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Category: Trigonometry

Question-143499

Question Number 143499 by mnjuly1970 last updated on 15/Jun/21 Commented by MJS_new last updated on 15/Jun/21 tan(60°α)=3tanα1+3tanαtan(60°+α)=3+tanα13tanα$$\mathrm{tan}\:\mathrm{3}\alpha\:=\frac{\left(\mathrm{3}−\mathrm{tan}^{\mathrm{2}} \:\alpha\right)\mathrm{tan}\:\alpha}{\mathrm{1}−\mathrm{3tan}^{\mathrm{2}} \:\alpha}…