Question Number 21431 by Tinkutara last updated on 23/Sep/17 $$\mathrm{In}\:\mathrm{any}\:\Delta{ABC},\:{a}\left({b}\:\mathrm{cos}\:{C}\:−\:{c}\:\mathrm{cos}\:{B}\right)\:= \\ $$ Answered by $@ty@m last updated on 23/Sep/17 $$={ab}\mathrm{cos}\:{C}−{ac}\mathrm{cos}\:{B} \\ $$$$=\frac{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} −{c}^{\mathrm{2}} }{\mathrm{2}}−\frac{{c}^{\mathrm{2}}…
Question Number 21429 by Tinkutara last updated on 23/Sep/17 $$\mathrm{In}\:\mathrm{any}\:\Delta{ABC},\:\Sigma{a}^{\mathrm{2}} \left(\mathrm{sin}\:{B}\:−\:\mathrm{sin}\:{C}\right)\:= \\ $$ Answered by $@ty@m last updated on 23/Sep/17 $${We}\:{have} \\ $$$$\frac{{a}}{\mathrm{sin}\:{A}}=\frac{{b}}{\mathrm{sin}\:{B}}=\frac{{c}}{\mathrm{sin}\:{C}}={k},\:{say} \\ $$$$\therefore\Sigma{a}^{\mathrm{2}}…
Question Number 21430 by Tinkutara last updated on 23/Sep/17 $$\mathrm{In}\:\mathrm{any}\:\Delta{ABC},\:\mathrm{the}\:\mathrm{value}\:\mathrm{of} \\ $$$$\mathrm{2}{ac}\:\mathrm{sin}\:\left(\frac{{A}\:−\:{B}\:+\:{C}}{\mathrm{2}}\right)\:\mathrm{is} \\ $$ Answered by $@ty@m last updated on 23/Sep/17 $$=\mathrm{2}{ac}\mathrm{sin}\:\left(\frac{\pi−\mathrm{2}{B}}{\mathrm{2}}\right) \\ $$$$=\mathrm{2}{ac}\mathrm{cos}\:{B} \\…
Question Number 86932 by jagoll last updated on 01/Apr/20 Answered by mr W last updated on 01/Apr/20 $$\mathrm{1}. \\ $$$${RS}={RT} \\ $$$$\mathrm{5}\left({x}−\mathrm{3}\right)+\mathrm{6}=\mathrm{4}\left(\mathrm{2}{x}−\mathrm{6}\right) \\ $$$$\mathrm{15}=\mathrm{3}{x} \\…
Question Number 86878 by jagoll last updated on 01/Apr/20 $$\mathrm{If}\:\mathrm{sin}\:^{\mathrm{10}} \:\left(\mathrm{x}\right)\:+\:\mathrm{cos}\:^{\mathrm{10}} \:\left(\mathrm{x}\right)\:=\:\frac{\mathrm{11}}{\mathrm{36}} \\ $$$$\mathrm{find}\:\mathrm{sin}\:^{\mathrm{12}} \:\left(\mathrm{x}\right)\:+\:\mathrm{cos}\:\:^{\mathrm{12}} \left(\mathrm{x}\right)\:=\:? \\ $$ Commented by Prithwish Sen 1 last updated…
Question Number 152385 by imjagoll last updated on 28/Aug/21 $$\:\mathrm{4}−\mathrm{cosec}\:^{\mathrm{2}} \left(\mathrm{2x}\right)\geqslant\:\mathrm{0} \\ $$$$\:\mathrm{find}\:\mathrm{x} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 21297 by NECx last updated on 19/Sep/17 Answered by sma3l2996 last updated on 20/Sep/17 $$\mathrm{2}{sin}^{−\mathrm{1}} \left({x}\sqrt{\mathrm{6}}\right)+{sin}^{−\mathrm{1}} \left(\mathrm{4}{x}\right)=\frac{\pi}{\mathrm{2}} \\ $$$${sin}^{−\mathrm{1}} \left(\mathrm{4}{x}\right)=\frac{\pi}{\mathrm{2}}−\mathrm{2}{sin}^{−\mathrm{1}} \left({x}\sqrt{\mathrm{6}}\right) \\ $$$${sin}\left({sin}^{−\mathrm{1}}…
Question Number 21296 by NECx last updated on 19/Sep/17 Commented by NECx last updated on 19/Sep/17 $$\mathrm{please}\:\mathrm{help}\:\mathrm{me}\:\mathrm{solve}\:\mathrm{this}.\:\mathrm{It}\:\mathrm{was} \\ $$$$\mathrm{solved}\:\mathrm{before}\:\mathrm{but}\:\mathrm{i}\:\mathrm{cant}\:\mathrm{assess}\:\mathrm{the} \\ $$$$\mathrm{answer}\:\mathrm{again}. \\ $$$$ \\ $$$$\mathrm{please}\:\mathrm{help}…
Question Number 21273 by 8116417733 last updated on 18/Sep/17 $$\mathrm{cos}\:\mathrm{70}+\mathrm{4cos}\:\mathrm{70} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 21272 by Tinkutara last updated on 18/Sep/17 $$\mathrm{Let}\:\alpha,\:\beta\:\in\:\left(−\pi,\:\pi\right)\:\mathrm{be}\:\mathrm{such}\:\mathrm{that} \\ $$$$\mathrm{cos}\left(\alpha\:−\:\beta\right)\:=\:\mathrm{1}\:\mathrm{and}\:\mathrm{cos}\left(\alpha\:+\:\beta\right)\:=\:\frac{\mathrm{1}}{{e}}. \\ $$$$\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{pairs}\:\mathrm{of}\:\alpha,\:\beta\:\mathrm{satisfying} \\ $$$$\mathrm{the}\:\mathrm{above}\:\mathrm{system}\:\mathrm{of}\:\mathrm{equation}\:\mathrm{is} \\ $$ Answered by mrW1 last updated on 18/Sep/17…