Question Number 143350 by gsk2684 last updated on 13/Jun/21 $$\mathrm{if}\:\mathrm{tan}^{\mathrm{2}} \alpha\mathrm{tan}^{\mathrm{2}} \beta+\mathrm{tan}^{\mathrm{2}} \beta\mathrm{tan}^{\mathrm{2}} \gamma+ \\ $$$$\mathrm{tan}^{\mathrm{2}} \gamma\mathrm{tan}^{\mathrm{2}} \alpha+\mathrm{2tan}^{\mathrm{2}} \alpha\mathrm{tan}^{\mathrm{2}} \beta\mathrm{tan}^{\mathrm{2}} \gamma=\mathrm{1} \\ $$$$\mathrm{then}\:\mathrm{find}\:\mathrm{sin}^{\mathrm{2}} \alpha+\mathrm{sin}^{\mathrm{2}} \beta+\mathrm{sin}^{\mathrm{2}}…
Question Number 143348 by gsk2684 last updated on 13/Jun/21 $$\mathrm{if}\:\:\frac{\mathrm{cos}\:^{\mathrm{4}} \mathrm{x}}{\mathrm{cos}\:^{\mathrm{2}} \mathrm{y}}+\frac{\mathrm{sin}\:^{\mathrm{4}} \mathrm{x}}{\mathrm{sin}\:^{\mathrm{2}} \mathrm{y}}=\mathrm{1}\:\mathrm{then}\: \\ $$$$\mathrm{find}\:\frac{\mathrm{cos}\:^{\mathrm{4}} \mathrm{y}}{\mathrm{cos}\:^{\mathrm{2}} \mathrm{x}}+\frac{\mathrm{sin}\:^{\mathrm{4}} \mathrm{y}}{\mathrm{sin}\:^{\mathrm{2}} \mathrm{x}}=? \\ $$ Answered by som(math1967)…
Question Number 143274 by Aditya9886 last updated on 12/Jun/21 Answered by Olaf_Thorendsen last updated on 12/Jun/21 $${y}\:=\:\mathrm{sin}^{\mathrm{2}} \left(\mathrm{cos}{x}\right) \\ $$$$\frac{{dy}}{{dx}}\:=\:\left(−\mathrm{sin}{x}\right)×\mathrm{2cos}\left(\mathrm{cos}{x}\right)×\mathrm{sin}\left(\mathrm{cos}{x}\right) \\ $$$$\frac{{dy}}{{dx}}\:=\:−\mathrm{sin}{x}.\mathrm{sin}\left(\mathrm{2cos}{x}\right) \\ $$$$ \\…
Question Number 12132 by tawa last updated on 14/Apr/17 $$\mathrm{Given}\:\mathrm{that}\:\:\mathrm{1}°\:=\:\mathrm{0}.\mathrm{017}\:\mathrm{rad} \\ $$$$\mathrm{Use}\:\:\mathrm{f}\left(\mathrm{a}\right)\:=\:\mathrm{sin}\left(\mathrm{a}\right)\:\mathrm{to}\:\mathrm{find}\:\mathrm{an}\:\mathrm{approximate}\:\mathrm{value}\:\mathrm{for}\:\mathrm{sin}\left(\mathrm{29}\right)°. \\ $$ Answered by mrW1 last updated on 14/Apr/17 $$\frac{\Delta{y}}{\Delta{x}}=\frac{{f}\left({x}+\Delta{x}\right)−{f}\left({x}\right)}{\Delta{x}}\approx\frac{{dy}}{{dx}} \\ $$$$\Rightarrow\:{f}\left({x}+\Delta{x}\right)\approx{f}\left({x}\right)+\frac{{dy}}{{dx}}\Delta{x} \\…
