm{2}}…

Question Number 25125 by adityapratap2585@gmail.com last updated on 04/Dec/17 $$\mathbf{A}\mathrm{vertical}\mathrm{stick}12\mathbf{cm}\mathrm{long}\mathrm{casts}\mathrm{a}$$$$\mathrm{shadow}\mathrm{of}8\mathbf{cm}\mathrm{long}\mathrm{on}\mathrm{the}\mathrm{ground}.$$$$\mathrm{At}\mathrm{the}\mathrm{same}\mathrm{time},\mathrm{a}\mathrm{tower}\mathrm{casts}\mathrm{a}$$$$\mathrm{shadow}\mathrm{of}40\mathbf{m}\mathrm{long}\mathrm{on}\mathrm{the}\mathrm{ground}.$$$$\mathrm{find}\mathrm{the}\mathrm{hight}\mathrm{of}\mathrm{the}\mathrm{tower}?$$ Commented by adityapratap2585@gmail.com last updated…

Question Number 24973 by Rishabh#1 last updated on 30/Nov/17 $$\mathrm{If}a{\sin }^{2}x+b{\cos }^{2}x=c,b{\sin }^{2}y+a{\cos }^{2}y=d$$$$\mathrm{and}a\tan x=b\tan y\mathrm{then}\frac{a^2}{b^2}=?$$$$(\mathrm{in}\mathrm{terms}\mathrm{of}a,b,c,d)$$ Commented by nnnavendu…

Question Number 24972 by Rishabh#1 last updated on 30/Nov/17 $$\mathrm{If}\alpha ,\beta \mathrm{and}\gamma \mathrm{are}\mathrm{conected}\mathrm{by}\mathrm{the}\mathrm{relation}$$$${2\tan }^2\alpha {\tan }^2\beta {\tan }^2\gamma +{\tan }^2\alpha {\tan }^2\beta +$$$${\tan }^2\beta {\tan }^2\gamma +{\tan }^2\gamma {\tan }^2\alpha =1\mathrm{then}$$$$\mathrm{which}\:\mathrm{of}\:\mathrm{these}\:\mathrm{are}\:\mathrm{correct}\left(\mathrm{multi}\:\mathrm{correct}\right)…

Question Number 24959 by adityapratap2585@gmail.com last updated on 29/Nov/17 $$\mathrm{In}\mathrm{a}△\mathrm{ABC},\mathrm{\angle }\mathrm{B}=\pi /6,\mathrm{\angle }\mathrm{C}=\pi /4\mathrm{and}$$$$\mathrm{D}\mathrm{divides}\mathrm{BC}\mathrm{internally}\mathrm{in}\mathrm{the}\mathrm{ratio}$$$$1:3\mathrm{then},\frac{\sin \mathrm{\angle }\mathrm{BAD}}{\sin \mathrm{\angle }\mathrm{CAD}}\mathrm{equal}\mathrm{to}\mathrm{\_}\mathrm{\_}$$ Answered by myintkhaing last updated on 30/Nov/17 $$\frac{\sqrt{\mathrm{2}}}{\mathrm{6}} \…