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Question Number 23648 by Tinkutara last updated on 03/Nov/17 $$\mathrm{If}\:\mathrm{sin}\left(\mathrm{3}\theta\:+\:\alpha\right)\:+\:\mathrm{sin}\left(\mathrm{3}\theta\:−\:\alpha\right)\:+\:\mathrm{sin}\left(\alpha\:−\:\theta\right) \\ $$$$−\:\mathrm{sin}\left(\alpha\:+\:\theta\right)\:=\:\mathrm{cos}\alpha\:\mathrm{and}\:\mathrm{cos}\alpha\:\neq\:\mathrm{0},\:\mathrm{then} \\ $$$$\mathrm{which}\:\mathrm{of}\:\mathrm{the}\:\mathrm{values}\:\mathrm{of}\:\theta\:\mathrm{does}\:\mathrm{not}\:\mathrm{satisfy} \\ $$$$\mathrm{the}\:\mathrm{given}\:\mathrm{equation}? \\ $$$$\left(\mathrm{1}\right)\:{n}\pi\:+\:\left(−\mathrm{1}\right)^{{n}} \:\frac{\pi}{\mathrm{6}},\:{n}\:\in\:{I} \\ $$$$\left(\mathrm{2}\right)\:{n}\pi\:+\:\left(−\mathrm{1}\right)^{{n}} \:\frac{\pi}{\mathrm{10}},\:{n}\:\in\:{I} \\ $$$$\left(\mathrm{3}\right)\:{n}\pi\:+\:\left(−\mathrm{1}\right)^{{n}} \:\frac{\pi}{\mathrm{5}},\:{n}\:\in\:{I}…
Question Number 89079 by john santu last updated on 15/Apr/20 $$\left(\mathrm{cos}\:\mathrm{4}{x}+\mathrm{1}\right)\left(\mathrm{cos}\:\mathrm{2}{x}+\mathrm{1}\right)\left(\mathrm{cos}\:{x}+\mathrm{1}\right)=\:\frac{\mathrm{1}}{\mathrm{8}} \\ $$$$\mathrm{0}\:\leqslant\:{x}\:\leqslant\:\mathrm{2}\pi \\ $$ Answered by TANMAY PANACEA. last updated on 15/Apr/20 $$\mathrm{2}{cos}^{\mathrm{2}} \mathrm{2}{x}.\mathrm{2}{cos}^{\mathrm{2}}…
Question Number 89047 by jagoll last updated on 15/Apr/20 $$\mathrm{cos}\:{x}+\mathrm{sin}\:{x}=\frac{\mathrm{4}}{\mathrm{5}} \\ $$$$\mathrm{5sin}\:{x}\:=\:? \\ $$ Commented by john santu last updated on 15/Apr/20 $$\pm\:\sqrt{\mathrm{1}−\mathrm{sin}\:^{\mathrm{2}} {x}}\:=\:\frac{\mathrm{4}}{\mathrm{5}}−\mathrm{sin}\:{x} \\…
Question Number 154440 by ArielVyny last updated on 18/Sep/21 $${arcsec}\left({sec}+\mathrm{2}\right)=?? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 154434 by oustmuchiya@gmail.com last updated on 18/Sep/21 Answered by mr W last updated on 18/Sep/21 $$\frac{{BD}}{{AB}}=\frac{{AB}}{{BC}} \\ $$$$\Rightarrow{BD}=\frac{{AB}^{\mathrm{2}} }{{BC}}=\frac{\mathrm{8}^{\mathrm{2}} }{\mathrm{16}}=\mathrm{4} \\ $$ Terms…
Question Number 23343 by ajfour last updated on 29/Oct/17 Commented by ajfour last updated on 29/Oct/17 $${Q}.\mathrm{23330}\:\left({solution}\right) \\ $$ Commented by Tinkutara last updated on…
Question Number 23330 by Tinkutara last updated on 28/Oct/17 $$\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{ordered}\:\mathrm{pair}\left(\mathrm{s}\right)\:\left({x},\:{y}\right) \\ $$$$\mathrm{satisfying}\:\mathrm{the}\:\mathrm{equations}\:\mathrm{sin}{x}.\mathrm{cos}{y}\:=\:\mathrm{1} \\ $$$$\mathrm{and}\:{x}^{\mathrm{2}} \:+\:{y}^{\mathrm{2}} \:\leqslant\:\mathrm{9}\pi^{\mathrm{2}} \:\mathrm{is}/\mathrm{are} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 23304 by Tinkutara last updated on 28/Oct/17 $$\mathrm{If}\:\mathrm{sin}^{\mathrm{4}} \mathrm{x}\:+\:\mathrm{cos}^{\mathrm{4}} \mathrm{y}\:+\:\mathrm{2}\:=\:\mathrm{4}\:\mathrm{sinx}.\mathrm{cosy}\:\& \\ $$$$\mathrm{0}\:\leqslant\:{x},{y}\:\leqslant\:\frac{\pi}{\mathrm{2}}\:,\:\mathrm{then}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{sin}{x}\:+ \\ $$$$\mathrm{cos}{y}\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to} \\ $$ Commented by Joel577 last updated on 28/Oct/17…