Question Number 77178 by jagoll last updated on 04/Jan/20 $$ \\ $$$${given}\:\mathrm{cos}^{−\mathrm{1}} \left({x}\right)+\mathrm{cos}^{−\mathrm{1}} \left({y}\right)+\mathrm{cos}^{−\mathrm{1}} \left({z}\right)=\pi \\ $$$${and}\:{x}+{y}+{z}=\frac{\mathrm{3}}{\mathrm{2}} \\ $$$${prove}\:{that}\:{x}\:=\:{y}\:=\:{z}\:. \\ $$ Answered by john santu…
Question Number 77129 by mathocean1 last updated on 03/Jan/20 $$\mathrm{solve}\:\mathrm{in}\:\mathrm{R} \\ $$$$\mid\mathrm{tan2}{x}\mid−\sqrt{\mathrm{3}}\geqslant\mathrm{0} \\ $$ Answered by jagoll last updated on 03/Jan/20 Commented by mathocean1 last…
Question Number 77123 by mathocean1 last updated on 03/Jan/20 $$\mathrm{ABC}\:\mathrm{is}\:\mathrm{a}\:\mathrm{non}−\mathrm{right}\:\mathrm{triangle}. \\ $$$$\left.\mathrm{1}\right)\:\mathrm{Demonstrate}\:\mathrm{that} \\ $$$$\mathrm{tan}\left(\hat {\mathrm{A}}+\hat {\mathrm{B}}\right)=−\mathrm{tan}\hat {\mathrm{C}}. \\ $$$$\left.\mathrm{1}\right)\:\mathrm{By}\:\mathrm{using}\:\mathrm{tan}\left(\hat {\mathrm{A}}+\hat {\mathrm{B}}\right)=\frac{\mathrm{tan}\hat {\mathrm{A}}+\mathrm{tan}\hat {\mathrm{B}}}{\mathrm{1}−\mathrm{tan}\hat {\mathrm{A}tan}\hat {\mathrm{B}}}…
Question Number 142617 by iloveisrael last updated on 03/Jun/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 77041 by mathocean1 last updated on 02/Jan/20 $$\mathrm{solve}\:\mathrm{in}\:\left[\mathrm{0};\pi\right] \\ $$$$\mathrm{sin}{x}−\mathrm{sin}^{\mathrm{3}} {x}=\mathrm{1}−\mathrm{cos2}{x} \\ $$ Answered by mind is power last updated on 02/Jan/20 $$\Leftrightarrow…
Question Number 77027 by mathocean1 last updated on 02/Jan/20 $$\mathrm{Please}\:\mathrm{help}\:\mathrm{me}\:\mathrm{to}\:\mathrm{solve}\:\mathrm{it}\:\mathrm{in}\:\left[−\pi;\mathrm{0}\right] \\ $$$$\mathrm{cos2}{x}+\mathrm{cos}{x}+\mathrm{1}=\mathrm{sin3}{x}+\mathrm{sin2}{x}+\mathrm{sin}{x} \\ $$$${E}\mathrm{xplain}\:\mathrm{details}\:\mathrm{if}\:\mathrm{possible}. \\ $$$$ \\ $$ Answered by mr W last updated on…
Question Number 11475 by tawa last updated on 26/Mar/17 Answered by sm3l2996 last updated on 26/Mar/17 $$\mathrm{Question}\:\mathrm{105}:\left(\mathrm{B}\right) \\ $$$$\mathrm{Question}\:\mathrm{106}: \\ $$$$\Delta\mathrm{AFD}=\frac{\mathrm{x}^{\mathrm{2}} }{\mathrm{2}}=\frac{\mathrm{25}}{\mathrm{2}}=\mathrm{12}.\mathrm{5}\:\left(\mathrm{C}\right) \\ $$ Commented…
Question Number 11474 by tawa last updated on 26/Mar/17 Answered by sm3l2996 last updated on 26/Mar/17 $$\left(\mathrm{E}\right) \\ $$ Commented by tawa last updated on…
Question Number 11456 by Joel576 last updated on 26/Mar/17 $$\mathrm{sin}\:{x}\:−\:\mathrm{cos}\:{x}\:=\:{a},\:\:\frac{\pi}{\mathrm{4}}\:\leqslant\:{x}\:\leqslant\:\frac{\pi}{\mathrm{2}} \\ $$$$\mathrm{Which}\:\mathrm{statement}\:\mathrm{is}\:\mathrm{correct}? \\ $$$$\left(\mathrm{1}\right)\:\mathrm{sin}^{\mathrm{2}} \:{x}\:−\:\mathrm{cos}^{\mathrm{2}} \:{x}\:=\:−\frac{\mathrm{1}}{\mathrm{2}}\sqrt{\mathrm{3}\:+\:\mathrm{2}{a}^{\mathrm{2}} \:−\:{a}^{\mathrm{4}} } \\ $$$$\left(\mathrm{2}\right)\:\mathrm{sin}^{\mathrm{4}} \:{x}\:+\:\mathrm{cos}^{\mathrm{4}} \:{x}\:=\:\frac{\mathrm{1}}{\mathrm{8}}\left(−\mathrm{3}{a}^{\mathrm{4}} \:+\:\mathrm{6}{a}^{\mathrm{2}} \:+\:\mathrm{5}\right) \\…
Question Number 142393 by qaz last updated on 31/May/21 $$\underset{\mathrm{k}=\mathrm{0}} {\overset{\mathrm{n}−\mathrm{1}} {\sum}}\mathrm{sec}^{\mathrm{2}} \left(\frac{\mathrm{k}\pi}{\mathrm{n}}\right)=\mathrm{n}^{\mathrm{2}} ……??? \\ $$ Answered by mindispower last updated on 31/May/21 $$=\underset{{k}=\mathrm{0}} {\overset{{n}−\mathrm{1}}…