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Question Number 196625 by sniper237 last updated on 28/Aug/23 $${Let}\:\:{a}={BC}\:\:{b}={CA}\:\:{c}={AB} \\ $$$${ABC}\:\:{is}\:{rectangle}\:{iff}\:\:{tan}\left(\frac{\hat {{A}}}{\mathrm{2}}\right)=\frac{{a}}{{b}+{c}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 196611 by ERLY last updated on 27/Aug/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 196523 by ERLY last updated on 27/Aug/23 $${resoudre}\:{dans}\:{c}\:{l}\:{equation}\:{sinx}=\mathrm{2}\:\:\:\:\:\bigstar{erly}\:{rolvinst}\bigstar\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:<{erly}\:{rolvinst}> \\ $$ Answered by Frix last updated on 26/Aug/23 $$\mathrm{sin}\:{x}\:=\frac{\mathrm{e}^{\mathrm{i}{x}} −\mathrm{e}^{−\mathrm{i}{x}} }{\mathrm{2i}}=\mathrm{2} \\ $$$$\mathrm{e}^{\mathrm{i}{x}} −\frac{\mathrm{1}}{\mathrm{e}^{\mathrm{i}{x}}…
Question Number 196517 by ERLY last updated on 26/Aug/23 Answered by mr W last updated on 27/Aug/23 $$\mathrm{cos}\:{x}+{i}\:\mathrm{sin}\:{x}={e}^{{ix}} \\ $$$$\mathrm{cos}\:{x}−{i}\:\mathrm{sin}\:{x}={e}^{−{ix}} \\ $$$$\Rightarrow\mathrm{cos}\:{x}=\frac{{e}^{{ix}} +{e}^{−{ix}} }{\mathrm{2}}=\mathrm{2} \\…
Question Number 196518 by ERLY last updated on 26/Aug/23 $${resouxre}\:{cosx}=\mathrm{2} \\ $$ Answered by Frix last updated on 26/Aug/23 $$\mathrm{Similar}\:\mathrm{to}\:\mathrm{the}\:\mathrm{other}\:\mathrm{question} \\ $$$${x}=\mathrm{2}{n}\pi\pm\mathrm{i}\:\mathrm{ln}\:\left(\mathrm{2}+\sqrt{\mathrm{3}}\right) \\ $$ Terms…
Question Number 196413 by a.lgnaoui last updated on 24/Aug/23 $$\mathrm{determiner}\:\:\boldsymbol{\mathrm{a}}\:\mathrm{et}\:\boldsymbol{\mathrm{b}} \\ $$$$ \\ $$ Commented by a.lgnaoui last updated on 24/Aug/23 Commented by AST last…
Question Number 196394 by Erico last updated on 24/Aug/23 $$\mathrm{If}\:\:{f}\left({x}\right)=\underset{\:\mathrm{0}} {\int}^{\:{x}} {e}^{−{f}\left({t}\right)} {dt} \\ $$$$\mathrm{Determine}\:{f}\left({x}\right) \\ $$ Answered by mr W last updated on 24/Aug/23…
Question Number 196302 by cortano12 last updated on 22/Aug/23 Answered by Rasheed.Sindhi last updated on 22/Aug/23 $$\mathrm{60}+\left(\mathrm{180}−{a}\right)+\left(\mathrm{180}−{b}\right)+\left(\mathrm{180}−{c}\right)=\mathrm{360} \\ $$$$\mathrm{60}+\mathrm{180}×\mathrm{3}−\mathrm{360}={a}+{b}+{c} \\ $$$${a}+{b}+{c}=\mathrm{240} \\ $$ Commented by…
Question Number 196265 by KRIMO last updated on 21/Aug/23 Answered by a.lgnaoui last updated on 21/Aug/23 $$\mathrm{posons}\:\mathrm{z}=\mathrm{a}+\mathrm{ib}\:\Leftrightarrow\mathrm{z}=\sqrt{\mathrm{a}^{\mathrm{2}} +\mathrm{b}^{\mathrm{2}} \:}\:\left(\frac{\mathrm{a}}{\:\sqrt{\mathrm{a}^{\mathrm{2}} +\mathrm{b}^{\mathrm{2}} }}+\mathrm{i}\frac{\mathrm{b}}{\:\sqrt{\mathrm{a}^{\mathrm{2}} +\mathrm{b}^{\mathrm{2}} }}\right) \\ $$$$\mathrm{avec}\:\:\frac{\mathrm{a}}{\:\sqrt{\mathrm{a}^{\mathrm{2}}…