Trigonometry – Page 176

cos-2n-1-cos-2-2n-1-cos-3-2n-1-cos-n-2n-1-1-2-n-prove-

Tinku Tara June 3, 2023 Trigonometry 0 Comments

Question Number 143063 by ERA last updated on 09/Jun/21 $\cos (\frac{π}{2 n + 1}) \cos (\frac{2 π}{2 n + 1}) \cos (\frac{3 π}{2 n + 1}) \dots . . \cos (\frac{n π}{2 n + 1}) = \frac{1}{2^{n}}$ $prove$ Terms of Service Privacy Policy Contact: info@tinkutara.com

cos-cos-2-cos-4-cos-2-n-sin-2-n-1-2-n-1-sin-prove-

Tinku Tara June 3, 2023 Trigonometry 0 Comments

Question Number 143057 by ERA last updated on 09/Jun/21 $\cos (α) \times \cos (2 α) \times \cos (4 α) \times \dots . \times \cos (2^{n} α) = \frac{\sin (2^{n + 1} α)}{2^{n + 1} \sin (α)}$ $prove$ Answered by Dwaipayan Shikari last updated on 09/Jun/21…

cos-1-x-2-1-x-2-1-1-2-tan-1-2x-1-x-2-2pi-3-x-

Tinku Tara June 3, 2023 Trigonometry 0 Comments

Question Number 143039 by bramlexs22 last updated on 09/Jun/21 $\cos^{- 1} (\frac{x^{2} - 1}{x^{2} + 1}) + \frac{1}{2} \tan^{- 1} (\frac{2 x}{1 - x^{2}}) = \frac{2 π}{3}$ $x = ?$ Terms of Service Privacy Policy Contact:…

Hello-sirs-i-want-that-you-explain-me-how-we-solve-the-trigonometric-inequality-with-tangente-we-can-take-for-example-tan2x-3-i-can-solve-this-type-of-equality-but-not-the-inequality-Pleas

Tinku Tara June 3, 2023 Trigonometry 0 Comments

Question Number 77472 by mathocean1 last updated on 06/Jan/20 $Hello sirs \dots$ $i want that you explain me how$ $we solve the trigonometric$ $inequality with tangente .$ $we can take for example \tan 2 x ⩾ \sqrt{3}$ $i can solve this type of equality$ $but not the inequality! Please$ $$\mathrm{i}\:\mathrm{need}\:\mathrm{your}\:\mathrm{help}…\:\mathrm{Even}\:\mathrm{the}\:\mathrm{steps} \…

Question-143003

Tinku Tara June 3, 2023 Trigonometry 0 Comments

Question Number 143003 by bramlexs22 last updated on 08/Jun/21 Answered by EDWIN88 last updated on 08/Jun/21 $(1) Since Δ ACE and Δ ACB share the same$ $altitude, and AE = \frac{1}{3} AB, the area of Δ ACE =$ $\frac{1}{3} the area of Δ ACB .$ $By Heron formula$ $$\:\:\:\frac{\mathrm{1}}{\mathrm{3}}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\Delta\mathrm{ACB}\:=\:\frac{\mathrm{1}}{\mathrm{3}}\sqrt{\frac{\mathrm{15}}{\mathrm{2}}\left(\frac{\mathrm{7}}{\mathrm{2}}\right)\left(\frac{\mathrm{5}}{\mathrm{2}}\right)\left(\frac{\mathrm{3}}{\mathrm{2}}\right)}\:=\frac{\mathrm{5}\sqrt{\mathrm{7}}}{\mathrm{4}}…

