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Category: Trigonometry

Question-14991

Question Number 14991 by tawa tawa last updated on 06/Jun/17 Answered by ajfour last updated on 06/Jun/17 =tanθ(11tanθ)+1tanθ(1tanθ)=tan2θtanθ11tanθ(tanθ1)$$\:\:\:\:=\frac{\mathrm{tan}\:^{\mathrm{3}} \theta−\mathrm{1}}{\mathrm{tan}\:\theta\left(\mathrm{tan}\:\theta−\mathrm{1}\right)}\: \