Category: Trigonometry

Question Number 75502 by mathocean1 last updated on 12/Dec/19 $$\mathrm{S}\mathrm{olve}\mathrm{it}\mathrm{in}]-\pi ;\pi ]$$$$\sin \left(2\mathrm{x}\right)=\cos \left(\mathrm{x}\right)$$ Commented by mathmax by abdo last updated on 12/Dec/19 $${sin}\left(\mathrm{2}{x}\right)={cosx}\:\Leftrightarrow\:{sin}\left(\mathrm{2}{x}\right)={sin}\left(\frac{\pi}{\mathrm{2}}−{x}\right)\:\Leftrightarrow\mathrm{2}{x}=\frac{\pi}{\mathrm{2}}−{x}+\mathrm{2}{k}\pi\:{or} \…

Question Number 9928 by Tawakalitu ayo mi last updated on 16/Jan/17 Commented by RasheedSoomro last updated on 16/Jan/17 $$\mathrm{Picture}\mathrm{not}\mathrm{visible}.$$ Terms of Service Privacy…

Question Number 9920 by Tawakalitu ayo mi last updated on 15/Jan/17 Answered by mrW1 last updated on 16/Jan/17 $$x=360-(360-290)-(360-320)$$$$=360-70-40$$$$=250$$$${or}…

Question Number 9914 by Tawakalitu ayo mi last updated on 15/Jan/17 Answered by mrW1 last updated on 15/Jan/17 $$\frac{QA}{PQ}=\frac{RA}{PR}$$$$\frac{QA}{15}=\frac{RA}{9}$$$$QA=\frac{15}{9}RA=\frac{5}{3}RA=\frac{5}{3}(QR-QA)$$$$\mathrm{3}{QA}=\mathrm{5}{QR}−\mathrm{5}{QA}…

Question Number 9831 by tawakalitu last updated on 06/Jan/17 Answered by ridwan balatif last updated on 06/Jan/17 $${\mathrm{Area}}_{\mathrm{AC}}={\mathrm{Area}}_{\mathrm{ABC}}={\mathrm{Area}}_{\mathrm{AB}}$$$$\mathrm{Area}_{\mathrm{AC}} +\mathrm{Area}_{\mathrm{ABC}} +\mathrm{Area}_{\mathrm{AB}} =\mathrm{Area}\:\mathrm{of}\:\mathrm{circle}…