Calculate-cos-7-cos-4-7-cos-5-7-

Tinku Tara June 3, 2023 Trigonometry 0 Comments

Question Number 11900 by @ANTARES_VY last updated on 04/Apr/17 $Calculate .$ $\cos \frac{π}{7} \times \cos \frac{4 π}{7} \times \cos \frac{5 π}{7} .$ Answered by ajfour last updated on 04/Apr/17 $= \cos \frac{π}{7} \cos \frac{4 π}{7} [- \cos (π - \frac{5 π}{7})]$ $$=\:−\mathrm{cos}\:\frac{\pi}{\mathrm{7}}\mathrm{cos}\:\frac{\mathrm{4}\pi}{\mathrm{7}}\mathrm{cos}\:\frac{\mathrm{2}\pi}{\mathrm{7}} \…

cot-cosec-k-then-find-cosec-cot-and-also-find-cot-

Tinku Tara June 3, 2023 Trigonometry 0 Comments

Question Number 11844 by minakshidahaval0202@gmail.co. last updated on 02/Apr/17 $\cot α + cosec α = k t h e n f i n d cosec α - c o t α a n d a l s o f i n d c o t α$ Answered by sma3l2996 last updated on 02/Apr/17 $w e h a v e$ $(i) : c o t α + c o s e c α = \frac{c o s α}{s i n α} + \frac{1}{s i n α} = k$ $$=\frac{{cos}\alpha+\mathrm{1}}{{sin}\alpha}=\frac{\left({cos}\alpha+\mathrm{1}\right)\left({cos}\alpha−\mathrm{1}\right)}{{sin}\alpha\left({cos}\alpha−\mathrm{1}\right)}=\frac{−{sin}^{\mathrm{2}} \alpha}{{sin}\alpha\left({cos}\alpha−\mathrm{1}\right)}…

Simplify-sin-6-

Tinku Tara June 3, 2023 Trigonometry 0 Comments

Question Number 11751 by tawa last updated on 31/Mar/17 $Simplify : \sin (6 θ)$ Answered by mrW1 last updated on 31/Mar/17 $\sin (6 θ) = \sin (4 θ + 2 θ) = \sin (4 θ) \cos (2 θ) + \sin (2 θ) \cos (4 θ)$ $$=\mathrm{2sin}\:\left(\mathrm{2}\theta\right)\mathrm{cos}^{\mathrm{2}} \:\left(\mathrm{2}\theta\right)+\mathrm{sin}\:\left(\mathrm{2}\theta\right)\left[\mathrm{1}−\mathrm{2sin}^{\mathrm{2}} \:\left(\mathrm{2}\theta\right)\right] \…

If-2cos-5pi-4-3x-cos-pi-4-3x-0-and-sin-2x-2y-cos-y-where-pi-4-x-pi-2-and-pi-4-y-pi-2-find-the-value-of-sin-2x-y-cos-2x-y-cos-2x-y-sin-2x-y-

Tinku Tara June 3, 2023 Trigonometry 0 Comments

Question Number 142794 by EDWIN88 last updated on 05/Jun/21 $If 2 \cos (\frac{5 π}{4} + 3 x) \cos (\frac{π}{4} + 3 x) = 0 and$ $\sin (2 x - 2 y) = \cos y where \frac{π}{4} ⩽ x ⩽ \frac{π}{2} and$ $\frac{π}{4} ⩽ y ⩽ \frac{π}{2} . find the value of {\begin{cases} \sin (2 x + y) \\ \cos (2 x + y) \\ \cos (2 x - y) \\ \sin (2 x - y) \end{cases}$ Answered by Rasheed.Sindhi last updated on 05/Jun/21 $$\mathrm{2cos}\:\left(\frac{\mathrm{5}\pi}{\mathrm{4}}+\mathrm{3x}\right)\mathrm{cos}\:\left(\frac{\pi}{\mathrm{4}}+\mathrm{3x}\right)=\mathrm{0} \…

what-is-solution-in-R-sin-x-x-2-x-2-4x-5-0-

Tinku Tara June 3, 2023 Trigonometry 0 Comments

Question Number 77218 by john santu last updated on 04/Jan/20 $w h a t i s s o l u t i o n i n R$ $\frac{\sin (x) - ∣ x + 2 ∣}{x^{2} - 4 x - 5} ⩾ 0 ?$ Answered by MJS last updated on 04/Jan/20 $$\mathrm{sin}\:{x}\:−\mid{x}+\mathrm{2}\mid\geqslant\mathrm{0}\wedge\left({x}^{\mathrm{2}} −\mathrm{4}{x}−\mathrm{5}\right)>\mathrm{0}…

Category: Trigonometry