Question Number 142010 by jlewis last updated on 25/May/21 $$\mathrm{find}\:\mathrm{x}\:\mathrm{2cosh}\:\mathrm{2x}\:+\mathrm{10sinh}\:\mathrm{2x}=\mathrm{5} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 10917 by okhema last updated on 02/Mar/17 $${hence}\:{show}\:{that} \\ $$$$\left.{i}\right)\frac{\mathrm{1}−{cos}\mathrm{4}\theta}{{sin}\mathrm{4}\theta}={tan}\mathrm{2}\theta \\ $$$$\left.{ii}\right)\frac{\mathrm{1}−{cos}\mathrm{6}\theta}{{sin}\mathrm{6}\theta}={tan}\mathrm{3}\theta \\ $$ Answered by sandy_suhendra last updated on 02/Mar/17 $$\mathrm{we}\:\mathrm{use}\:\:\:\:\mathrm{cos}\:\mathrm{2}\theta=\mathrm{1}−\mathrm{2sin}^{\mathrm{2}} \theta\:\Rightarrow\:\mathrm{2sin}^{\mathrm{2}}…
Question Number 10916 by okhema last updated on 02/Mar/17 $${find}\:{all}\:{possible}\:{values}\:{of}\:{cos}\theta\:{such} \\ $$$${that}\:\mathrm{2}{cot}^{\mathrm{2}} \theta+{cos}\theta=\mathrm{0} \\ $$ Answered by sandy_suhendra last updated on 02/Mar/17 $$\frac{\mathrm{2cos}^{\mathrm{2}} \theta}{\mathrm{sin}^{\mathrm{2}} \theta}\:+\:\mathrm{cos}\theta\:=\mathrm{0}…
Question Number 10906 by niraj last updated on 01/Mar/17 $${Q}\:.\:\:{smallest}\:{positive}\:{x}\:{satisfying}\:{the}\:{equation} \\ $$$${sin}\mathrm{3}{x}+\mathrm{3}{cosx}=\mathrm{2}{sin}\mathrm{2}{x}\left({sinx}+{cosx}\right)\:,\:{is} \\ $$ Commented by niraj last updated on 02/Mar/17 $${sir}\:{answer}\:{please} \\ $$ Answered…
Question Number 76439 by mathocean1 last updated on 27/Dec/19 $$\mathrm{solve}\:\mathrm{in}\:\left[\mathrm{0};\mathrm{2}\pi\left[\:\right.\right. \\ $$$$\mathrm{1}+\mathrm{2sin3}{x}\leqslant\mathrm{0} \\ $$ Answered by john santu last updated on 27/Dec/19 $${sin}\mathrm{3}{x}=−\frac{\mathrm{1}}{\mathrm{2}}.\rightarrow{x}=\left\{\mathrm{10}^{{o}} ,\mathrm{50}^{{o}} ,\mathrm{130}^{{o}}…
Question Number 76434 by benjo last updated on 27/Dec/19 $$\mathrm{if}\:\mathrm{sec}\:\mathrm{x}\:−\:\mathrm{tan}\:\mathrm{x}\:=\:\mathrm{4},\:\mathrm{then}\:\mathrm{find}\: \\ $$$$\mathrm{sin}\:\mathrm{x}. \\ $$ Answered by john santu last updated on 27/Dec/19 $${using}\::\:\mathrm{sec}\:^{\mathrm{2}} {x}−\mathrm{tan}\:^{\mathrm{2}} {x}\:=\mathrm{1}…
Question Number 10873 by Saham last updated on 28/Feb/17 $$\mathrm{without}\:\mathrm{using}\:\mathrm{calculator}\:\mathrm{or}\:\mathrm{table},\:\mathrm{find}\:\mathrm{the}\:\mathrm{exact}\:\mathrm{value}\:\mathrm{of}\:\:: \\ $$$$\mathrm{sin}\left[\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{1}}{\mathrm{2}}\right)\right] \\ $$ Answered by fariraihmudzengerere75@gmail.c last updated on 28/Feb/17 $${Answer}\:\:\:.\:\mathrm{sin}\:\left[\mathrm{tan}^{−\mathrm{1}} \left({x}\right)\right]={x}/\sqrt{\left(\mathrm{1}+\boldsymbol{\mathrm{x}}\frac{\mathrm{2}}{}\right)} \\…
Question Number 10837 by okhema last updated on 27/Feb/17 $${given}\:{that}\:{sinA}=\frac{\mathrm{12}}{\mathrm{13}}{and}\:{sinB}=\frac{\mathrm{4}}{\mathrm{5}}, \\ $$$${where}\:{A}\:{and}\:{B}\:{are}\:{acute}\:{angles}, \\ $$$${find}\:{cos}\left({A}−{B}\right)\:{and}\:{sin}\left({A}+{B}\right) \\ $$$$ \\ $$ Answered by ridwan balatif last updated on…
Question Number 10836 by okhema last updated on 27/Feb/17 $${solve}\:{cos}\mathrm{2}\theta−\mathrm{3}{cos}\theta=\mathrm{1} \\ $$$${for}\:{o}\leqslant\theta\leqslant\mathrm{2}\pi \\ $$ Answered by ridwan balatif last updated on 27/Feb/17 $$\mathrm{cos2}\theta−\mathrm{3cos}\theta=\mathrm{1} \\ $$$$\left(\mathrm{2cos}^{\mathrm{2}}…
Question Number 10825 by Saham last updated on 26/Feb/17 $$\mathrm{Given}\:\mathrm{that}\: \\ $$$$\mathrm{sin}\left(\mathrm{x}\right)\:−\:\mathrm{sin}\left(\mathrm{y}\right)\:=\:\mathrm{sin}\left(\theta\right) \\ $$$$\mathrm{cos}\left(\mathrm{x}\right)\:+\:\mathrm{cos}\left(\mathrm{y}\right)\:=\:\mathrm{cos}\left(\theta\right) \\ $$$$\mathrm{Show}\:\mathrm{that}\: \\ $$$$\mathrm{cos}\left(\mathrm{x}\:+\:\mathrm{y}\right)\:=\:−\frac{\mathrm{1}}{\mathrm{2}} \\ $$ Answered by mrW1 last updated…