Question Number 12092 by agni5 last updated on 13/Apr/17 $$\mathrm{Prove}\:\mathrm{that}\:\:\mathrm{tan}\:\mathrm{70}°−\mathrm{tan}\:\mathrm{50}°+\mathrm{tan}\:\mathrm{10}°\:=\sqrt{\mathrm{3}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 12085 by chux last updated on 12/Apr/17 Answered by ajfour last updated on 12/Apr/17 $${let}\:\mathrm{6}°=\theta \\ $$$$\mathrm{sin}\:\mathrm{24}°=\mathrm{2sin}\:\mathrm{12}°\mathrm{cos}\:\mathrm{12}° \\ $$$${let}\:\mathrm{sin}\:\mathrm{12}°={x}\:\:{and}\:\:\mathrm{cos}\:\mathrm{12}°={y} \\ $$$$\mathrm{sin}\:\left(\mathrm{3}\theta+\mathrm{2}\theta\right)=\:{y}\:\mathrm{sin}\:\mathrm{18}°+{x}\:\mathrm{cos}\:\mathrm{18}° \\ $$$$\Rightarrow\:{x}\mathrm{cos}\:\mathrm{18}°+{y}\mathrm{sin}\:\mathrm{18}°\:=\mathrm{sin}\:\mathrm{5}\theta=\frac{\mathrm{1}}{\mathrm{2}}…
Question Number 12078 by agni5 last updated on 12/Apr/17 $$\mathrm{If}\:\mathrm{tan}\:^{\mathrm{2}} \alpha\:=\:\mathrm{1}+\mathrm{2tan}\:^{\mathrm{2}} \beta\:\:\mathrm{then}\:\mathrm{prove}\:\mathrm{that} \\ $$$$\:\mathrm{cos}\:\mathrm{2}\beta\:=\mathrm{1}+\mathrm{2cos}\:\mathrm{2}\alpha\:. \\ $$ Answered by ajfour last updated on 12/Apr/17 $$\mathrm{1}+\mathrm{2cos}\:\mathrm{2}\alpha\:=\mathrm{1}+\frac{\mathrm{2}\left(\mathrm{1}−\mathrm{tan}\:^{\mathrm{2}} \alpha\right)}{\mathrm{1}+\mathrm{tan}\:^{\mathrm{2}}…
Question Number 12063 by tawa last updated on 10/Apr/17 Answered by b.e.h.i.8.3.4.1.7@gmail.com last updated on 11/Apr/17 $$\mathrm{100}+\mathrm{4}\left(\mathrm{180}−{a}\right)=\mathrm{360}\Rightarrow\mathrm{4}{a}=\mathrm{820}−\mathrm{360} \\ $$$$\mathrm{4}{a}=\mathrm{460}\Rightarrow{a}=\mathrm{115}\:\:\:\:.\blacksquare \\ $$ Terms of Service Privacy…
Question Number 143102 by liberty last updated on 10/Jun/21 Answered by som(math1967) last updated on 10/Jun/21 $$\mathrm{2}\boldsymbol{{y}}=\mathrm{40}°+\mathrm{2}×\mathrm{48} \\ $$$$\boldsymbol{{y}}=\frac{\mathrm{136}}{\mathrm{2}}=\mathrm{68}° \\ $$$$\boldsymbol{{again}}\:\mathrm{48}\:+\boldsymbol{{x}}=\boldsymbol{{y}} \\ $$$$\boldsymbol{{x}}=\mathrm{68}−\mathrm{48}=\mathrm{20}° \\ $$…
Question Number 12028 by tawa last updated on 09/Apr/17 $$\mathrm{Express}\::\:\mathrm{sin}\left(\mathrm{33}\right)\:\mathrm{in}\:\mathrm{surd}\:\mathrm{form}. \\ $$ Answered by sandy_suhendra last updated on 10/Apr/17 $$\mathrm{let}\:\mathrm{A}=\mathrm{18}° \\ $$$$\mathrm{5A}=\mathrm{90}° \\ $$$$\mathrm{3A}=\mathrm{90}°−\mathrm{2A} \\…