Question Number 75504 by mathocean1 last updated on 12/Dec/19 $$\mathrm{please}\:\mathrm{sirs}\:\mathrm{i}\:\mathrm{would}\:\mathrm{like}\:\mathrm{that}\:\mathrm{you}\:\mathrm{help}\:\mathrm{me}\:\mathrm{to} \\ $$$$\mathrm{show}\:\mathrm{this}: \\ $$$$\mathrm{sin}\left(\frac{\pi}{\mathrm{3}}+\mathrm{x}\right)\mathrm{sin}\left(\frac{\pi}{\mathrm{3}\:}−\mathrm{x}\right)=\frac{\mathrm{3}}{\mathrm{4}}−\mathrm{sin}^{\mathrm{2}} \mathrm{x} \\ $$ Answered by som(math1967) last updated on 12/Dec/19 $${sin}\left(\frac{\pi}{\mathrm{3}}\:+{x}\right){sin}\left(\frac{\pi}{\mathrm{3}}−{x}\right)…
Question Number 75502 by mathocean1 last updated on 12/Dec/19 $$\left.\mathrm{S}\left.\mathrm{olve}\:\mathrm{it}\:\mathrm{in}\:\right]−\pi;\pi\right] \\ $$$$\mathrm{sin}\left(\mathrm{2x}\right)=\mathrm{cos}\left(\mathrm{x}\right) \\ $$ Commented by mathmax by abdo last updated on 12/Dec/19 $${sin}\left(\mathrm{2}{x}\right)={cosx}\:\Leftrightarrow\:{sin}\left(\mathrm{2}{x}\right)={sin}\left(\frac{\pi}{\mathrm{2}}−{x}\right)\:\Leftrightarrow\mathrm{2}{x}=\frac{\pi}{\mathrm{2}}−{x}+\mathrm{2}{k}\pi\:{or} \\…
Question Number 9941 by Tawakalitu ayo mi last updated on 17/Jan/17 $$\mathrm{Prove}\:\mathrm{that}. \\ $$$$\mathrm{tan}^{−\mathrm{1}} \left[\frac{\mathrm{p}}{\mathrm{p}\:+\:\mathrm{2q}}\right]\:+\:\mathrm{tan}^{−\mathrm{1}} \left[\frac{\mathrm{q}}{\mathrm{p}\:+\:\mathrm{q}}\right]\:=\:\frac{\pi}{\mathrm{4}} \\ $$ Answered by mrW1 last updated on 17/Jan/17…
Question Number 9928 by Tawakalitu ayo mi last updated on 16/Jan/17 Commented by RasheedSoomro last updated on 16/Jan/17 $$\mathrm{Picture}\:\mathrm{not}\:\mathrm{visible}. \\ $$ Terms of Service Privacy…
Question Number 9921 by Tawakalitu ayo mi last updated on 15/Jan/17 Answered by mrW1 last updated on 16/Jan/17 $$\mathrm{2}{x}=\mathrm{180}−\mathrm{50}−\mathrm{70}=\mathrm{60} \\ $$$$\Rightarrow{x}=\mathrm{30} \\ $$$${y}=\mathrm{180}−\mathrm{50}−{x}=\mathrm{100} \\ $$$${z}=\mathrm{180}−{x}−\left(\mathrm{70}+\mathrm{50}\right)=\mathrm{180}−\mathrm{30}−\mathrm{120}=\mathrm{30}…
Question Number 9920 by Tawakalitu ayo mi last updated on 15/Jan/17 Answered by mrW1 last updated on 16/Jan/17 $${x}=\mathrm{360}−\left(\mathrm{360}−\mathrm{290}\right)−\left(\mathrm{360}−\mathrm{320}\right) \\ $$$$=\mathrm{360}−\mathrm{70}−\mathrm{40} \\ $$$$=\mathrm{250} \\ $$$${or}…
Question Number 75453 by Master last updated on 11/Dec/19 Commented by MJS last updated on 11/Dec/19 $$\mathrm{impossible}\:\mathrm{to}\:\mathrm{solve} \\ $$ Commented by Master last updated on…
Question Number 9914 by Tawakalitu ayo mi last updated on 15/Jan/17 Answered by mrW1 last updated on 15/Jan/17 $$\frac{{QA}}{{PQ}}=\frac{{RA}}{{PR}} \\ $$$$\frac{{QA}}{\mathrm{15}}=\frac{{RA}}{\mathrm{9}} \\ $$$${QA}=\frac{\mathrm{15}}{\mathrm{9}}{RA}=\frac{\mathrm{5}}{\mathrm{3}}{RA}=\frac{\mathrm{5}}{\mathrm{3}}\left({QR}−{QA}\right) \\ $$$$\mathrm{3}{QA}=\mathrm{5}{QR}−\mathrm{5}{QA}…
Question Number 140907 by bramlexs22 last updated on 14/May/21 $$\:\sqrt{\mathrm{sin}\:\mathrm{x}}\:\mathrm{cos}\:\mathrm{x}\:−\sqrt{\mathrm{sin}\:^{\mathrm{5}} \mathrm{x}}\:\mathrm{cos}\:\mathrm{x}\:=\:\mathrm{cos}\:^{\mathrm{3}} \mathrm{x}\:\sqrt{\mathrm{sin}\:\mathrm{x}} \\ $$ Answered by john_santu last updated on 14/May/21 $$\sqrt{\mathrm{sin}\:{x}}\:\geqslant\:\mathrm{0} \\ $$$$\Rightarrow\sqrt{\mathrm{sin}\:{x}}\:\mathrm{cos}\:{x}\left(\mathrm{1}−\mathrm{sin}\:^{\mathrm{4}} \:{x}−\mathrm{cos}\:^{\mathrm{2}}…
Question Number 9831 by tawakalitu last updated on 06/Jan/17 Answered by ridwan balatif last updated on 06/Jan/17 $$\mathrm{Area}_{\mathrm{AC}} =\mathrm{Area}_{\mathrm{ABC}} =\mathrm{Area}_{\mathrm{AB}} \\ $$$$\mathrm{Area}_{\mathrm{AC}} +\mathrm{Area}_{\mathrm{ABC}} +\mathrm{Area}_{\mathrm{AB}} =\mathrm{Area}\:\mathrm{of}\:\mathrm{circle}…