Menu Close

Category: Trigonometry

Question-17119

Question Number 17119 by gourav~ last updated on 01/Jul/17 Commented by prakash jain last updated on 01/Jul/17 sin(A+3B)+sin(3A+B)sin2A+sin2B=2sin(4A+4B2)cos(2B2A2)2sin(A+B)cos(AB)=2sin(2(A+B))cos(AB)2sin(A+B)cos(AB)$$=\frac{\mathrm{sin}\:\left(\mathrm{2}\left({A}+{B}\right)\right)}{\mathrm{sin}\:\left({A}+{B}\right)} \