Category: Trigonometry

Question Number 13234 by tawa tawa last updated on 17/May/17 $$\mathrm{The}\mathrm{angle}\mathrm{of}\mathrm{elevation}\mathrm{of}\mathrm{the}\mathrm{sun}\mathrm{is}27°.\mathrm{A}\mathrm{man}\mathrm{is}180\mathrm{cm}\mathrm{tall}.\mathrm{How}\mathrm{long}\mathrm{is}$$$$\mathrm{his}\mathrm{shadow}.\mathrm{Give}\mathrm{your}\mathrm{answer}\mathrm{to}\mathrm{the}\mathrm{nearest}10\mathrm{cm}$$ Answered by b.e.h.i.8.3.4.1.7@gmail.com last updated on 17/May/17 $${l}=\mathrm{180}.{tg}\mathrm{27}^{°} #\mathrm{90}\:{cm} \…

Question Number 13224 by Tinkutara last updated on 16/May/17 Commented by Tinku Tara last updated on 16/May/17 $$\mathrm{Can}\mathrm{u}\mathrm{please}\mathrm{use}\mathrm{a}\mathrm{different}\mathrm{name}$$$$\mathrm{for}\mathrm{your}\mathrm{user}\mathrm{id}.\mathrm{Since}\mathrm{tinku}\mathrm{tara}$$$$\mathrm{is}\mathrm{publisher}\mathrm{name}.$$$$\mathrm{Thank}\:\mathrm{You}\:\mathrm{for}\:\mathrm{ur}\:\mathrm{cooperation}. \…

Question Number 13194 by Tinkutara last updated on 16/May/17 Answered by ajfour last updated on 16/May/17 $$\left(i\right)$$$$letx=\tan \alpha ,y=\tan \beta ,z=\tan \gamma$$$$\tan (\alpha +\beta +\gamma )=\frac{\mathrm{\Sigma }\tan \alpha -\mathrm{\Pi }\tan \alpha }{1-\mathrm{\Sigma }\tan \alpha \tan \beta }$$$$x+y+z=xyz\dots .\left(given\right)$$$$\:\Rightarrow\:\Sigma\mathrm{tan}\:\alpha\:=\:\Pi\mathrm{tan}\:\alpha\:\:\:\:\:\:\:…

Question Number 13143 by tawa tawa last updated on 15/May/17 $$\mathrm{Find}\mathrm{the}\mathrm{point}(\mathrm{x},\mathrm{y})\mathrm{which}\mathrm{lies}8\mathrm{unit}\mathrm{from}\mathrm{the}\mathrm{origin},\mathrm{along}\mathrm{the}\mathrm{terminal}\mathrm{line}$$$$\mathrm{of}155°.$$ Commented by RasheedSindhi last updated on 15/May/17 $$\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} =\mathrm{8}^{\mathrm{2}}…

Question Number 78643 by thiruppathit883@gmail.com last updated on 19/Jan/20 $$\sin 20\times \sin 40\times \sin 80=\sqrt{3/8}$$ Commented by jagoll last updated on 19/Jan/20 $$\mathrm{using}\mathrm{formula}$$$$\mathrm{sin}\:\theta×\mathrm{sin}\:\left(\mathrm{60}^{\mathrm{o}} −\theta\right)×\mathrm{sin}\:\left(\mathrm{60}^{\mathrm{o}} +\theta\right)= \…