Question Number 199005 by Safojon last updated on 26/Oct/23 Commented by mr W last updated on 29/Oct/23 $${i}\:{got}\:\frac{\mathrm{1}}{\mathrm{tan}\:\mathrm{1}°} \\ $$$${solution}\:{see}\:{Q}\mathrm{199226} \\ $$ Commented by Rasheed.Sindhi…
Question Number 198907 by a.lgnaoui last updated on 25/Oct/23 $$\mathrm{find}\:\mathrm{the}\:\mathrm{Area}\:\mathrm{betwen}\:\mathrm{Circle}\:\mathrm{1}\:\mathrm{and}\: \\ $$$$\mathrm{Circle2}. \\ $$ Commented by a.lgnaoui last updated on 25/Oct/23 Commented by Rasheed.Sindhi last…
Question Number 198900 by Safojon last updated on 25/Oct/23 $$\frac{\mathrm{2}{sin}\mathrm{2}°+\mathrm{4}{sin}\mathrm{4}°+…+\mathrm{180}{sin}\mathrm{180}°}{\mathrm{90}}=? \\ $$$${calculate}.{help}\:{me}\:{pleas}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 198815 by a.lgnaoui last updated on 24/Oct/23 $$\mathrm{Determiner}\:\boldsymbol{\mathrm{x}} \\ $$ Commented by a.lgnaoui last updated on 24/Oct/23 Commented by cherokeesay last updated on…
Question Number 198761 by ajfour last updated on 24/Oct/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 198828 by a.lgnaoui last updated on 24/Oct/23 $$\:\:\boldsymbol{\mathrm{Show}}\:\boldsymbol{\mathrm{th}{at}}: \\ $$$$\:\boldsymbol{{Area}}\left(\boldsymbol{{blue}}\:\boldsymbol{{circle}}\right)=\boldsymbol{{Area}}\left(\boldsymbol{{Green}}\:\:\boldsymbol{{circle}}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: \\ $$ Commented by a.lgnaoui last updated on 24/Oct/23 Answered by…
Question Number 198477 by a.lgnaoui last updated on 20/Oct/23 $$\mathrm{find}\:\mathrm{the}\:\mathrm{Area}\:\left(\mathrm{ABCD}\right) \\ $$ Commented by a.lgnaoui last updated on 20/Oct/23 Commented by mr W last updated…
Question Number 198423 by pascal889 last updated on 19/Oct/23 $$\mathrm{show}\:\mathrm{that} \\ $$$$\frac{\mathrm{1}+\mathrm{sin}\varnothing}{\mathrm{cos}\varnothing}\:=\frac{\mathrm{cos}\varnothing}{\mathrm{1}−\mathrm{sin}\varnothing} \\ $$$$\mathrm{Pls}\:\mathrm{help} \\ $$$$ \\ $$ Answered by BaliramKumar last updated on 19/Oct/23…
Question Number 198357 by pticantor last updated on 18/Oct/23 $$\boldsymbol{{let}}\:\:\boldsymbol{{a}}\in\mathbb{R},\:\boldsymbol{{z}}\in\mathbb{C} \\ $$$$\boldsymbol{{resolve}}\: \\ $$$$\left(\boldsymbol{{z}}+\mathrm{1}\right)^{\boldsymbol{{n}}} =\boldsymbol{{e}}^{\boldsymbol{{i}}\pi\boldsymbol{{na}}} \\ $$$$\boldsymbol{{deduce}}\:\boldsymbol{{that}}\:\boldsymbol{{P}}_{\boldsymbol{{n}}} =\underset{{k}=\mathrm{0}} {\overset{\boldsymbol{{n}}−\mathrm{1}} {\prod}}\boldsymbol{{sin}}\left(\boldsymbol{{a}}+\frac{\boldsymbol{{k}}\pi}{\boldsymbol{{n}}}\right) \\ $$ Terms of Service…
Question Number 197937 by mathlove last updated on 05/Oct/23 $$\sqrt{\mathrm{3}}\:{sin}^{\mathrm{2}} \theta\centerdot{tan}\beta+{cos}^{\mathrm{2}} \beta=? \\ $$ Answered by Frix last updated on 05/Oct/23 $$\mathrm{It}\:\mathrm{is}\:\mathrm{what}\:\mathrm{it}\:\mathrm{is},\:\mathrm{not}\:\mathrm{getting}\:\mathrm{better}\:\mathrm{any}\:\mathrm{way}. \\ $$$${p}=\mathrm{tan}\:\theta\:\wedge{q}=\mathrm{tan}\:\beta\:\rightarrow\:\frac{\sqrt{\mathrm{3}}{p}^{\mathrm{2}} {q}}{{p}^{\mathrm{2}}…